How to resolve file missing on remote server - php

Please i need your help on this. Any time i transfer this file into remote server through ftp, it often get missing on the server somehow. I always have to re-upload it. Recently all i get are errors like this PHP Warning: require(maxUpload.class.php): failed to open stream: No such file or directory.
I know the errors are due to due to my require() function.
Is there any reason this file keep getting lost on the remote server?
<?php
require 'maxUpload.class.php'
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title>Upload Page</title>
</head>
<body>
<?php
$myUpload = new maxUpload();
//$myUpload->setUploadLocation(getcwd().DIRECTORY_SEPARATOR);
$myUpload->uploadFile();
?>
</body>
This is maxUpload.class.php
<?php
class maxUpload{
var $uploadLocation;
function maxUpload(){
$this->uploadLocation = getcwd().DIRECTORY_SEPARATOR."/images". DIRECTORY_SEPARATOR;
}
function setUploadLocation($dir){
$this->uploadLocation = $dir;
}
function showUploadForm($msg='',$error=''){
?>
<div id="container">
<div id="content">
<?php
if ($msg != ''){
echo '<p class="msg">'.$msg.'</p>';
} else if ($error != ''){
echo '<p class="emsg">'.$error.'</p>';
}
?>
<form action="" method="post" enctype="multipart/form-data" >
<center>
<label>Upload Image (Jpeg Only)
<input name="myfile" type="file" size="30" />
</label>
<label>
<input type="submit" name="submitBtn" class="sbtn" value="Upload" />
</label>
</center>
</form>
</div>
</div>
<?php
}
function uploadFile(){
if (!isset($_POST['submitBtn'])){
$this->showUploadForm();
} else {
$msg = '';
$error = '';
if (!file_exists($this->uploadLocation)){
$error = "The target directory doesn't exists!";
} else if (!is_writeable($this->uploadLocation)) {
$error = "The target directory is not writeable!";
} else {
$target_path = $this->uploadLocation . basename( $_FILES['myfile']['name']);
if(#move_uploaded_file($_FILES['myfile']['tmp_name'], $target_path)) {
$msg = basename( $_FILES['myfile']['name']).
" <b style='color:white;'>was uploaded successfully!</b>";
} else{
$error = "The upload process failed!";
}
}
$this->showUploadForm($msg,$error);
}
}
}
?>

Your file is not missing, this error also indicate that you are giving wrong path to the file, make sure maxUpload.class.php is in same folder. you need to give correct path to require() function where to locate this file.
You can also use getcwd() to Gets the current working directory.
something like echo getcwd();. you can use chdir() function to go to specific folder by giving correct path chdir("../");
i don't know your folder structure but add
require '../maxUpload.class.php' or
require '/maxUpload.class.php'

Related

How do I change upload location from working directory to upload folder

I got (from a forum) an image upload script that replace the existing image with the new one once they bear the same name. It works for my need but i need the image to be in my upload folder. How do i do this?
<?php
/*************************************************
* Max's File Uploader
*
* Version: 1.0
* Date: 2007-11-26
*
****************************************************/
class maxUpload{
var $uploadLocation;
/**
* Constructor to initialize class varaibles
* The uploadLocation will be set to the actual
* working directory
*
* #return maxUpload
*/
function maxUpload(){
$this->uploadLocation = getcwd().DIRECTORY_SEPARATOR;
}
/**
* This function sets the directory where to upload the file
* In case of Windows server use the form: c:\\temp\\
* In case of Unix server use the form: /tmp/
*
* #param String Directory where to store the files
*/
function setUploadLocation($dir){
$this->uploadLocation = $dir;
}
function showUploadForm($msg='',$error=''){
?>
<div id="container">
<div id="header"><div id="header_left"></div>
<div id="header_main">Max's File Uploader</div><div id="header_right"></div></div>
<div id="content">
<?php
if ($msg != ''){
echo '<p class="msg">'.$msg.'</p>';
} else if ($error != ''){
echo '<p class="emsg">'.$error.'</p>';
}
?>
<form action="" method="post" enctype="multipart/form-data" >
<center>
<label>File:
<input name="myfile" type="file" size="30" />
</label>
<label>
<input type="submit" name="submitBtn" class="sbtn" value="Upload" />
</label>
</center>
</form>
</div>
<div id="footer">Powered by PHP F1</div>
</div>
<?php
}
function uploadFile(){
if (!isset($_POST['submitBtn'])){
$this->showUploadForm();
} else {
$msg = '';
$error = '';
//Check destination directory
if (!file_exists($this->uploadLocation)){
$error = "The target directory doesn't exists!";
} else if (!is_writeable($this->uploadLocation)) {
$error = "The target directory is not writeable!";
} else {
$target_path = $this->uploadLocation . basename( $_FILES['myfile']['name']);
if(#move_uploaded_file($_FILES['myfile']['tmp_name'], $target_path)) {
$msg = basename( $_FILES['myfile']['name']).
" was uploaded successfully!";
} else{
$error = "The upload process failed!";
}
}
$this->showUploadForm($msg,$error);
}
}
}
?>
The html code looks like:
<?php require_once("maxUpload.class.php"); ?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>File Uploader</title>
<link href="style/style.css" rel="stylesheet" type="text/css" />
</head>
<body>
<?php
$myUpload = new maxUpload();
//$myUpload->setUploadLocation(getcwd().DIRECTORY_SEPARATOR);
$myUpload->uploadFile();
?>
</body>
Well, i was able to solve my problem with modification of this single line from $this->uploadLocation = getcwd().DIRECTORY_SEPARATOR;into this
$this->uploadLocation = getcwd().DIRECTORY_SEPARATOR."images". DIRECTORY_SEPARATOR;
Thanks every one.

