Trim symbol and decimal value from currency string - php

Question

I have currency input strings like these.
$50 ...I only need 50
$60.59 ...I only need 60, need to remove $ and .59
€360 ...I only need 360
€36.99 ...I only need 36, need to remove € and .99
£900 ...I only need 900
£90.99 ...I only need 90
In other words, I need to remove all currency symbols from the start of the string and I only need the integer value -- the decimal values can be cut off.

Answer 1

This RegEx should do it
(\$|€|£)\d+
This is even better (thanks to Jan)
[$€£]\d+
Use it with PHP's Preg Match
preg_match — Perform a regular expression match

Answer 2

I would recommend not using a regular expression, as it's overkill for this scenario.
$str = (int)ltrim($str, '$£€');
this is all you need.
Performance vs Regex
I ran the above test through a script to see what the time difference is between my answer and using a RegEx, and on average the RegEx solution was ~20% slower.
<?php
function funcA($a) {
echo (int)ltrim($a, '$£€');
};
function funcB($a) {
echo preg_replace('/^.*?([0-9]+).*$/', '$1', $a);
};
//setup (only run once):
function changeDataA() {}
function changeDataB() {}
$loops = 50000;
$timeA = 0.0;
$timeB = 0.0;
$prefix = str_split('€$€');
ob_start();
for($i=0; $i<$loops; ++$i) {
$a = $prefix[rand(0,2)] . rand(1,999) . '.' . rand(10,99);
$start = microtime(1);
funcA($a);
$timeA += microtime(1) - $start;
$start = microtime(1);
funcB($a);
$timeB += microtime(1) - $start;
}
ob_end_clean();
$timeA = round(1000000 * ($timeA / $loops), 3);
$timeB = round(1000000 * ($timeB / $loops), 3);
echo "
TimeA averaged $timeA microseconds
TimeB averaged $timeB microseconds
";
Timings vary depending on system load, so times should be considered only relative to each other, not compared between executions. Also this isn't a perfect script for performance benchmarking, there are outside influences that can affect these results, but this gives a general idea.
TimeA averaged 5.976 microseconds
TimeB averaged 6.831 microseconds

Answer 3

Use regular expression. Ex:
$toStr = preg_replace('/^.*?([0-9]+).*$/', '$1', $fromStr);
See preg_replace documentation.

Answer 4

use below way
$str = '$50 From here i need only 50
$60.59 From here i need only 60, Need to remove $ and .59
€360 From here i need only 360.
€36.99 From here i need only 36 need to remove € and .99.
£900 From here i need only 900.
£90.99 From here i need only 90.';
$arr_ = array('$','€','£');
echo str_replace($arr_,'',$str);

Answer 5

You could go for:
<?php
$string = <<<DATA
$50 From here i need only 50
$60.59 From here i need only 60, Need to remove $ and .59
€360 From here i need only 360.
€36.99 From here i need only 36 need to remove € and .99.
£900 From here i need only 900.
£90.99 From here i need only 90.
DATA;
# look for one of $,€,£ followed by digits
$regex = '~[$€£]\K\d+~';
preg_match_all($regex, $string, $amounts);
print_r($amounts);
/*
Array
(
[0] => Array
(
[0] => 50
[1] => 60
[2] => 360
[3] => 36
[4] => 900
[5] => 90
)
)
*/
?>
See a demo on ideone.com.

Answer 6

$newString=$string;
$currencyArray = array("$","€","£"); //just add the new item if you want that to add more
foreach($currencyArray as $value)
$newString= str_replace($value,"",$newString);
$newString has what you need.