Can't update Date field in MySql using PHP - php

Question

I have a DATE field in my table, and I'm trying to update it using the following code:
$query = mysqli_query($conn,$sql);
$todaydate = date("Y-m-d");
$sqlDate = date('Y-m-d', strtotime($todaydate));
$sql="UPDATE Library SET Loaned=1, LoanedDate=$sqlDate WHERE BookId=$bookId";
$query = mysqli_query($conn,$sql);
It updates the "Loaned" field fine, but always sets the Date field to "0000-00-00". Can anyone indicate what I'm doing wrong?

Answer 1

Youre missing ' quotes in your update query
Just use something like this
$sql="UPDATE Library SET Loaned=1, LoanedDate='$sqlDate' WHERE BookId='$bookId'";
$query = mysqli_query($conn,$sql);

Answer 2

You must have to add Quotes to the values... other wise the date may seem like an invalid integer to mysql. Here's how:
$query = mysqli_query($conn,$sql);
$todaydate = date("Y-m-d", time()); //<== DON'T FORGET THE 2ND ARGUMENT TO date(): TIME-STAMP. YOU MAY USE: time()
$sqlDate = date('Y-m-d', strtotime($todaydate));
$sql ="UPDATE Library SET Loaned=1, LoanedDate='{$sqlDate}' WHERE BookId='{$bookId}'";
$query = mysqli_query($conn,$sql);

Answer 3

Why don't you use only MySQL function to update date
Use this
$sql = "UPDATE Library SET Loaned = 1, LoanedDate = DATE(NOW())
WHERE BookId = '".$bookId."'";

Answer 4

Change your query with this code
$sql="UPDATE Library SET Loaned=1, LoanedDate= current_date() WHERE BookId='".$bookId."'";
Also check data structure in database.

Answer 5

This query is working fine:
$current_date = strtotime(date('Y-m-d H:i:s'));
$sql = "UPDATE user SET dt_added = '".$current_date."' WHERE id = '$id' ";

Answer 6

You're not concatenating the Date string properly in the SQL query.
Use ' and . operator to concatenate the string. Like this,
$sql="UPDATE Library SET Loaned=1, LoanedDate='".$sqlDate."' WHERE BookId='".$bookId."'";
Altough it's good practice to use Prepared statement to pass arguments in SQL query.
Learn more about PHP Prepared Statements

Answer 7

Looking closer, I would just do:
$sql="UPDATE Library SET Loaned=1, LoanedDate='".$todaydate."' WHERE BookId='".$bookId."'";
instead of
$sql="UPDATE Library SET Loaned=1, LoanedDate='".$sqlDate."' WHERE BookId=$bookId";