Getting error while value is link - php

Question

I am getting the following error.
Message: Trying to get property of non-object
Table Structure:
name ='fb' value='https://www.facebook.com/mypage'
Model:
function get_fb_url(){
$query=$this->db->select('value');
$query=$this->db->from('preferences');
$query=$this->db->where('name','fb');
return $this->db->get()->row();
}
Controller:
$data['fb_url']=$this->Home_model->get_fb_url()->value;
View:
<li><img src="css/imgs/fb.png" /></li>
When i run my page it give me error
Message: Trying to get property of non-object
only when if value in the table is link like above, if its simple text then text properly show on page.
How Can i get rid off this error?

Answer 1

Instead of echo use return type
Change
echo $this->db->get()->row();
to
return $this->db->get()->row();
And add $ before variable name in view
<a href="<?php echo $fb_url;?>"
UPDATED
Change your model code to
function get_fb_url() {
$this->db->select('value');
$this->db->from('preferences');
$this->db->where('name', 'fb');
return $this->db->get()->row();
}

Answer 2

you must try like this:
function get_fb_url() {
$this->db->select('value');
$this->db->from('preferences');
$this->db->where('name', 'fb');
$query = $this->db->get();
return $query->row();
}
and in Controller:
$result = $this->Home_model->get_fb_url();
//try print $result, it must be an stdObject
$data['fb_url']=$result->value;
it is because in $data['fb_url']=$this->Home_model->get_fb_url()->value; / differentiate the link to the other function, that's why u r getting this error.

Answer 3

get_fb_url is returning object array not object. so you have to return value from method.
function get_fb_url()
{
$query=$this->db->select('value');
$query=$this->db->from('preferences');
$query=$this->db->where('name','fb');
return $this->db->get()->row()->value;
}
and than
$data['fb_url']=$this->Home_model->get_fb_url();

Answer 4

In Your model do this
public function get_fb_url() {
$this->db->select('value');
$this->db->from('preferences');
$this->db->where('name','fb');
$query = $this->db->get();
$row = $query->row();
return $row;
}
In Controller :
$data = array();
$result = $this->Home_model->get_fb_url();
$data['fb_url'] = $result->value;
$this->load->view('your_view',$data);
In View :
echo $fb_url;