MySQL find multiple records by two columns - php

Question

Let's say I have an array as follows (ID => Type):
$contentIndexes = [
32 => 'news',
40 => 'blog',
68 => 'blog',
109 => 'document',
124 => 'news'
]
And the following database table:
CREATE TABLE `ContentIndex` (
`ID` INT(11) NOT NULL AUTO_INCREMENT,
`ItemID` INT(11) NOT NULL,
`ItemType` VARCHAR(50) NOT NULL COLLATE 'utf8_unicode_ci',
//...
);
How would I retrieve each ContentIndex based on the combination of the 'ItemID' and 'ItemType' columns (preferably with just one query).
Using WHERE IN is not an option since it wouldn't take the combination in consideration:
ContentIndexQuery::create()
->filterByItemID(array_keys($contentIndexes))
->filterByItemType($contentIndexes)
->find();
Any ideas?

Answer 1

I don't know the Propel syntax, but the basic SQL syntax would be with OR.
WHERE ((ItemID = 32 AND ItemType = 'news')
OR
(ItemID = 40 AND ItemType = 'blog')
OR
(ItemID = 68 AND ItemType = 'blog')
OR
(ItemID = 109 AND ItemType = 'document')
OR
(ItemID = 124 AND ItemType = 'news')
)

Answer 2

For any Propel users encountering this problem in the future, this is what I came up with to create a query as Barmar stated:
$items = ContentIndexQuery::create();
$i = 0;
foreach ($contentIndexes as $id = > $type) {
if ($i > 0) $items->_or();
$items->condition('cond1'.$i, ContentIndexTableMap::COL_ITEM_ID . ' = ?', $id)
->condition('cond2'.$i, ContentIndexTableMap::COL_ITEM_TYPE . ' = ?', $type)
->where(['cond1'.$i, 'cond2'.$i], 'AND');
$i += 1;
}
$items = $items->find()->getData();