uploading zip files with PHP, undefined index

I'm having issues uploading zip files and can't seem to find an answer.
Index.php
<form id="convertFile" action="convert.php" method="post" enctype="multipart/form-data">
<div class="form-group">
<label for="exampleInputFile">File input</label>
<input name="upload" type="file" id="inputFile">
</div>
<div class="form-group">
<button type="submit">Submit</button>
</div>
</form>
convert.php:
if(isset($_FILES)){
echo $_FILES['upload']['name'];
}else{
echo json_encode(array('status'=>'error'));
}
When I upload a zip file, I get: Notice: Undefined index: upload in C:\wamp\www\xmlconverter\convert.php on line 3
This is what chrome shows in the post header:
------WebKitFormBoundaryuFNy5dZtFj7olmD5
Content-Disposition: form-data; name="zip_file"; filename="123.zip"
Content-Type: application/x-zip-compressed
------WebKitFormBoundaryuFNy5dZtFj7olmD5--
This works on any other major file format, but can't get it to read the zip file. If I var_dump $_FILES or $_POST they are empty.
What am I missing? Why does all other files work but zip does not.
Thank you
using wamp and php 5.5.12
Where is your zip file type definition?
Anyways, let say this was the html form to upload zip files you'd have the following:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>Untitled Document</title>
</head>
<body>
<?php if($message) echo "<p>$message</p>"; ?>
<form enctype="multipart/form-data" method="post" action="">
<label>Choose a zip file to upload: <input type="file" name="zip_file" /></label>
<br />
<input type="submit" name="submit" value="Upload" />
</form>
</body>
</html>
On the server-side script which handles the post you'd have:
<?php
if($_FILES["zip_file"]["name"]) {
$filename = $_FILES["zip_file"]["name"];
$source = $_FILES["zip_file"]["tmp_name"];
$type = $_FILES["zip_file"]["type"];
$name = explode(".", $filename);
$accepted_types = array('application/zip', 'application/x-zip-compressed', 'multipart/x-zip', 'application/x-compressed');
foreach($accepted_types as $mime_type) {
if($mime_type == $type) {
$okay = true;
break;
}
}
$continue = strtolower($name[1]) == 'zip' ? true : false;
if(!$continue) {
$message = "The file you are trying to upload is not a .zip file. Please try again.";
}
$target_path = "/home/var/yoursite/httpdocs/".$filename; // change this to the correct site path
if(move_uploaded_file($source, $target_path)) {
//if you also wanted to extract the file after upload
//you can do the following
$zip = new ZipArchive();
$x = $zip->open($target_path);
if ($x === true) {
$zip->extractTo("/home/var/yoursite/httpdocs/"); // change this to the correct site path
$zip->close();
unlink($target_path);
}
$message = "Your .zip file was uploaded and unpacked.";
} else {
$message = "There was a problem with the upload. Please try again.";
}
}
?>
I used a script very similar to one posted by #unixmiah without issue on my cPanel based server. Worked great (and has for year now) but ran into issue of error "PHP, undefined index" when using locally with wamp.
Here is the mod that worked for me:
<?php
function rmdir_recursive($dir) {
foreach(scandir($dir) as $file) {
if ('.' === $file || '..' === $file) continue;
if (is_dir("$dir/$file")) rmdir_recursive("$dir/$file");
else unlink("$dir/$file");
}
rmdir($dir);
}
if(!empty($_FILES)){
//added above to script and closing } at bottom
if($_FILES["zip_file"]["name"]) {
$filename = $_FILES["zip_file"]["name"];
$source = $_FILES["zip_file"]["tmp_name"];
$type = $_FILES["zip_file"]["type"];
$name = explode(".", $filename);
$accepted_types = array('application/zip', 'application/x-zip-compressed', 'multipart/x-zip', 'application/x-compressed');
foreach($accepted_types as $mime_type) {
if($mime_type == $type) {
$okay = true;
break;
}
}
$continue = strtolower($name[1]) == 'zip' ? true : false;
if(!$continue) {
$message = "<b>The file you are trying to upload is not a .zip file! Please try again...</b>";
}
$target_path = "somedir/somesubdir/".$filename; // change this to the correct site path
if(move_uploaded_file($source, $target_path)) {
$zip = new ZipArchive();
$x = $zip->open($target_path);
if ($x === true) {
$zip->extractTo("somedir/somesubdir/"); // change this to the correct site path
$zip->close();
unlink($target_path);
}
$message = "<h2>ZIP file was uploaded and content was replaced!</h2>";
} else {
$message = "There was a problem with the upload. Please try again.";
}
}
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>QikSoft ZIP Upper</title>
</head>
<body>
<?php if(!empty($message)) echo "<p>$message</p>"; ?>
<form enctype="multipart/form-data" method="post" action="">
<label><h3>Upload Your ZIP:</h3> <input type="file" name="zip_file" /></label>
<br /><br />
<input type="submit" name="submit" value="START UPLOAD" />
</form>
</body>
</html>
Also note that the echo message has been changed:
<?php if(!empty($message)) echo "<p>$message</p>"; ?>
One thing that does not work is file restriction. Currently allows other types besides ZIP. Anyone with fix, be greatly appreciated.
It's echo $_FILES['upload']['tmp_name'];
Try checking and adjusting the post_max_size value in your php.ini file, this worked for me as the default is 3M, raised the value to 128M and everything was peachy

