Can't unserialize jQuery data with PHP - php

Question

I am trying to implement a modal AJAX form. But when I press "Submit" I only receive empty body emails. I guess I have bugs in PHP code.
HTML:
<form class="form" method="POST">
<input type="text" name="name" placeholder="Name">
<input type="text" name="phone" placeholder="Phone">
<input type="submit" value="Submit" >
</form>
Jquery:
$(".form").submit(function() {
var this1= $(this);
var form_data = $(this).serialize();
if (is_empty(this1)){
$.ajax({
type: "POST",
url: "feedback.php",
data: form_data,
success: function (res) {
swal("Thank you", "very much", "success");
$('.black_layout').fadeOut(200);
$('.main_form_wrapper').fadeOut(200);
this1.trigger('reset');
}
});
}
return false;
});
PHP in feedback.php file:
parse_str($_POST['form_data'], $formdata);
$name = $formdata['name'];
$phone=$formdata['phone'];
$formcontent="From: $name \n Phone: $phone";
$recipient = "email#gmail.com";
$subject = "MAIL HEADER";
mail($recipient, $subject, $formcontent) or die("Error");
EDIT:I am also not getting a "Thank you" message for some reason.

Answer 1

You have an error during sending form data with ajax request. here is your code which is working fine :
JQuery :
$(".form").submit(function() {
var this1= $(this);
var form_data = $(this).serialize();
alert(form_data);
//if (is_empty(this1)){
$.ajax({
type: "POST",
url: "feedback.php",
data: {'form_data' : form_data },
success: function (res) { alert(res);
//swal("Thank you", "very much", "success");
$('.black_layout').fadeOut(200);
$('.main_form_wrapper').fadeOut(200);
this1.trigger('reset');
}
});
//}
return false;
});