What is the php function to extract only the word Duitsland from the following string /Duitsland|/groepsreizen fietsen|Stars/1.
I tried everything but dit not find the right method.
http://php.net/manual/de/function.str-replace.php
$result= str_replace("Duitsland", "", "/Duitsland|/groepsreizen fietsen|Stars/1");
Result: "/|/groepsreizen fietsen|Stars/1"
There is multiple way to do this work. One way is using regex. Use regex in preg_match() to finding specific word of string.
$str = "/Duitsland|/groepsreizen fietsen|Stars/1";
preg_match("/[^|\/]+/", $str, $match);
echo $match[0];
You can test it in demo
with strpos function find require o/p
$haystack = '/Duitsland|/groepsreizen fietsen|Stars/1';
$needle = 'Duitsland';
if (strpos($haystack,$needle) !== false) {
echo $needle;
}
I think this is what you're looking for:
(this code does not need to know what is the word before, it just seeks the first (as long as possible) word in the string)
<?php
$str = "/Duitsland|/groepsreizen fietsen|Stars/1";
preg_match("/\w+/i", $str, $matches);
$first_word = array_shift($matches);
echo $first_word;
It will work no matter how many non-letter symbols there are before that word, i.e. it's not dependent on any fixed-count other characters.
Demo: http://ideone.com/GX8IT6
Related
According to PHP manual "If matches is provided, then it is filled with the results of search. $matches[0] will contain the text that matched the full pattern, $matches[1] will have the text that matched the first captured parenthesized subpattern, and so on."
How can I return a value from a string with only knowing the first few characters?
The string is dynamic and will always change whats inside, but the first four character will always be the same.
For example how could I return "Car" from this string "TmpsCar". The string will always have "Tmps" followed by something else.
From what I understand I can return using something like this
preg_match('/(Tmps+)/', $fieldName, $matches);
echo($matches[1]);
Should return "Car".
Your regex is flawed. Use this:
preg_match('/^Tmps(.+)$/', $fieldName, $matches);
echo($matches[1]);
$matches = []; // Initialize the matches array first
if (preg_match('/^Tmps(.+)/', $fieldName, $matches)) {
// if the regex matched the input string, echo the first captured group
echo($matches[1]);
}
Note that this task could easily be accomplished without regex at all (with better performance): See startsWith() and endsWith() functions in PHP.
"The string will always have "Tmps" followed by something else."
You don't need a regular expression, in that case.
$result = substr($fieldName, 4);
If the first four characters are always the same, just take the portion of the string after that.
An alternative way is using the explode function
$fieldName= "TmpsCar";
$matches = explode("Tmps", $fieldName);
if(isset($matches[1])){
echo $matches[1]; // return "Car"
}
Given that the text you are looking in, contains more than just a string, starting with Tmps, you might look for the \w+ pattern, which matches any "word" char.
This would result in such an regular expression:
/Tmps(\w+)/
and altogether in php
$text = "This TmpsCars is a test";
if (preg_match('/Tmps(\w+)/', $text, $m)) {
echo "Found:" . $m[1]; // this would return Cars
}
I would like to know how I can cut a string in PHP starting from the last character -> to a specific character. Lets say I have following link:
www.whatever.com/url/otherurl/2535834
and I want to get 2535834
Important note: the number can have a different length, which is why I want to cut out to the / no matter how many numbers there are.
Thanks
In this special case, an url, use basename() :
echo basename('www.whatever.com/url/otherurl/2535834');
A more general solution would be preg_replace(), like this:
<----- the delimiter which separates the search string from the remaining part of the string
echo preg_replace('#.*/#', '', $url);
The pattern '#.*/#' makes usage of the default greediness of the PCRE regex engine - meaning it will match as many chars as possible and will therefore consume /abc/123/xyz/ instead of just /abc/ when matching the pattern.
Use
explode() AND end()
<?php
$str = 'www.whatever.com/url/otherurl/2535834';
$tmp = explode('/', $str);
echo end ($tmp);
?>
Working Demo
This should work for you:
(So you can get the number with or without a slash, if you need that)
<?php
$url = "www.whatever.com/url/otherurl/2535834";
preg_match("/\/(\d+)$/",$url,$matches);
print_r($matches);
?>
Output:
Array ( [0] => /2535834 [1] => 2535834 )
With strstr() and str_replace() in action
$str = 'www.whatever.com/url/otherurl/2535834';
echo str_replace("otherurl/", "", strstr($str, "otherurl/"));
strstr() finds everything (including the needle) after the needle and the needle gets replaced by "" using str_replace()
if your pattern is fixed you can always do:
$str = 'www.whatever.com/url/otherurl/2535834';
$tmp = explode('/', $str);
echo $temp[3];
Here's mine version:
$string = "www.whatever.com/url/otherurl/2535834";
echo substr($string, strrpos($string, "/") + 1, strlen($string));
I have a string that contains many underscores followed by words ex: "Field_4_txtbox" I need to find the last underscore in the string and remove everything following it(including the "_"), so it would return to me "Field_4" but I need this to work for different length ending strings. So I can't just trim a fixed length.
