I have to check expiry date of vehicle, I have taken interval of 1 day but its taking positive value so its not showing as EXPIRED rather its taking the positive value and showing as EXPIRES TOMORROW.
SELECT
vehicle_reg_num,
vehicle_type,
insurance_validity,
tax_validity,
fc_validity
FROM vms_vehicles_list
WHERE ((insurance_validity BETWEEN NOW() AND DATE_ADD(NOW(), INTERVAL 7 DAY)
OR insurance_validity BETWEEN DATE_ADD (NOW(),INTERVAL -7 DAY) AND NOW())
OR (tax_validity BETWEEN NOW() AND DATE_ADD(NOW(),INTERVAL 7 DAY)
OR tax_validity BETWEEN DATE_ADD(NOW(),INTERVAL -7 DAY) AND NOW())
OR (fc_validity BETWEEN NOW() AND DATE_ADD(NOW(), INTERVAL 7 DAY))
OR fc_validity BETWEEN DATE_ADD(NOW(),INTERVAL -7 DAY) AND NOW())
AND vehicle_delete_flag=0;
Your query should be like this.
SELECT
vehicle_reg_num,
vehicle_type,
insurance_validity,
tax_validity,
fc_validity
FROM vms_vehicles_list
WHERE ((insurance_validity BETWEEN NOW() AND SUBDATE(NOW(),7)
OR insurance_validity BETWEEN SUBDATE(NOW(),7) AND NOW())
OR (tax_validity BETWEEN NOW() AND SUBDATE(NOW(),7)
OR tax_validity BETWEEN SUBDATE(NOW(),7) AND NOW())
OR (fc_validity BETWEEN NOW() AND SUBDATE(NOW(),7)))
OR fc_validity BETWEEN SUBDATE(NOW(),7) AND NOW()) AND vehicle_delete_flag=0;
Related
I have a Table in Database which has records of Logins.
Table name: user_logins
ID | timestamp
1 2019.01.03 (Year, Month, Day)
2 2019.01.04
3 2019.01.05
4 2019.01.05
5 2019.01.07
6 2019.01.07
7 2019.01.09
I want to Show only Count of Records by this Week.
From Monday to Sunday (04-02-2019 ... 10-02-2019)
My PHP and SQL Code is:
$mo = mysql_num_rows(mysql_query('SELECT * FROM user_logins WHERE DAYNAME(DATE(timestamp)) = "monday" and timestamp >= DATE_SUB(CURDATE(), INTERVAL DAYOFWEEK(CURDATE())-0 DAY)'));
this should show the records of 04-02-2019
Here is my SQL Fiddle link:
SQL Fiddle
This:
DATE_ADD(CURDATE(), INTERVAL - WEEKDAY(CURDATE()) DAY)
gives this week's Monday.
So:
SELECT * FROM user_logins
WHERE
timestamp
BETWEEN DATE_ADD(CURDATE(), INTERVAL - WEEKDAY(CURDATE()) DAY)
and
NOW()
Try following query:
SELECT id FROM `user_logins`
WHERE timestamp >= curdate() - INTERVAL DAYOFWEEK(curdate())+6 DAY
AND timestamp < curdate() - INTERVAL DAYOFWEEK(curdate())-1 DAY
Demo
In my DB I have a column called dato_tid (Datatype = date)
right now I have 2 post
1 where the date is 2018-07-18
2 where the date is 2018-07-20
I need to select the post, that has less then 24 hours to go
SELECT * FROM `udflyt` WHERE dato_tid > DATE_ADD(CURDATE(), INTERVAL -1 day)
this line will select both posts
SELECT * FROM `udflyt` WHERE dato_tid > DATE_ADD(CURDATE(), INTERVAL -24 HOUR)
and so will this, I did try to change the > to < but the same.
SELECT * FROM `udflyt` WHERE dato_tid > (now() - interval 1 day )
this line will also get both posts
So what do I need to do, Thanks
Actually, 24 hours to go means you should ADD a day, not subtract a day.
SELECT *
FROM `udflyt`
WHERE dato_tid <= DATE_ADD(CURDATE(), INTERVAL +1 day);
Will provide only the record with date '2018-07-18' (which is what you are looking for, I believe.
The below shows the values used for comparison for both doing addition and subtraction.
SELECT *, DATE_ADD(CURDATE(), INTERVAL +1 day), DATE_ADD(CURDATE(), INTERVAL -1 day)
FROM `udflyt`
WHERE dato_tid <= DATE_ADD(CURDATE(), INTERVAL +1 day);
I want to get all the records from mysql database who have updated their records within 30 days from the current date for that i have used the below query but it is not working properly. $tda is the current date and $prevmonth is the date of exactly
30 days back from the current date. Please help. Thanks.
