I have the following line of query in my stored procedure. The purpose of this stored procedure is if the website link is already in the table, it will update the existing one. If not it will record as new row from the other table' value.
CREATE DEFINER=`root`#`localhost` PROCEDURE `insert_diffmod_v2`(
IN para_diffmod LONGTEXT,
IN para_link LONGTEXT)
BEGIN
IF EXISTS (
SELECT website_link FROM diffmod WHERE website_link=para_link
)THEN
UPDATE diffmod
SET diffmod_content=para_diffmod
WHERE website_link= para_link;
ELSE
INSERT INTO diffmod(website_id,website_link)
SELECT id,link
FROM site_html
Where link=para_link;
UPDATE diffmod
SET diffmod_content= para_diffmod
where website_link = para_link;
END IF;
END
Let's say www.google.com is already recorded. When I call like:
CALL myDB.insert_diffmod_v2('test','www.google.com');
there is no problem and it do update the existing record.
But when I called the link which is not in the record (let's say Yahoo) like
CALL myDB.insert_diffmod_v2('test','www.yahoo.com');
it didn't insert as new record in the table. Can I know why ?
Insert in to on duplicate key update example
"$" are parameters and make website_id,website_link as unique
INSERT INTO diffmod SET
website_id = (SELECT id FROM site_html Where link=#para_link),
website_link= $para_link,
diffmod_content=$para_diffmod
ON DUPLICATE KEY UPDATE
diffmod_content=$para_diffmod
Related
Can anyone explain me what below code actually do, I have this on my mysqlDB.sql exported file
DROP TRIGGER IF EXISTS `alertupdateevent`;
DELIMITER $$
CREATE TRIGGER `alertupdateevent` AFTER INSERT ON `RECOG`
FOR EACH ROW BEGIN
INSERT INTO `mydb`.`ALERTUPDATES` (`FIRSTNAME`, `LASTNAME`, `CAMNAME`, `TIMESTAMP`, `RESERVE1`, `ALERTTYPE`, `IMGURL`) VALUES (NEW.FIRSTNAME, NEW.LASTNAME, NEW.DOB, NEW.TIMESTAMP, NEW.FACEID, 'RECOG' , NEW.FACEURL);
END
$$
DELIMITER ;
Currently I dealing a project which is not developed by me, and I am not well familiarized with mysql.
The problem I am facing is I have two table in DB like RECOG and ALERTUPDATES and I need to insert data to both of these table(same data), and I can see only one php which insert data to the table `RECOG'.
So my question does the above piece of code insert data automatically to table ALERTUPDATES when data insert on RECOG table by php.
Yes, you are correct.
Trigger are used to INSERT UPDATE on some TABLE based on action perform on some TABLE actions like insert, update or delete.
Refer MySQL triggers
Try this..
CREATE TRIGGER trigger_name
BEFORE INSERT
ON table_name FOR EACH ROW
BEGIN
-- variable declarations
-- trigger code
END;
Parameters or Arguments
trigger_name
The name of the trigger to create.
BEFORE INSERT
It indicates that the trigger will fire before the INSERT operation is executed.
table_name
The name of the table that the trigger is created on.
RESTRICTIONS
You can not create a BEFORE trigger on a view.
You can update the NEW values.
You can not update the OLD values.
Example:
DELIMITER //
CREATE TRIGGER contacts_before_insert
BEFORE INSERT
ON contacts FOR EACH ROW
BEGIN
DECLARE vUser varchar(50);
-- Find username of person performing INSERT into table
SELECT USER() INTO vUser;
-- Update create_date field to current system date
SET NEW.created_date = SYSDATE();
-- Update created_by field to the username of the person performing the INSERT
SET NEW.created_by = vUser;
END; //
DELIMITER ;
Ref:http://www.techonthenet.com/mysql/triggers/before_insert.php
IDEA:
Having a table of item, user, assign now if I assign one item to user which the record will be save on table of assign,
table_item:
ID------INT
NAME----TEXT
COUNT---INT
table_user:
ID-------INT
NAME-----TEXT
table_assing:
ID------INT
USER----INT (user id)
ITEM----INT (item_id)
COUNT---INT (this is for subtractions from the column of COUNT table of item)
Here I want to set trigger on inserting to table (table_assing) the value of column COUNT should subtract from column of COUNT table of table_item
This is possible on PHP that I can set to query on once action but it will take lots of code if it's possible on MySQL that will be much better and fast and effective with accuracy
simple trigger after insert on table table_assign
UPDATE table_item
SET table_item.count = (table_item.count - NEW.table_assign.count)
WHERE table_item.id = table_assign.item
Something like this should work.
DELIMITER $$
USE database_name$$
CREATE TRIGGER trigger_name AFTER INSERT ON table_asign FOR EACH ROW
BEGIN
UPDATE table_item SET count=count+NEW.count WHERE id=NEW.id;
END;$$
The 'NEW.id' refers to the new row in the table 'table_asign'
This is actually a form to update the team members who work for a specific client, When i deselect a member then it's status turns to 0.
I have a table with all unique records. table consists of four columns -
first column is `id` which is unique and auto_incremented.
second column is `client_id`.
third column is `member_id`. (these second and third columns together make the primary key.)
fourth column is `current` which shows the status (default is 1.).
