Hi we are using ffmpeg for compressing the video through php script, now what i need is i want to get the video size of compressed image, but am getting an video path so kindly guide me how i need to over come this?
Below is the code what i used for compressing the video
original path
$path = "sample.mp4";
Command to compress
exec("ffmpeg -i sample.mp4 -vcodec h264 -acodec aac -strict -2 compressed_video.mp4);
The command what i used for getting video size
$compressed_video_information = exec("ls -h1 compressed_video.mp4);
echo $compressed_video_information;
I get just file path instaed of getting video file size, so someone help me how to overcome this issue?
-h option (ex: ls -lh) displays size in human readable form(KB/MB/GB etc..)
exec("ls -lh compressed_video.mp4",$out);// pass file path here
$size=explode(' ',$out[0]);
print_r($size[4]);
Use the PHP function filesize:
<?php
$filesize_in_bytes = filesize('compressed_video.mp4');
Related
hello all i am building a video hosting site and wanted to know what are the video formats which my php code should convert the user's video so that all the major browsers support the file.
by searching on internet i got to know that mp4,swf,avi,ogg are the formats but if i convert one video to all these formats then there will be 4 times the space of a single video and also there will be server load and time consuming process for the conversion.
so i was wondering if there is one or two formats which i should take with me so to reduce the server load and conversion time.
i am converting the video by this code (ffmpeg)
if (move_uploaded_file(#$_FILES['profileimage99']['tmp_name'], $uploadfile)) {
$base = basename($uploadfile, $safe_file['ext']);
$new_file = $base.'flv';
$new_image = $base.'jpg';
$new_image_path = $live_img.$new_image;
$new_flv = $live_dir.$new_file;
require 'vendor/autoload.php';
//ececute ffmpeg generate flv
exec('ffmpeg -i '.$uploadfile.' -f flv -s 768x432 '.$new_flv.'');
//execute ffmpeg and create thumb
exec('ffmpeg -i '.$uploadfile.' -f mjpeg -vframes 71 -s 768x432 -an '.$new_image_path.'');
also please tell me will it be good to use exec in php code ??
The most common web video formats are WebM, OGG, and MP4 with MP4 being supported in IE, Chrome, Safari, Opera, and FireFox.
Therefore, it would be prudent to stick with MP4.
So, i have kind of accepted this task on work but im really not sure if its possible.
We are going to build a website where users can upload videos from their computers and mobile phone browsers. The video files can be a large range of aspect ratios, width, height, codex and file formats.
I will have access to ffmpeg from php exec command on a web server.
Is it possible to use this to convert the user files to one file format that works on computers, android and iphone.
The requirements is that we can set a max width, to witch the video will be scaled, dynamically to match height.
Does anyone know is this can be done, and be done in a reasonable amount of time. Will do project on 2 days. And if so some pointers in the right direction would be nice.
Had the same problem but solved by using HandBrake the open source video transcoder
https://handbrake.fr/
If your target can only be one file format, then I would choose mp4 baseline. (However some browsers won't play it, which is why the html tag offers multiple source flags, which usually include webm and ogg video...)
Using ffprobe -show_streams $uploadedFile you can get the dimensions (and aspect ratio) of the file. Using math you can get the new dimensions based on your needs.
$newDim=$new_width.":".$new_height;
$output = shell_exec("/usr/bin/ffmpeg -i $uploadedFile -f mp4 \
-c:a libfdk_aac -b:a 128k -c:v libx264 -vprofile baseline \
-movflags faststart -vf scale=$newDim $output");```
Here is the breakdown:
f mp4 > format mp4
c:a libfdk_aac > audio codec
c:v libx264 > video codec
vprofile baseline > minimal codec usage for mobile
movflags faststart > put the moov atom at the beginning of file
$output > should have '.mp4' as a file ending
Of course the devil is in the details (and the number of processing cores you can throw at an online converter), but this will get you up and running at least.
Edit: Actually answered the question. :)
By the way, ffmpeg does offer the vf flag: -vf scale=320,-1, but sometimes it gives you a dimension not divisible by 2 which throws an error in x264 encoding. Its better to do the math yourself.
I want to upload a file (Indeed, I already did it using PHP and JQuery) but I want to encode it to MP4 and/or WebM in the process of the upload, such as Youtube does when you upload a video there. Is there a option to be able to do it in the server during the process?
Do I have to encode them first and then upload?
