Getting all records json_encode - php

Question

I'm trying to get all data from table 1 in json format.
$arr = array();
$sql = "SELECT * FROM table1 ORDER BY price DESC";
$statement = $connect->prepare($sql);
$statement->execute();
$result = $statement->fetchAll();
foreach ($result as $val){
$arr['id'] = $val['item'];
$arr['price'] = $val['price'];
}
echo json_encode($arr);
Result:
{"id":"item00125","price":"112.35"}
The problem is that I get only one record. Why isn't the foreach(){ not sending all the records?

Answer 1

Try:
foreach ($result as $val){
$arr[] = array(
"id" => $val['item'],
"price" => val['price']
);
}

Answer 2

That's because your array is being over-written every time.
Try this:
$i = 0;
foreach ($result as $val){
$arr[$i]['id'] = $val['item'];
$arr[$i]['price'] = $val['price'];
$i++;
}
echo json_encode($arr);

Answer 3

You got only one result because you override array key at every itration of loop
Just pass result set into json_encode Without using loop as
$statement->execute();
$results=$statement->fetchAll(PDO::FETCH_ASSOC);
$json=json_encode($results);

Answer 4

here your result variable get the all records but the problem is in the for each loop you are put the each value in position of ['id'] and ['price'] so every time for each loop put the value at that same position so means replace the value so you are getting the last value so I thing you have to put the every record in different different position like this:
$i = 0;
foreach ($result as $val)
{
$arr[$i]['id'] = $val['item'];
$arr[$i]['price'] = $val['price'];
$i++;
}
echo json_encode($arr);
I hope it works fine