How to use a variable in an array request in php - php

Question

Im using
$i = 0;
while ($i <= 6) {
print $game['stats']['item0'];
$i++;
}
I want the item0 to increment to item1 up to item6, so the last while should be
print $game['stats']['item6'];
I also tried: $game['stats']['item{$i}'] but it doesn't work.
Any Ideas for me?

Answer 1

If you need to do something a set number of times, a for loop is generally more concise than a while loop.
for ($i=0; $i < 6; $i++) {
print $game['stats']["item$i"];
}
It isn't a more correct way of doing it, it really just depends on your style, but I thought it was worth mentioning.

Answer 2

You can try this:
while ($i <= 6) {
$key = 'item'.$i;
print $game['stats'][$key];
$i++;
}

Answer 3

You should be good to go with this
$i = 0;
while ($i <= 6) {
print $game['stats']["item$i"];
$i++;
}
When a string is specified in double quotes or with heredoc, variables
are parsed within it.

Answer 4

Include the $i at the end of the string :
<?php
$i = 0;
while ($i <= 6) {
print $game['stats']['item' . $i]; //<============== , 'item0', 'item1', ...
$i++;
}
?>

Answer 5

You have to append $i after item. And you don't need to define new variable.
$i = 0;
while ($i <= 6) {
print $game['stats']['item'.$i];
$i++;
}

Answer 6

Here's an edited version of your code. It should work:
<?php
$i = 1;
$game = array("stats" =>
array("item1" => 1, "item2" => 2, "item3" => 3, "item4" => 4, "item5" => 5, "item6" => 6 ));
while ($i <= 6) {
$tmp = 'item'.$i;
print $game['stats'][$tmp];
$i++;
}