on upload get all file names in array in php

What i want to know is how can I get a list [specifically array] of all the files name in a directory when I select it through upload button, after which I would upload that array of files to the database. As one file as a single entry. So how do I do that?
No to forget that I just need files names and I have to upload these names only not the actual files.
are the files on the server? if you hopping to have a button you click on browser and open a folder on the end user this will not work. most browsers only allow single file selection
If you are using ftp, this function will return all of the filenames of a directory in an array.
function ftp_searchdir($conn_id, $dir) {
if(!#ftp_is_dir($conn_id, $dir)) {
die('No such directory on the ftp-server');
}
if(strrchr($dir, '/') != '/') {
$dir = $dir.'/';
}
$dirlist[0] = $dir;
$list = ftp_nlist($conn_id, $dir);
foreach($list as $path) {
$path = './'.$path;
if($path != $dir.'.' && $path != $dir.'..') {
if(ftp_is_dir($conn_id, $path)) {
$temp = ftp_searchdir($conn_id, ($path), 1);
$dirlist = array_merge($dirlist, $temp);
}
else {
$dirlist[] = $path;
}
}
}
ftp_chdir($conn_id, '/../');
return $dirlist;
}
<?
if (isset($_POST[submit])) {
$uploadArray= array();
$uploadArray[] = $_POST['uploadedfile'];
$uploadArray[] = $_POST['uploadedfile2'];
$uploadArray[] = $_POST['uploadedfile3'];
foreach($uploadArray as $file) {
$target_path = "upload/";
$target_path = $target_path . basename( $_FILES['$file']['name']);
if(move_uploaded_file($_FILES['$file']['tmp_name'], $target_path)) {
echo "The file ". basename( $_FILES['$file']['name']).
" has been uploaded";
} else{
echo "There was an error uploading the file, please try again!";
}
}
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1" />
<title>Untitled Document</title>
</head>
<body>
<form enctype="multipart/form-data" action="upload-simple.php" method="POST">
<p>
<input type="hidden" name="MAX_FILE_SIZE" value="100000" />
Choose a file to upload:
<input name="uploadedfile" type="file" />
</p>
<p>Choose a file to upload:
<input name="uploadedfile2" type="file" />
</p>
<p>Choose a file to upload:
<input name="uploadedfile3" type="file" />
<input name="submit" type="submit" id="submit" value="submit" />
</p>
</form>
</body>
</html>
This Might be Solve your Problems
If the files already exist on the server you can use glob
$files = glob('*.ext'); // or *.* for all files
foreach($files AS $file){
// $file is the name of the file
}

Error with php code (file upload)

