Here is the format of affiliate URL I have http://tracking.vcommission.com/aff_c?offer_id=2119&&url=http%3A%2F%2Fwww.netmeds.com%2F%3Fsource_attribution%3DVC-CPS-Emails%26utm_source%3DVC-CPS-Emails%26utm_medium%3DCPS-Emails%26utm_campaign%3DEmails
If you see it has 2 URLs:
first URL: is for vcommission.com and
Second URL: netmeds.com
I have CSV file with lot of rows. Each rows may have different second URL. I wanted to get second URL for each rows. First URL is also not static as for different CSV, this would also different.
How can I get second URL?
Some basic string parsing like this should give you an idea.
$url='http://tracking.vcommission.com/aff_c?offer_id=2119&&url=http%3A%2F%2Fwww.netmeds.com%2F%3Fsource_attribution%3DVC-CPS-Emails%26utm_source%3DVC-CPS-Emails%26utm_medium%3DCPS-Emails%26utm_campaign%3DEmails';
list($u,$q)=explode('url=',urldecode($url));
$o=(object)parse_url($q);
echo $o->host;
A good way to find the domain for a URL is with parse_url
Unfortunately due to the way your data is stored this is not really an option however you may be able to use some sort of regex to find contained web addresses in the query string
<?php
$url = "http://tracking.vcommission.com/aff_c?offer_id=2119&&url=http%3A%2F%2Fwww.netmeds.com%2F%3Fsource_attribution%3DVC-CPS-Emails%26utm_source%3DVC-CPS-Emails%26utm_medium%3DCPS-Emails%26utm_campaign%3DEmails";
$p = parse_url($url);
$pattern = "/www[^%]*/";
preg_match($pattern, $p['query'], $result);
var_dump($result);
You may need to adjust the regex pattern based on how the other data presents itself.
Related
I need to create a variable in PHP from a URL, which does not have a fully formed query string.
e.g. http://search.domain.com/domain2.com
In this example, the variable needs to be
$website='domain2.com'
Is there a way to convert the entered URL in address bar to my ?website= variable?
An example would be the whois.domaintools service, which allows you to query a whois record from their website using the following url format:
http://whois.domaintools.com/domain.com
This then displays info based on the url you specified.
Can i achieve this using a MOD_Rewrite in the .htaccess, or can i use some PHP function like http_build_query to achieve this? I'm going around in circles and surely missing something obvious!
You can use this code to get your array $urlpart
$link = $_SERVER['REQUEST_URI'];
$urlpart = explode('/',trim(parse_url($link, PHP_URL_PATH), '/'));
I have seen on most online newspaper websites that when i click on a headline link, e.g. two thieves caught red handed, it normally opens a url like this: www.example.co.uk/news/two-thieves-caught-red-handed.
How do I deal with this url in php code, so that I can only pick the last part in the url. e.g. two-thieves-caught-red-handed. After that I want to work with this string.
I know how to deal with GET parameters like "www.example.co.uk/news/headline=two thieves caught red handed".
But I do not want to do it that way. Could you show me another way.
You can use the combination of explode and end functions for that
for example:
<?php
$url = "www.example.co.uk/news/two-thieves-caught-red-handed";
$url = explode('/', $url);
$end = end($url);
echo "$end";
?>
The code will result
two-thieves-caught-red-handed
You have several options in php to get the current url. For a detailed overview look here.
One would be to use $_SERVER[REQUEST_URI] and the use a string manipulation function for extraction of the parts you need.
Maybe this thread will help you too.
For example, if there is a url like www.website.com/hello/richard, would it be possible to echo hello and 100 separately onto my page.
eg:
hello how are you today richard
You can get the data from $_SERVER['REQUEST_URI'] and then do whatever you like with it.
Yes it would be. Try this:
$myURL = $_SERVER['REQUEST_URI'];
$myTokens = explode('/', $myURL);
echo $myTokens[1] . "blah" . $myTokens[2];
This code gets the current URL into the myURL variable, then it calls a function called explode which turns it into an array based on the position of the '\' character. Then it echos out certain elements of that array. If you play around with output using echo you will soon see for yourself what is going on.
Sure that's possible. You can get URL as a string using $_SERVER['request_uri]. Then you might want to use explode function to firm array of strings where delimiter is /. Then you may parse it. Or you can do this via .htaccess using rewrite rule
It seems Google's URLs are structured differently these days. So it is harder to extract the referring keyword from them. Here is an example:
http://www.google.co.uk/search?q=jquery+post+output+46&ie=utf-8&oe=utf-8&aq=t&rls=org.mozilla:en-US:official&client=firefox-a#pq=jquery+post+output+46&hl=en&cp=30&gs_id=1v&xhr=t&q=jquery+post+output+php+not+running&pf=p&sclient=psy-ab&client=firefox-a&hs=8N5&rls=org.mozilla:en-US%3Aofficial&source=hp&pbx=1&oq=jquery+post+output+php+not+run&aq=0w&aqi=q-w1&aql=&gs_sm=&gs_upl=&bav=on.2,or.r_gc.r_pw.,cf.osb&fp=bdeb326aa44b07c5&biw=1280&bih=875
The search I performed was actually "jquery post output php not running", so the first 'q=' does not contain the full search. The second one does. I'd like to write a script that always extracts the last 'q=', but I'm not sure if Google's URL's always have the full search last. Anyone had any experience with this.
You can accomplish this using parse_url(), parse_str(), and urldecode(), where $str is the refer string:
$fragment = parse_url($str, PHP_URL_FRAGMENT);
parse_str($fragment, $arr);
$query = urldecode($arr['q']); // jquery post output php not running
How would I go about extracting just the base URl from a long string that was inputted into a form?
Example:
User inputs: http://stackoverflow.com/question/ask/asdfasneransea
Program needs just: http://stackoverflow.com and not /question/ask/asdfasneransea
What is the easist way to do this using PHP?
You can simply use parse_url()
$url = parse_url('http://example.com/foo/bar');
$host = $url['host']; // example.com
Use the parse_url function to get the separate parts of the URL, then reassemble the parts you are looking for.