edit_form.php in custom block of totara/moodle - php

I have created a custom block "blockpre" in totara which will show the results of assignments.In edit_form.php of my block blockpre i added some extra elements in mform for my block.
in edit_form.php i have created a class "block_blockpre_edit_form" which extends "block_edit_form" (standard class). I have added standard elements in mform and also 1 extra element.
The problem is that i'm unable to access the value of standard as well as extra element added.
i have tried using $mform->get_data on view page of my block but its not working on any of the block pages.
Is there some standard way to access the value of mform element ?
edit_form.php
<?php
class block_blockpre_edit_form extends block_edit_form {
protected function specific_definition($mform) {
// Section header title according to language file.
$mform->addElement('header', 'configheader', get_string('blocksettings', 'block'));
// A sample string variable with a default value.
$mform->addElement('text', 'config_text', get_string('blockstring', 'block_blockpre'));
$mform->setDefault('config_text', 'default value');
$mform->setType('config_text', PARAM_MULTILANG);
$mform->addElement('header', 'configheader', get_string('blocksettings1', 'block_blockpre'));
global $CFG, $OUTPUT,$DB,$USER;
$courseid = $_REQUEST['id'];
$sel="select id,name from {assign} where course=".$courseid;
$sel1= $DB->get_records_sql($sel);
foreach($sel1 as $s)
{mform element
$dis=$s->id;
$namem=$dis;
$mform->addElement('advcheckbox','assignid',$s->name,null, array('name' => $namem),$namem); //extra element
}
}
}
?>
Thanks for help in advance.

You can display form data with $mform->render();
Or use the data internally with $mform->set_data();

Related

Joomla custom fields inside template

I would like to customize my template for Joomla 3.7 so that I can use the new feature of Joomla 3.7, Custom fields (com_fields), and display and format them via CSS in my template where I need to display them.
Can someone suggest me the PHP code I should use in the template to display field(s), some example please.
Thanks in advance.
For everyone getting late to the party. In case you want to use your custom form fields in a Module-Override (which really are the only way to modify j!-templates, so google 'joomla template override') you can use this handy snippet:
<?php
JLoader::register('FieldsHelper', JPATH_ADMINISTRATOR . '/components/com_fields/helpers/fields.php');
$jcFields = FieldsHelper::getFields('com_content.article', $item, true);
$itemCustomFields = array();
foreach($jcFields as $field) {
$itemCustomFields[$field->name] = $field->rawvalue;
}
?>
Now you cna use your customfields like so: itemCustomFields['customFieldName1']
Haven't tested in article overrides. May soon, if so, this will get updated.
certainly not the right way to do it but I had the same need and I found a work around based on https://www.giudansky.com/news/12-coding/146-joomla-custom-fields
Copie default.php from /components/com_content/views/article/tmpl/default.php to
templates/YOUR_THEME/html/com_content/article/default.php
Add following code line 25 :
$myCustomFields = array();
foreach($this->item->jcfields as $field) {
$myCustomFields[$field->name] = $field->value;
}
$GLOBALS['myCustomFields'] = $myCustomFields;
Typically you put on a global var the content of fields attached to your article.
On your template page you can know retrieved value of your field.
just print_r($GLOBALS['myCustomFields']); to view the content of your array.
That will do the trick waiting for a better answer..
This is absolutely the wrong way to do this I think but I was tearing my hair out so i came up with this quick db query to return custom field values in the template. surely this violates some kind of joomla protocol?
obviously this assumes you can get $articleid into your template already which is the Current ID of your article.
I too am waiting on a better solution but hope this helps
$db =& JFactory::getDBO();
$sql = "select * from #__fields_values where `item_id` = $articleid";
$db->setQuery($sql);
$fieldslist = $db->loadObjectList();
echo $fieldslist[0]->value;
echo $fieldslist[1]->value;
echo $fieldslist[your field ID here]->value;
I found it was easiest to follow how com_fields does it in its rendering code. In Joomla!3.7+, you'll find it in [joomla_root]/components/com_fields/layouts/fields/render.php .
Here are the main parts you need to reproduce the formatting that Joomla has:
JLoader::register('FieldsHelper', JPATH_ADMINISTRATOR . '/components/com_fields/helpers/fields.php');
<dl class="fields-container">
<?php foreach ($this->item->jcfields as $field) : ?>
<?php // If the value is empty do nothing ?>
<?php if (!isset($field->value) || $field->value == '') : ?>
<?php continue; ?>
<?php endif; ?>
<?php $class = $field->params->get('render_class'); ?>
<dd class="field-entry <?php echo $class; ?>">
<?php echo FieldsHelper::render($context, 'field.render', array('field' => $field)); ?>
</dd>
<?php endforeach; ?>
</dl>
This loops through all available tags for the component or article. The nice thing about this method is it still applies the render classes you include with the fields.
Make sure to set Automatic Display to Do not automatically display on your fields; otherwise you will see them twice on your page view.
If you want to just target specific fields to show, you can use the name of the field to target it. (The label and value pair is underneath.) See the field Joomla docs for more info.
I implemented this small function to get specific custom field values:
function getCustomFieldValue($field_name, $article_id, $default_value = '') {
// Load custom field list
$fields = FieldsHelper::getFields('com_content.article', $article_id, true);
$field_ids = array_column($fields, 'id', 'name');
$model = JModelLegacy::getInstance('Field', 'FieldsModel', array('ignore_request' => true));
// Return the value if the field exists, otherwise the default
return array_key_exists($field_name, $field_ids)
? $model->getFieldValue($field_ids[$field_name] , $article_id)
: $default_value;
}
Usage:
$some_field_value = getCustomFieldValue('some-field-name', $some_article_id);
Optimization: I placed the function into a helper class, implemented the variables $fields, $field_ids and $model static and checked if they are already loaded to prevent redundant loading of the same data.