$da=date('d');
$tda=date('d-m-Y');
$prevmonth = date(''.$da.'-m-Y', strtotime('-1 months'));
$sql_q=executeQuery("select * from ".reg." where 'uid' !=".$_SESSION['uid']." AND Updatedate >= '$prevmonth' AND Updatedate <='$tda '");
You can do it in mysql as
`Updatedate` < DATE(NOW() - INTERVAL 30 DAY)
OR
`Updatedate` < DATE_SUB(CURDATE(), INTERVAL 30 DAY)
For Varchar
STR_TO_DATE(Updatedate, '%Y-%m-%d') < DATE_SUB(CURDATE(), INTERVAL 30 DAY)
UPDATE :
The query posted in the comment is wrong and should be
$sql_q=executeQuery("select * from registration
where
`uid` != ".$_SESSION['uid']."
AND STR_TO_DATE(Update_date, '%d-%m-%Y') < DATE_SUB(CURDATE(), INTERVAL 30 DAY)") ;
If you are looking for data within last 30 days then
$sql_q=executeQuery("select * from registration
where
`uid` != ".$_SESSION['uid']."
AND STR_TO_DATE(Update_date, '%d-%m-%Y') >= DATE_SUB(CURDATE(), INTERVAL 30 DAY)") ;
I like doing something like this: AND UpdateDate > NOW() - INTERVAL 30 DAY AND UpdateDate < NOW().
If your Updatedate column is a DATETIME column then you can do the following:
SELECT *
FROM table
WHERE uid <> ?
AND Updatedate >= DATE_SUB(NOW(), INTERVAL 1 MONTH)
AND Updatedate <= NOW();
Or:
SELECT *
FROM table
WHERE uid <> ?
AND Updatedate BETWEEN DATE_SUB(NOW(), INTERVAL 1 MONTH) AND NOW();
Or if it's a timestamp then this:
SELECT *
FROM table
WHERE uid <> ?
AND FROM_UNIXTIME(Updatedate) >= DATE_SUB(NOW(), INTERVAL 1 MONTH)
AND FROM_UNIXTIME(Updatedate) <= NOW();
I have a table with 3 columns: id, updated_at, click_sum.
Many rows have the exact same updated_at value which makes it hard to simply retrieve the data, order by updated_at and display the sums in a chart.
Since there are multiple sums for the same dates which screws the chart.
What I try to achieve is to get the following output:
update_at | click_sum
-----------+-----------
date1 | 100
date2 | 3
date3 | 235
date4 | 231
Optionally only those dates which are form the last month, week or day AND not simply the dates which are NOW() - 1 month.
The current query I build is very large and doesn't work that well.
It groups by dates (no duplicated dates appear) and SUM()s the clicks correctly but defining from when (last month, week, day) the dates are doesn't seem to work properly.
Query: ($interval stands for MONTH or DAY or SECOND or WEEK)
SELECT d.updated_at, SUM(d.clicks_sum) AS click_sum
FROM aggregated_clicks d
JOIN
(
SELECT c.id, MAX(StartOfChains.updated_at) AS ChainStartTime
FROM aggregated_clicks c
JOIN
(
SELECT DISTINCT a.updated_at
FROM aggregated_clicks a
LEFT JOIN aggregated_clicks b ON (b.updated_at >= a.updated_at - INTERVAL 1 DAY AND b.updated_at < a.updated_at)
WHERE b.updated_at IS NULL
) StartOfChains ON c.updated_at >= StartOfChains.updated_at
GROUP BY c.id
) GroupingQuery
ON d.id = GroupingQuery.id
WHERE GroupingQuery.ChainStartTime >= DATE_SUB(NOW(), INTERVAL 1 $interval)
GROUP BY GroupingQuery.ChainStartTime
ORDER BY GroupingQuery.ChainStartTime ASC
maybe I'm assuming too much about the nature of your question (and the table it refers to), but I think this can be done much more simply than the query you've shown.
figuring the latest completed month isn't very hard.
it starts with knowing the first date of this current month -- use this:
date_sub(curdate(), interval (extract(day from curdate())-1) day)
and to know the first day of that previous month, use this:
date_sub(date_sub(curdate(), interval extract(day from (curdate())-1) day), interval 1 month)
so if you want to get the sums for just the days in between -- i.e. the latest completed month, use this:
select updated_at, sum(click_sum) from aggregated_clicks
where updated_at >= date_sub(date_sub(curdate(), interval extract(day from (curdate())-1) day), interval 1 month)
and updated_at < date_sub(curdate(), interval (extract(day from curdate())-1) day)
group by updated_at;
figuring the lastest completed week is just as easy. this example will assume a Sunday-Saturday week.
because of the way the ODBC standard defines date numbers, it's easy to find the end (Saturday) of the previous week:
date_sub(curdate(), interval dayofweek(curdate()) day)
and the beginning (Sunday) of that week is six days before that:
date_sub(curdate(), interval (dayofweek(curdate())+6) day)
so if you want to get the sums for just the days in between -- i.e. the latest completed week, use this:
select updated_at, sum(click_sum) from aggregated_clicks
where updated_at >= date_sub(curdate(), interval (dayofweek(curdate())+6) day)
and updated_at <= date_sub(curdate(), interval dayofweek(curdate()) day)
group by updated_at;
and of course figuring based on the latest completed day is super easy.
to get the date of the previous day, use this:
date_sub(curdate(), interval 1 day)
so if you want the sums just for yesterday, use this:
select updated_at, sum(click_sum) from aggregated_clicks
where updated_at = date_sub(curdate(), interval 1 day)
group by updated_at;
NOTE: I've tested these queries using MySQL 5.1, YMMV.
