Check if the value is an integer in PHP - php

Question

I am working on a project and in that project I have two objectives
I receive data from user
I check if the data sent by the user is an interger or in case is an integer, if is less than 1
So I wrote this code
<form action="" method="get">
<input type="text" name="quantity" value="2"/>
<input type="submit"/>
</form>
<?php
if (!is_int($_GET['quantity']) || $_GET['quantity'] < 1){
$_GET['quantity'] = 1;
}
echo $_GET['quantity'];
The problem, I am facing is that, the program always echo 1 even if the data is less than 1 or is not an integer at all.
Help me solve this problem please

Answer 1

Try replacing
if (!is_int($_GET['quantity']) || $_GET['quantity'] < 1){
with
$quantity = (int) $_GET['quantity'];
if ($quantity < 1) {...}
This casts it to an integer, and if not an integer, casts it as being assigned 0. Then it compares whether it is < 1 or not, and should have the desired result that you are looking for.

Answer 2

The problem is, 'quantity' is actually a string. So when you call
is_int($_GET["quantity"))
it will always return false, because it is of type string.
The easiest solution would be to convert 'quantity' to an int.
is_int((int) $_GET["quantity")

Answer 3

Hope this will help you
$quantity = $_GET['quantity'];
if (!is_numeric($quantity) || $quantity < 1)
{
$quantity = 1;
}
echo $quantity;

Answer 4

try this it will work
<?php
if (is_numeric($_GET['quantity']) || $_GET['quantity'] < 1){
$_GET['quantity'] = 1;
}
echo $_GET['quantity'];

Answer 5

You can just create a function to get the integer value of the input.
function strtonumber($string = "") {
$num = intval($string);
if ($num === 0) {
$num = preg_replace("/[^0-9]/", "", $string);
$num = intval($num);
}
return $num;
}
$quantity = strtonumber($_GET["quantity"]);
if ($quantity < 1) {
$quantity = 1
}
intval returns the integer value of the input.
echo intval("12ab"); // 12
but if the digits come after a letter, it returns 0.
echo intval("ab12"); // 0
In that case, to get the 12 from "ab12", we remove any non-digit character and get the integer value again.
The function will always return an integer so you don't need to check if the input is an integer or not.