It occurs #1054 Error when I call procedure in mysql - php

Question

CREATE PROCEDURE test_proc (in name varchar(100),out return_msg varchar(3000))
BEGIN
BEGIN
DECLARE v_return_msg VARCHAR(3000); -- return message
DECLARE v_error_flag INT DEFAULT 0;
DECLARE EXIT HANDLER FOR SQLEXCEPTION SET v_error_flag = -1;
START TRANSACTION;
INSERT INTO `tablename` (name, value) VALUES (name, 'Test2');
END;
IF v_error_flag < 0 THEN
ROLLBACK;
CALL DBMS_OUTPUT.PUT_LINE('Error : ' || mysql_error );
SELECT * FROM INSERT_INFO; -- UPDATE_TABLE_USED
SHOW ERRORS;
ELSE
COMMIT;
CALL DBMS_OUTPUT.PUT_LINE('Sucess : ' || sqlerrm );
SELECT 'Process succeed!!!';
END IF;
END
This is my mysql query(procedure).
However, When I CALL my procedure, It occurs error.
MySQL Message: #1054 - Unknown column 'v_error_flag' in 'field list'
I think IF statement occur error.
IF v_error_flag < 0 THEN
However, I don't know how can I fix it.

Answer 1

The v_error_flag is declared with in the BEGIN ... END.
The IF v_error_flag < 0 THEN condition is out of the block so v_error_flag is not recognized and throwing the error.
You need to move the IF v_error_flag < 0 THEN condition inside the BEGIN ... END block.
or
Simply remove or comment the Second BEGIN ... END block as:
CREATE PROCEDURE test_proc (in name varchar(100),out return_msg varchar(3000))
BEGIN
-- BEGIN <-- remove/comment this
DECLARE v_return_msg VARCHAR(3000); -- return message
DECLARE v_error_flag INT DEFAULT 0;
DECLARE EXIT HANDLER FOR SQLEXCEPTION SET v_error_flag = -1;
START TRANSACTION;
INSERT INTO `tablename` (name, value) VALUES (name, 'Test2');
-- END; <-- remove/comment this
IF v_error_flag < 0 THEN
ROLLBACK;
CALL DBMS_OUTPUT.PUT_LINE('Error : ' || mysql_error );
SELECT * FROM INSERT_INFO; -- UPDATE_TABLE_USED
SHOW ERRORS;
ELSE
COMMIT;
CALL DBMS_OUTPUT.PUT_LINE('Sucess : ' || sqlerrm );
SELECT 'Process succeed!!!';
END IF;
END