I know I can do an If statement that checks for certain endings like
if(strstr($key,'chkbox')) {
$string= rtrim($key, '_chkbox');
}
but I would like to do this in one go with a regex pattern, how can I accomplish this?
The matching regex would be:
/_[^_]*$/
Just replace that with '':
preg_replace( '/_[^_]*$/', '', your_string );
There is no need to use an extremly costly regex, a simple strrpos() would do the job:
$string=substr($key,0,strrpos($key,"_"));
strrpos — Find the position of the last occurrence of a substring in a string
You can also just use explode():
$string = 'Field_4_txtbox';
$temp = explode('_', strrev($string), 2);
$string = strrev($temp[1]);
echo $string;
As of PHP 5.4+
$string = 'Field_4_txtbox';
$string = strrev(explode('_', strrev($string), 2)[1]);
echo $string;
I'm attempting to create a bad word filter in PHP that will analyze the word and match against an array of known bad words, but keep the first letter of the word and replace the rest with asterisks. Example:
fook would become f***
shoot would become s**
The only part I don't know is how to keep the first letter in the string, and how to replace the remaining letters with something else while keeping the same string length.
$string = preg_replace("/\b(". $word .")\b/i", "***", $string);
Thanks!
$string = 'fook would become';
$word = 'fook';
$string = preg_replace("~\b". preg_quote($word, '~') ."\b~i", $word[0] . str_repeat('*', strlen($word) - 1), $string);
var_dump($string);
$string = preg_replace("/\b".$word[0].'('.substr($word, 1).")\b/i", "***", $string);
This can be done in many ways, with very weird auto-generated regexps...
But I believe using preg_replace_callback() would end up being more robust
<?php
# as already pointed out, your words *may* need sanitization
foreach($words as $k=>$v)
$words[$k]=preg_quote($v,'/');
# and to be collapsed into a **big regexpy goodness**
$words=implode('|',$words);
# after that, a single preg_replace_callback() would do
$string = preg_replace_callback('/\b('. $words .')\b/i', "my_beloved_callback", $string);
function my_beloved_callback($m)
{
$len=strlen($m[1])-1;
return $m[1][0].str_repeat('*',$len);
}
Here is unicode-friendly regular expression for PHP:
function lowercase_except_first_letter($s) {
// the following line SKIP the first word and pass it to callback func...
// \W it allows to keep the first letter even in words in quotes and brackets
return preg_replace_callback('/(?<!^|\s|\W)(\w)/u', function($m) {
return mb_strtolower($m[1]);
}, $s);
}
I need to know how I can replace the last "s" from a string with ""
Let's say I have a string like testers and the output should be tester.
It should just replace the last "s" and not every "s" in a string
how can I do that in PHP?
if (substr($str, -1) == 's')
{
$str = substr($str, 0, -1);
}
Update: Ok it is also possible without regular expressions using strrpos ans substr_replace:
$str = "A sentence with 'Testers' in it";
echo substr_replace($str,'', strrpos($str, 's'), 1);
// Ouputs: A sentence with 'Tester' in it
strrpos returns the index of the last occurrence of a string and substr_replace replaces a string starting from a certain position.
(Which is the same as Gordon proposed as I just noticed.)
All answers so far remove the last character of a word. However if you really want to replace the last occurrence of a character, you can use preg_replace with a negative lookahead:
$s = "A sentence with 'Testers' in it";
echo preg_replace("%s(?!.*s.*)%", "", $string );
// Ouputs: A sentence with 'Tester' in it
$result = rtrim($str, 's');
$result = str_pad($result, strlen($str) - 1, 's');
See rtrim()
Your question is somewhat unclear whether you want to remove the s from the end of the string or the last occurence of s in the string. It's a difference. If you want the first, use the solution offered by zerkms.
This function removes the last occurence of $char from $string, regardless of it's position in the string or returns the whole string, when $char does not occur in the string.
function removeLastOccurenceOfChar($char, $string)
{
if( ($pos = strrpos($string, $char)) !== FALSE) {
return substr_replace($string, '', $pos, 1);
}
return $string;
}
echo removeLastOccurenceOfChar('s', "the world's greatest");
// gives "the world's greatet"
If your intention is to inflect, e.g singularize/pluralize words, then have a look at this simple inflector class to know which route to take.
$str = preg_replace("/s$/i","",rtrim($str));
The very simplest solution is using rtrim()
That is exactly what that function is intended to be used for:
Strip whitespace (or other characters) from the end of a string.
Nothing simpler than that, I am not sure why, and would not follow the suggestions in this thread going from regex to "if/else" blocks.
This is your code:
$string = "Testers";
$stripped = rtrim( $string, 's' );
The output will be:
Tester