using if/else statement with str_replace to add variables via shortcode

I'm working with a custom shortcode that generates a custom paypal button & passes specific parameters to a paypal checkout form.
I'm using the str_replace function to pass attributes defined in the shortcode to the html form.
I'd like to set a default style class & default title if not defined as an attribute in the shortcode.
My php:
function paypal_button_func($attrs){
$class=$attrs['class']; //Added button style class variable
$title=$attrs['title']; //Added button title variable
if( isset( $atts['title'])) //add button title to the form html
{
return $html=str_replace('[title]',$title,$html);
}
//This sets the default title if not defined
else {
return $html=str_replace ('[title]','SIGN UP NOW',$html);
}
And this is my html
<input type="submit" class="[class]" value="[title]" /> <!-- updated class and value for addtl shortcode parameters -->
I was successful with using the following code to pass the shortcode attributes to the html, but the problem is that if the attributes aren't defined in the shortcode it outputs the [class] and [title] as values, which is not what i want to happen.
$html=str_replace('[title]',$title,$html); //add button title assigned to the form
$html=str_replace('[class]',$class,$html); //replaces class assigned to the form
simply make sure to initialize your replacements properly, i suggest using an if/else shorthand when creating your vars:
$class = isset($attrs['class']) ? $attrs['class'] : 'default-class-name'; //Added button style class variable
$title = isset($attrs['title']) ? $attrs['title'] : 'SIGN UP NOW'; //Added button title variable
this way your html will always get a replacement, either the attrs value or the defaults.
also i noticed you have a typo checking on isset($atts['title']) where you probably want $attrs and not $atts
good luck!

How to tell custom developed magento block to use a template?