I am getting the following errors:
Notice: Undefined index: theimage in C:\wamp\www_upload\index.php on line 5
Notice: Undefined index: theimage in C:\wamp\www_upload\index.php on line 7
Here is the code:
<?php
$target_path = "images/";
$target_path = $target_path . basename( $_FILES['theimage']['name']);
if(move_uploaded_file($_FILES['theimage']['tmp_name'], $target_path)) {
echo "<p>The image ". basename( $_FILES['theimage']['name']). " has been uploaded</p>";
} else{
echo "<p>There was an error uploading the image, please try again!</p>";
}
?>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<html>
<head>
<title></title>
<meta name="" content="">
</head>
<body>
<form enctype="multipart/form-data" action="index.php" method="POST">
<fieldset>
<input name="theimage" type="file" />
<input type="submit" value="Upload" />
</fieldset>
</form>
</body>
</html>
Any ideas on how to fix this please ?
<?php
if(!empty($_FILES['theimage'])) {
// YOUR CURRENT PHP CODE HERE
?>
The problem is the upload script is executing even if nothing is posted (like when you first load the page).
Check to make sure you're getting data in $_FILES or $_POST before you try to do anything with them:
<?php
if(isset($_FILES)) { // if(isset($_POST))
// would work as well
$target_path = "images/";
$target_path = $target_path . basename( $_FILES['theimage']['name']);
if(move_uploaded_file($_FILES['theimage']['tmp_name'], $target_path)) {
echo "<p>The image ". basename( $_FILES['theimage']['name']).
" has been uploaded</p>";
} else {
echo "<p>There was an error uploading the image!</p>";
}
}
?>
Change your submit button to:
<input type = 'submit' name = 'theSubmitBtn' value = 'Upload'>
Then, wrap all of your php code at the top inside of this if check:
if(isset($_POST['theSubmitBtn'])) {
... Your Code ...
}
See if that works for you. On a side note, you will also need to add much more error checking if this is to be used in a production environment.

how to upload image code and save path into mysql db

how to write code to upload image and save path into mysql db?
i have tried but none are working.
One way is to upload image and store it in a folder on server, and save name to mysql database. Here's an example ::
First we'll create a form to upload ::
//file.html
Upload your file to the database...
<form action="upload.php" method="post" enctype="multipart/form-data" name="uploadform">
<input type="hidden" name="MAX_FILE_SIZE" value="350000">
<input name="picture" type="file" id="picture" size="50">
<input name="upload" type="submit" id="upload" value="Upload Picture!">
</form>
Then we create upload.php
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title> Upload Image </title>
<?php
// if something was posted, start the process...
if(isset($_POST['upload']))
{
// define the posted file into variables
$name = $_FILES['picture']['name'];
$tmp_name = $_FILES['picture']['tmp_name'];
$type = $_FILES['picture']['type'];
$size = $_FILES['picture']['size'];
// if your server has magic quotes turned off, add slashes manually
if(!get_magic_quotes_gpc()){
$name = addslashes($name);
}
// open up the file and extract the data/content from it
$extract = fopen($tmp_name, 'r');
$content = fread($extract, $size);
$content = addslashes($content);
fclose($extract);
// connect to the database
include "connect.php";
// the query that will add this to the database
$addfile = "INSERT INTO files (name, size, type, content ) VALUES ('$name', '$size', '$type', '$content')";
mysql_query($addfile) or die(mysql_error());
if(!empty($_FILES))
{
$target = "upload/";
$target = $target . basename( $_FILES['picture']['name']) ;
$ok=1;
$picture_size = $_FILES['picture']['size'];
$picture_type=$_FILES['picture']['type'];
//This is our size condition
if ($picture_size > 5000000)
{
echo "Your file is too large.<br>";
$ok=0;
}
//This is our limit file type condition
if ($picture_type =="text/php")
{
echo "No PHP files<br>";
$ok=0;
}
//Here we check that $ok was not set to 0 by an error
if ($ok==0)
{
Echo "Sorry your file was not uploaded";
}
//If everything is ok we try to upload it
else
{
if(move_uploaded_file($_FILES['picture']['tmp_name'], $target))
{
echo "The file ". basename( $_FILES['picture']['name']). " has been uploaded <br/>";
}
else
{
echo "Sorry, there was a problem uploading your file.";
}
}
}
mysql_close();
echo "Successfully uploaded your picture!";
}else{die("No uploaded file present");
}
?>
</head>
<body>
<div align="center">
<img src="upload/<?php echo $name; ?>"
<br />
upload more images
</div>
</body>
</html>
//getpicture.php
**//Finally the connect.php**

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