PHP echo array value without looping - php

Question

I have the following code which works perfectly fine to give me the name of the customer with the ID of 10:
foreach($customer_list as $row) {
if ($row->CUSTOMER_ID == 10)
echo $row->NAME;
}
Is there a way I can do this more directly, without the foreach loop and if statement? I'd like to do something like:
echo $customer_list[CUSTOMER_ID][10]->NAME;
But I don't know the syntax or if it's even possible.

Answer 1

You could use array_filter It will return an array of customers whose ID is 10. We then select the first match (the only match probably) and access the NAME property.
$name = reset( array_filter(
$customer_list,function($c){return $c->CUSTOMER_ID === 10;}
))->NAME;
The cleaner approach is to factor it out, into a separate function:
$getCustName = function($list,$id){
return reset( array_filter(
$list,
function($c) use ($id) {return $c->CUSTOMER_ID === $id;}
))->NAME;
};
Then you can get the name easily with just one line:
$name = $getCustName($customer_list,10);

Answer 2

You can use php array_filter method.
Basically you need to pass a function which will check value of customer_Id and returns the element of the array.

Answer 3

you can add your code inside a function and then call that function when you need the name. I am assuming you have unique customer ID's.
function getCustName($customers,$id){
if(count($customers)>0){
foreach($customers as $row) {
if ($row->CUSTOMER_ID == $id)
return $row->NAME;
}
} else{
return false;
}
}
Now if you need to get customer name just call the function
echo getCustName($customer_list,10);