How to Post values outside the form in php - php

Question

I need to post values outside the form in php , How to do it
Here is my sample code
<input type="hidden" id="test" name="test" />
<input type="hidden" id="testvalue" name="testvalue"/>
<?Php for($i=0;$i<5;$i++) { ?>
<form action='some_url'>
<input type="text" value="dynamic_value" name='testname'>
<select name="testselect">
<option value="<?php echo $dynamicvalue[$i]?>"><?php echo $dynamicvalue[$i]?></option>
</select>
<button class="btn btn-primary book_now" type="submit">BookNow</button>
</form>
<?php } ?>
i need to post all input values above the form also,since i cannot use that input field inside the loop, i want id to be unique so i cant use inside
any other option available to post all data

Answer 1

Use jQuery:
<script src="https://code.jquery.com/jquery-1.12.4.js"></script>
<script>
$(document).ready(function(){
$('form').submit(function(){
var test = $('#test').val();
var testvalue = $('#testvalue').val();
$(this).append('<input type="hidden" name="test" value="'+test+'">');
$(this).append('<input type="hidden" name="testvalue" value="'+testvalue+'">');
return true
});
});
</script>

Answer 2

You can add input fields into for-loop
<?php for($i=0;$i<5;$i++) { ?>
<form action='some_url'>
<input type="text" value="dynamic_value" name='testname'>
<select name="testselect">
<option value="<?php echo $dynamicvalue[$i]?>"><?php echo $dynamicvalue[$i]?></option>
</select>
<button class="btn btn-primary book_now" type="submit">BookNow</button>
<input type="hidden" name="test" />
<input type="hidden" name="testvalue"/>
</form>
<?php } ?>