----------
UPDATE: since the date column is a datetime, simply change all references to updated_at in my queries to date(updated_at) like so:
month case:
select date(updated_at), sum(click_sum) from aggregated_clicks
where date(updated_at) >= date_sub(date_sub(curdate(), interval extract(day from (curdate())-1) day), interval 1 month)
and date(updated_at) < date_sub(curdate(), interval (extract(day from curdate())-1) day)
group by date(updated_at);
week case:
select date(updated_at), sum(click_sum) from aggregated_clicks
where date(updated_at) >= date_sub(curdate(), interval (dayofweek(curdate())+6) day)
and date(updated_at) <= date_sub(curdate(), interval dayofweek(curdate()) day)
group by date(updated_at);
yesterday case:
select date(updated_at), sum(click_sum) from aggregated_clicks
where date(updated_at) = date_sub(curdate(), interval 1 day)
group by date(updated_at);
I'm not sure if I'm missing something really obvious, but I keep getting a syntax error on this query. Even if I AM missing something obvious, I'd like to know if there is a smarter way of getting what I'm after.
Basically, the query asks for any rows tied to a user with a start_date between Monday and Friday. That works great. But then I added a conditional query in case there are any rows for that Saturday or Sunday. Note that the conditional query is checking for ANY users with a Saturday or Sunday, not the user in the main query:
SELECT user_id,
DATE_FORMAT(DATE(shift_start),'%m/%d/%Y') date,
TIME_FORMAT(TIME(shift_start), '%h:%i %p') start,
TIME_FORMAT(TIME(shift_end), '%h:%i %p') end,
title
FROM shifts
WHERE user_id = '$user_id'
AND DATE(shift_start) BETWEEN
DATE_SUB(DATE(NOW()), INTERVAL WEEKDAY(NOW()) DAY) AND
DATE_ADD(DATE(NOW()), INTERVAL
(SELECT
IF(
COUNT(*) FROM shifts
WHERE DATE(shift_start) BETWEEN
DATE_ADD(DATE(NOW()), INTERVAL 5 - WEEKDAY(NOW()) DAY) AND
DATE_ADD(DATE(NOW()), INTERVAL 6 - WEEKDAY(NOW()) DAY),
6, 4)) - WEEKDAY(NOW()) DAY)
ORDER BY shift_start
I'm actually pretty proud of how it works before it messes up with the IF part, but again, if there is an obviously better way doing this, I'm all ears.
Oh, and when this gets ironed out, the "Now()" will be replaced with a date variable set up in the php script (passed to it via GET).
Awesome job, benlumey. Here's what worked:
SELECT user_id,
DATE_FORMAT(DATE(shift_start),'%m/%d/%Y') AS shift_start_date,
TIME_FORMAT(TIME(shift_start), '%h:%i %p') AS shift_start_time,
TIME_FORMAT(TIME(shift_end), '%h:%i %p') AS shift_end_time,
title
FROM shifts
WHERE user_id = '$user_id' AND
DATE(shift_start) BETWEEN
DATE_SUB(DATE(NOW()), INTERVAL WEEKDAY(NOW()) DAY)
AND
DATE_ADD
(
DATE(NOW()), INTERVAL
(
SELECT IF(COUNT(*),6,4)
FROM shifts
WHERE DATE(shift_start) BETWEEN
DATE_ADD(DATE(NOW()), INTERVAL 5 - WEEKDAY(NOW()) DAY)
AND
DATE_ADD(DATE(NOW()), INTERVAL 6 - WEEKDAY(NOW()) DAY)
) - WEEKDAY(NOW()) DAY
)
Try this subquery:
(SELECT
IF(COUNT(*) > 0, 6, 4)) - WEEKDAY(NOW()) DAY)
FROM shifts
WHERE DATE(shift_start) BETWEEN
DATE_ADD(DATE(NOW()), INTERVAL 5 - WEEKDAY(NOW()) DAY) AND
DATE_ADD(DATE(NOW()), INTERVAL 6 - WEEKDAY(NOW()) DAY)
Two things I've done
made it look like a normal query, the from and where can't go inside the if as far as i'm aware.
Put a condition in the if, don't think mysql will automatically take 0 as false and >0 as true.
this falls apart around here:
(SELECT
IF(
COUNT(*) FROM shifts
WHERE DATE(shift_start) BETWEEN
The count statement won't work.
What are you trying to do? You need a clear statement of what you are trying to accomplish here.
This is my swag at it:
(SELECT
IF(
(select COUNT(*) FROM shifts
WHERE DATE(shift_start) BETWEEN
DATE_ADD(DATE(NOW()), INTERVAL 5 - WEEKDAY(NOW()) DAY) AND
DATE_ADD(DATE(NOW()), INTERVAL 6 - WEEKDAY(NOW()) DAY))>0,6,4)
) - WEEKDAY(NOW()) DAY
But without knowing what you are trying to do I'm not sure.