Now i have a form which sends the values of client_id and member_id. But this forms also contains the values that are already in the table BUT NOT ALL.
I need a query which
(i) `INSERT` the values that are not already in the table,
(ii) `UPDATE` the `current` column to value `0` which are in the table but not in the form values.
here is a screenshot of my form.
If (select count(*) from yourtable where client_id = and member_id = ) > 0 THEN
update yourtable set current = 0;
ELSE
insert into yourtable (client_id,member_id,current) values (value1,value2,value3)
First of all check if the value exists in the table or not, by using a SELECT query.
Then check if the result haven't save value so it will be inserted, else show an error .
This would be a great time to create a database stored procedure that flows something like...
select user
if exists update row
else insert new row
stored procedures don't improve transaction times, but they are a great addition to any piece of software.
If this doesn't solve your problem then a database trigger might help out.
Doing a little research on this matter might open up some great ideas!
Add below logic in your SP
If (select count(*) from yourtable where client_id = <value> and member_id = <value>) > 0 THEN
update yourtable set current = 0;
ELSE
insert into yourtable (client_id,member_id,current) values (value1,value2,value3)
if you want simple solution then follow this:
*) use select with each entry in selected team.
if select returns a row
then use update sql
else
use insert sql.
In your case member_id & client_id together makes the primary key.
So , you can use sql ON DUPLICATE KEY UPDATE Syntax.
Example:
$sql="INSERT INTO table_name SET
client_id='".$clientId."',
member_id='".$member_id."',
current='".$current."'
ON DUPLICATE KEY
UPDATE
current = '".$current."'
";
In this case when member_id & client_id combination repeats , it will automatically executes update query for that particular row.
i have a contactnumber column in mysql database. In contactnumber column there are more than 20,000 entries. Now when i upload new numbers through .csv file, i dont want duplicate numbers in database.
How can i avoid duplicate numbers while inserting in database.
I initially implemented logic that checks each number in .csv file with each of the number in database.
this works but takes lot of time to upload .csv file containing 1000 numbers.
Pleae suggest how to minimize time required to upload .csv file while not uploading duplicate values.
Simply add a UNIQUE constraint to the contactnumber column:
ALTER TABLE `mytable` ADD UNIQUE (`contactnumber`);
From there you can use the IGNORE option to ignore the error you'd usually be shown when inserting a duplicate:
INSERT IGNORE INTO `mytable` VALUES ('0123456789');
Alternatively, you could use the ON DUPLICATE KEY UPDATE to do something with the dupe, as detailed in this question: MySQL - ignore insert error: duplicate entry
If your contactnumber should not be repeated then make it PRIMARY or at least a UNIQUE key. That way when a value is being inserted as a duplicate, insert will fail automatically and you won't have to check beforehand.
The way I would do it is to create a temporary table.
create table my_dateasyyyymmddhhiiss as select * from mytable where 1=0;
Do your inserts into that table.
and then query out the orphans on the between mytable and the temp table based on contactnumber
then run an inner join query between the two tables and fetch out the duplicate for your telecaller tracking.
finally drop the temporary table.
Thing that this does not address are duplicates within the supplied file (don't know if that would be an issue in this problem)
Hope this help
If you don't want to insert duplicate values in table and rather wants to keep that value in different table.
You can create trigger on table.
like this:
DELIMITER $$
CREATE TRIGGER unique_key BEFORE INSERT ON table1
FOR EACH ROW BEGIN
DECLARE c INT;
SELECT COUNT(*) INTO c FROM table1 WHERE itemid = NEW.itemid;
IF (c > 0) THEN
insert into table2 (column_name) values (NEW.itemid);
END IF;
END$$
DELIMITER ;
I would recommend this way
Alter the contactnumber column as UNIQUE KEY
Using phpmyadmin import the .csv file and check the option 'Do not abort on INSERT error' under Format-Specific Options before submitting
Hi i'm new to php and mysql.
I'm wondering how can i use PHP to check if a table in my mysql database contains a ROW which have the specific ID and if not add the data to the table .
For example,
Table structure:(Table name : record)
ID , DATA
i have ID=123 and DATA=hello stored in a variable in the php code , how can i use php sql query to find out whether the data exist by checking using its ID in the table , if not , INSERT the ID and DATA into the table.
I hope you understand.
p/s i have connected the php script to the database
Make the ID UNIQUE:
CREATE TABLE my_table( ID INT UNSIGNED UNIQUE...
then use INSERT IGNORE:
INSERT IGNORE INTO my_table( ID, DATA ) VALUES( some_id, some_data )
IF NOT EXISTS(SELECT 1 FROM structure WHERE ID = <yourid>)
INSERT INTO structure (ID, DATA) VALUES(<yourid>, <yourdata>)
Just replace INSERT with REPLACE.
http://dev.mysql.com/doc/refman/5.5/en/replace.html
Another option:
INSERT INTO record(id, `data`) SELECT 123, 'hello'
FROM new_table WHERE NOT EXISTS (SELECT id from record where id = 123 );
If your ID is unique key, then you can directly try to insert the row. If that ID is already in the table, the database would not let you insert it and will return error. Else you have to first run a SELECT statement to see if this ID exists in your table and if not insert it.
Also this thread will help you a lot I think How to 'insert if not exists' in MySQL?