This is the code in contollers
public function transactionsAction()
{
$ModelLayout = new Pteb_System_Model_Layout_Backend();
$ModelLayout->LoadLayout();
$Block = $ModelLayout->SetContentBlock( 'transactions-block', 'Pteb_System_Block_Cms' );
$Block->setTemplate('user/transactions/results.phtml');
$ModelLayout->ShowLayout();
}
/* this is the content to display on the page,
currently it displays without any template*/
$Block->setTemplate('user/transactions/results.phtml');
/* the template for the content above resides in the same folder as it is, with the name form.phtml. I replaced results.phtml with form.phtml in the above code but it displays the design only not the content.
Basically the form.phtml contains table structure with table heading while the results.phtml contains rows of contents.*/
How do I tell this results.phtml to use form.phtml as a template?
Can you try to go to this block:
Pteb_System_Block_Cms
and add the following setTemplate script:
public function __construct()
{
parent::__construct();
$this->setTemplate('abc/abc.phtml');
}

Multiple _form views on a single create view [Yii]

I'm trying to merge 3 models to create a fourth one. I have model1, model2 and model3 and I want to merge them into modelMaster. I've also created controllers for all of them. When I call modelMaster/create action, I render the modelMaster/create view which renders the modelMaster/_form view. Inside this _form view, I also want to render model1/_form, model2/_form and a CHtml::dropDownList(), wich takes datas from model3. However, this doesn't work. How can I combine these three different views into one another?
If you try to skip the form generate from the _form views and use unique model names, I think you can use this manual: single form with more models
So the generate of the form definition handles always the parent view and the _form's only the inputs
The other way to use single model in views, create a form model by extend CFormModel, and handle the data binding between this model and the wrapped submodels
If you want to nest several forms into one master form you have to adjust the form templates accordingly. All of your modelMaster/create, model1/_form, model2/_form-views create and render a new CActiveForm (and thus several <form> tags).
Since you cannot nest form-elements in html (how should html know which action to pass the data to) you have to avoid this by doing the following:
Extract the inputs of the form you want to nest into a new view, e.g. model1/_formInputs would look like
...
<?php echo $form->labelEx($model,'name'); ?>
<?php echo $form->textField($model,'name');
<?php echo $form->error($model,'name');
...
alter the model1/create and the other views and get a reference to the form created there, by assigning the return of $this->beginWidget to the variable $form (if not already done):
<?php $form = $this->beginWidget('CActiveForm', array(
'id'=>'foo',
)); ?>
replace the former input fields with
<?php $this->renderPartial('model1/_formInputs', array('form' => $form); ?>
Now, for example the old model1/create-view should work as expected
To get your multi-model-form working you just have to get the reference to the form created in modelMaster/create and use it to renderPartial all */_formInputs you require. Please also remember to include the models for the inputs into the renderPartial-call. So modelMaster/create would look something like:
<?php $form = $this->beginWidget('CActiveForm', array(
'id'=>'foo',
)); ?>
/* Master Inputs here */
// Rendering other models' inputs
<?php $this->renderPartial('model1/_formInputs', array('form' => $form, 'model' => $model1); ?>
<?php $this->renderPartial('model2/_formInputs', array('form' => $form, 'model' => $model2); ?>
/* Render Form Buttons here */
<?php $this->endWidget(); ?>
Submit with Ajax, in Yii it is easy to do and it will keep things easy to understand in the controllers, each controller will have a save and respond with json to confirm the save. There is already ajax validation.
/**
* Performs the AJAX validation.
* #param CModel the model to be validated
*/
protected function performAjaxValidation($model)
{
if(isset($_POST['ajax']) && $_POST['ajax']==='employee-form')
{
$valid = CActiveForm::validate($model);
if(strlen($valid) > 2) {
echo $valid;
Yii::app()->end();
}
}
}
As you can see I have modified it to return the error if there is one (validate returns [] if it is valid, I should probably check for that instead of strlen >2 ), otherwise let the script continue, in this case it will go to the save function.