You can do it at the end of file upload, which is after you moved the file to a specific location (below code)
move_uploaded_file($_FILES["file"]["tmp_name"],"upload/" . $_FILES["file"]["name"]);
You can use a free and well-known library called FFMPEG which supports a wide range of formats. Please take a look at these two links for example and better explanation:
https://www.phpro.org/tutorials/Video-Conversion-With-FFMPEG.html
https://trac.ffmpeg.org/wiki/Using%20FFmpeg%20from%20PHP%20scripts
Basically, you can call the FFMPEG function from PHP like this
<?php
/*** convert video to flash ***/
exec("ffmpeg -i video.avi -ar 22050 -ab 32 -f flv -s 320x240 video.flv");
?>
I am using php ffmpeg in a laravel project, to do multiple things probe, extract frame and encode. I am having an issue when creating a frame from the uploaded video file.
This is how the frame is created:
$video = $ffmpeg->open($destinationPath.'/'.$filename);
$video
->frame(FFMpeg\Coordinate\TimeCode::fromSeconds(10))
->save(public_path().$frame_path);
This is sometimes working and creates the frame but other times is not. I noticed that this bug comes up when I am trying to open a .mov file.
It's possible that your version of ffmpeg does not support the codec that is used in the source video file, and hence it is not able to decompress the video and extract an image.
You could try processing the file from the command line to see if you can extract an image that way, and ffmpeg may give you some more information on the problem.
An example command line to extract a png frame from a video file
ffmpeg -y -ss 30 -i [source_file] -vframes 1 [target_file]
Add -f image2 as an output option if your output name is a variable.
The PHP-FFMpeg library appends the -ss argument by default before the input file which requires the timestamp to be accurate in order to obtain the frame. I encountered this problem in case of mkv file. Files such as mkv and mov can not be accurately seeked.
https://github.com/PHP-FFMpeg/PHP-FFMpeg/blob/master/src/FFMpeg/Media/Frame.php#L79
You need to pass true as the second argument to the save function in order to give a Frame closest to the given point. It changes the position of -ss argument in ffmpeg command.
-ss position (input/output)
When used as an input option (before -i), seeks in this input file to position. Note that in most formats it is
not possible to seek exactly, so ffmpeg will seek to the closest seek
point before position. When transcoding and -accurate_seek is enabled
(the default), this extra segment between the seek point and position
will be decoded and discarded. When doing stream copy or when
-noaccurate_seek is used, it will be preserved.
When used as an output option (before an output filename), decodes but
discards input until the timestamps reach position.
position must be a time duration specification, see (ffmpeg-utils)the
Time duration section in the ffmpeg-utils(1) manual.
Here is the code I've been using with PHP:
https://totaldev.com/extract-image-frame-video-php-ffmpeg/
<?php
// Full path to ffmpeg (make sure this binary has execute permission for PHP)
$ffmpeg = "/full/path/to/ffmpeg";
// Full path to the video file
$videoFile = "/full/path/to/video.mp4";
// Full path to output image file (make sure the containing folder has write permissions!)
$imgOut = "/full/path/to/frame.jpg";
// Number of seconds into the video to extract the frame
$second = 0;
// Setup the command to get the frame image
$cmd = $ffmpeg." -i \"".$videoFile."\" -an -ss ".$second.".001 -y -f mjpeg \"".$imgOut."\" 2>&1";
// Get any feedback from the command
$feedback = `$cmd`;
// Use $imgOut (the extracted frame) however you need to
// ...
I'm converting from WMV to FLV using FFMPEG, and my problem is that the FLV videos are so big! the 15 minutes video's size ranges between 150MB and 1GB!
I'm using the following FFMPEG command to convert and split WMV videos :
nohup nice -1 ffmpeg -y -ss 00:00:00 -t 00:15:00 -async 1 -i INPUT.WMV -acodec libmp3lame OUTPUT.FLV
And I've tried converting to MP4 before and the video size was much smaller than the FLV video.
So my questions are:
Would the MP4 videos have any
compatibility issues browsers?
Would it work on iPhone, iPad? (I
know FLV videos doesn't work on
iPhones or iPads)
What is the best FFMPEG command to
convert to MP4 without losing the
quality of the video?
A few points...
Video size has to do with the bit rate, dimension, and codec. It does not have anything to do with the container.
You can certainly expect 15 minutes of video to be large, assuming you want more than a postage stamp for viewing area. This is normal.
Any time you re-compress something, you are going to lose quality. There is no way around this. You might be able to keep most quality by recompressing at a higher bitrate, but this defeats what you are trying to accomplish.
Bottom line, unless you need to, don't do it. Simply encode your videos at the appropriate bitrate to begin with.
For converting any video to mp4, use:
ffmpeg.exe -i INPUT.wmv -vcodec libx264 -sameq OUTPUT.mp4
If the quality is too low on that then set the bitrate to be around what you want:
ffmpeg.exe -i INPUT.wmv -vcodec libx264 -b 500k OUTPUT.mp4
The output mp4 file plays in Flash, browsers that support H.264 MPEG4, iOS, and Android.