This question already has answers here:
PHP function to get the subdomain of a URL
(29 answers)
Closed 6 years ago.
I am new to PHP world and I would like to be able to get any subdomain typed on the URL, for example if the URL is mike.myapp.com I would like to get "mike", if the URL is "james.myapp.com" I would like to get "james" and so on.
How this is done with PHP?
I've done that using this in the past:
$domain = 'myapp.com';
$sub = preg_replace('/\.' . preg_quote($domain) . '/i', '', $_SERVER['HTTP_HOST']);
This effectively gets rid of your domain and TLD and isolates the subdomain name.
You could just as well not using regex and use str_ireplace() replacing ".myapp.com" with an empty string.
Related
This question already has answers here:
Get parts of URL in PHP
(4 answers)
Closed 1 year ago.
I had previously been using basename to grab the last part of my URL however have noticed some issues if my URL contains parameters.
So if my URL is this:
https://www.google.com/test-page/?utm_source=test
How would I pull test-page from this?
You split it by the / delimiter, and then take the fourth item
$link = 'https://www.google.com/test-page/?utm_source=test';
$split = explode('/', $link);
if(isset($split[3]))
{
echo $split[3];
}
This question already has answers here:
PHP, Delete parts of a URL variable [duplicate]
(3 answers)
Closed 4 years ago.
I want to replace '/50' with URL.my URL is
http://localhost/CI/admin/pcustomer/cprofile/50?customer=18267&mobile=&nearby=
I want url as
http://localhost/CI/admin/pcustomer/cprofile?customer=18267&mobile=&nearby=
From that little info in your question, this seems to be the simplest way to achieve "I want to replace '/50' with URL"
$url = str_replace('/50', '', 'http://localhost/CI/admin/pcustomer/cprofile/50?customer=18267&mobile=&nearby=');
This question already has answers here:
How can I get parameters from a URL string?
(12 answers)
Closed 8 years ago.
I want to extract site link from Google URL, I need an efficient way to do this,
I have extracted this, but i am not comfortable with that like,
$googleURL = "http://www.google.ca/local_url?dq=food+Toronto,+ON&q=https://plus.google.com/110334461338830338847/about%3Fgl%3DCA%26hl%3Den-CA&ved=0CHAQlQU&sa=X&ei=HzrCVNX-JqSzigb-94D4CQ&s=ANYYN7nQx_FiR1PuowDmXBi1oyfkI2MImg";
I want this
https://plus.google.com/110334461338830338847/
I have done this in a following way.
$first = current(explode("about", $googleURL)); // returns http://www.google.ca/local_url?dq=food+Toronto,+ON&q=https://plus.google.com/110334461338830338847/
and then,
$myLink = explode("&q=", $first);
echo $myLink[1]; // return my need => https://plus.google.com/110334461338830338847/
but there may be two "about" or "&q=" in a googleURL which can cause problem.
I know that, this googleURL will be redirected to my need, but I need that specific link for a purpose.
I guess that it is not really safe to parse that since google can change its implementation anytime.
However, if you want to get a parameter from a String url, this question covers it pretty well :
How to get parameters from a URL string?
$parts = parse_url($googleUrl);
parse_str($parts['query'], $query);
echo $query['q'];
This question already has answers here:
Beautiful way to remove GET-variables with PHP?
(12 answers)
How to remove content from url after question mark. preg_match or preg_replace?
(2 answers)
Closed 8 years ago.
I have this url: http:www.blabla.com/x/x/x/x?username=testuser
I need a string to read this url, but forget everything and including the ? mark.
So it becomes this: http:www.blabla.com/x/x/x/x
The reason for this is because I am making this variable:
$host = $_SERVER['SERVER_NAME'] . $_SERVER['REQUEST_URI'];
And this code:
if($host == "http:www.blabla.com/x/x/x/x") {
echo "lul";
}
But right now, the URL changes depending on what user is on, and it has to execute the echo no matter what user is on.
So I read some reges and preg_match etc. and I just wanted to hear your opinions or advice. How would I accomblish this the best? thanks!
This is too trivial of a task for regex.
$host = $_SERVER['SERVER_NAME'] . explode("?", $_SERVER['REQUEST_URI'], 2)[0];
(Note: this assumes you're up-to-date, or at least using PHP 5.4, for the dereference to work without a temporary variable)
Or if you must omit the get / request section just explode ? and use $host[0]
This question already has answers here:
Closed 11 years ago.
Possible Duplicate:
Detecting a url using preg_match? without in the string
I wanting to search a string that is input by the user, for instances of http:// if one is found I want to wrap the link in the correct html,
so for example, the following could be input by a user,
Google's url is http://www.google.com,
what I want to save that as it,
Google's url is http://www.google.com
is this possible?
function make_clickable($sText) {
$sClickText = str_replace(' www.', ' http://www.', $sText);
$sClickText = preg_replace("/([\s])?(http|ftp|https)([\:\/\/])([^\s]+)/i", " $2$3$4",$sClickText);
return $sClickText;
}
Tadaa!