how to ajaxify zend_pagination results (already working with partialoop) using jquery

in the controller i have :
$paginator = Zend_Paginator::factory($mdlPost->getPosts($this->moduleData->accordion, 'name ASC'));
if(isset($params['cities'])) {
$paginator->setCurrentPageNumber(intval($params['cities']));
}
$paginator->setItemCountPerPage(4);
$this->view->posts = $paginator;
in the view's i have some thing like this :
if ($this->posts != null) {?>
<div id="cities_accord" class="news">
<?php echo $this->partialLoop('partials/post-min.phtml', $this->posts); ?>
</div>
<?php echo $this->paginationControl($this->posts,
'Sliding',
'public/pagination_cont.phtml');
}
the partial/post-min.phtml
<?php
$color = array(1=>'spring',2=>'summer',3=>'autumn',4=>'winter');
?>
<div id='<?php echo $color[$this->partialCounter] ?>' class="accordion_post">
<?php
$link = Digitalus_Uri::get(false, false, array('openCity' =>
$this->id));//$color[$this->partialCounter]));
?>
<h1 class="accordion_post_title"><?php echo $this->title ?></h1>
<p><?php echo $this->teaser ?> <i>read more</i></p>
</div>
the pagination_cont.phtml taken from this link zend ( http://framework.zend.com/manual/en/zend.paginator.usage.html )
will show links that will pass params to the controller to fetch the corresponding whole page which is working alright for now
but i want to change this so that i will be able ajaxify the returned ( i.e. only a single paginated value rather than reloading the whole page ) results how can i do that using jquery and what should i change ..
** EDIT: it would be nice to have a fail-save ,if possible, for browsers(users) that disabled javascript to see the same thing by reloading the page (i.e. keeping the current status for if(javascript_not_enabled ))**
This is what I've done in the past.
First, setup the AjaxContext action helper to enable the html context on your controller action.
Add a .ajax.phtml view that just contains the section of markup that may be replaced via AJAX as well as the pagination control links. You can probably just copy this out of your normal view. Replace that section in your normal view with something like
<div id="reloadable-content">
<?php echo $this->render('controller/action.ajax.phtml') ?>
</div>
This will ensure that your initial and any non-AJAX requests will still include the right content. The <div> id is purely for referencing the loadable block in JavaScript.
Also make sure you include your JS file (using headScript) in the normal view only.
Now, in your JS file, unobtrusively add the appropriate event binding to the paginator links. As you'll be replacing the pagination control section in order to reflect the correct current page and other links, it's probably best to do this using the jQuery live binding. I'm also assuming you'll wrap the pagination control with some kind of identifiable element (<div class="pagination-control"> for example)
$('.pagination-control').find('a').live('click', function(e) {
var link = $(this);
$('#reloadable-content').load(link.attr('href'), { format: 'html' });
return false;
});
Keep in mind that in using this method, you will lose the ability to navigate the paged requests using the normal back / forward browser buttons. You will also lose the ability to bookmark pages directly (though you could always provide a permanent link to the current page as part of the AJAX loaded content).
You can use something like the jQuery history plugin if you're really concerned but that will require more client-side work.
Another caveat is that the above will only work with pagination links. If you want to use a form with dropdown page selection, you need to add another event handler for the submission.
GOT IT and big Thanks to #Phil Brown :
in the controller int() change the response type to json
class NewsController extends Zend_Controller_Action
{
public function init()
{
$contextSwitch = $this->_helper->getHelper('contextSwitch');
$contextSwitch->addActionContext('list', 'JSON')
->initContext();
}
// ...
}
public listAtcion() {
// .............
$paginator = Zend_Paginator::factory($mdlPost->getPosts($this->moduleData->accordion, 'name ASC'));
if(isset($params['cities'])) {
$paginator->setCurrentPageNumber(intval($params['cities']));
}
$paginator->setItemCountPerPage(4);
$post = array();
foreach($paginator as $post ) {
$post[] = $post;
}
$this->view->post = $paginator;
#TODO //add a check here for non-ajax requests (#improvment)
$this->view->posts = $paginator;
}
in one of the views (most probably in the pagination_cont.phtml) on the pagination controller add the ajax links
<?= $this->ajaxLink (
$this->url('cities'=>$this->page_num),array('id'=>'div_id','complete'=>'js_method(json_data)','method'=>post) ,array('format'=>'JSON'));
and add a JavaScript function of js_method(json_data) to modify the div with id = 'div_id' with a json data
function js_method(json_data) {
var content = parse.JSON(json_data);
$('#div_id').html('');
//fill it with the reposnse content some thing like $('#div_id').append(content);
}

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