Pass variable from controller to view - php

Question

In my controller, I can get the organization name but when I pass it to the view
there's an error. It said invalid argument supplied for foreach( ):
.
This is my codes.
Controller
public function index()
{
$user_id = $this->session->userdata('user_id');
$data['title'] = "User";
$getID['orgID'] = $this->userModel->getOrganizationID($user_id); // used my session user_id to
foreach ($getID['orgID'] as $orgID)
{
$org_id = $orgID->org_id;
$getName['myOrganization'] = $this->userModel->myOrganization($org_id);
foreach($getName['myOrganization'] as $orgName)
{
$name = $orgName->org_name;
$data['name'] = $name;
}
}
$this->load->view('xxxx/xxxx/xxxx',$data);
Model
public function getOrganizationID($user_id)
{
$this->db->select('org_id');
$this->db->from('organization_members');
$this->db->where('user_id', $user_id);
$query = $this->db->get();
return $query->result();
}
public function myOrganization($org_id)
{
$this->db->select('org_name');
$this->db->from('tblorganization');
$this->db->where('org_id', $org_id);
$query = $this->db->get();
return $query->result();
}
My output
First array is my result of $getID['orgID'] = $this->userModel->getOrganizationID($user_id); which I used my user_id session to get all the org_id of the user then
Second array is my result of $getName['myOrganization'] = $this->userModel->myOrganization($org_id); which I used my org_id(from my previous method) to get all the org_name of the user.

Answer 1

Is there going to be more then one result? Because if its only one result then you can use $query->row(); and eliminate the foreach completely.
Always check to make sure your database method worked AND that you actually got a returned value whenever you are making any database call. So i'll let you add the if condition in the database method but in short it should return FALSE if nothing came back. So thats the database method heres one way of doing it in your controller. Note this: $getID['orgID'] is very awkward. You are getting results back from the members table so call it members.
// check for the negative first - if no members came back
if( ! $members = $this->userModel->getOrganizationID($user_id) )
{
// if no results back leave this method
// pass the user id so you can echo it out in the error page
$this->showNoResultsFor($user_id) ;
}
else{
foreach ($members as $member)
{
$org_id = $member->org_id;
// etc etc etc

Answer 2

I'm not a codeigniter expert but looking at your code, I am wondering why you are setting:
$getID['orgID'] = $this->userModel->getOrganizationID($user_id);
First, you are setting an array $getID['orgID'] rather than just using something like $memberships = ...; I'm not sure why you are casting an array.
Secondly, you seem to be referencing a model class without instantiating it:
$this->userModel->getOrganizationID($user_id);
Perhaps codeigniter does some magic? $this refers to this instance and from the code you show, your model is likely in a separate class/file so I am unclear how $this->userModel is referenced in your method, unless you are instantiating it in your Controller's constructor?
From what I see it looks like you are getting the error because you are not supplying a valid object/array to your foreach. Perhaps start by testing you are actually getting a valid return from $this->userModel->getOrganizationID($user_id).