how can i find second maximum of my query - php

Here is my SQL query to find a row in currency_price table grouped by maximum date of inserting to table. My question is how to find the second maximum. I mean how can I change this query to find the second maximum row in each group:
select currency_id,buy,sell
from (select * from currency_price order by `currency_id`, cu_date desc,buy,sell) x
group by `currency_id`
with this query i found a row for each id so for example i have sell and buy for each id .exm:
id sell buy
1000 500 480
1001 20 19
...
but here i want the second maximum date for each id.
I know some query to find second maximum but all does not take me to my answer.

If it is MySql then Use LIMIT 1,1; # Retrieve rows [start with rec]1-[fetch rec count]1
http://dev.mysql.com/doc/refman/5.7/en/select.html

Use ROW_NUMBER()
Sample
SELECT * FROM
(
SELECT *,ROW_NUMBER() OVER (ORDER BY AGE DESC) RNUM FROM TEST_TABLE
) QUERY1 WHERE RNUM=2

You could manually add a group order number to your initial ordered query & then select the second from each row.
The inner query, orders as required & numbers the rows starting from 1, resetting each time the currency_id changes.
set #num := 0, #ci := -1;
select currency_id,buy,sell
from
(select *,
#num := if(#ci = currency_id, #num + 1, 1) as gp_number,
#ci := currency_id as dummy
from currency_price
order by `currency_id`, cu_date desc,buy,sell) x
where gp_number=2
This could be put into a stored procedure from workbench as follows :
DELIMITER $$
CREATE PROCEDURE SecondMaximum()
BEGIN
set #num := 0, #ci := -1;
select currency_id,buy,sell
from
(select *,
#num := if(#ci = currency_id, #num + 1, 1) as gp_number,
#ci := currency_id as dummy
from currency_price
order by `currency_id`, cu_date desc,buy,sell) x
where gp_number=2;
END$$
DELIMITER ;
And from PHP you execute "CALL SecondMaximum();"
If you wanted to be able to change tables and/or fields, then you could pass these as string variables to the procedure & create & execute a prepared statement within the stored procedure. Just do a google search for tutorials on those.

Related

Random content definitive method [duplicate]

How can I best write a query that selects 10 rows randomly from a total of 600k?
A great post handling several cases, from simple, to gaps, to non-uniform with gaps.
http://jan.kneschke.de/projects/mysql/order-by-rand/
For most general case, here is how you do it:
SELECT name
FROM random AS r1 JOIN
(SELECT CEIL(RAND() *
(SELECT MAX(id)
FROM random)) AS id)
AS r2
WHERE r1.id >= r2.id
ORDER BY r1.id ASC
LIMIT 1
This supposes that the distribution of ids is equal, and that there can be gaps in the id list. See the article for more advanced examples
SELECT column FROM table
ORDER BY RAND()
LIMIT 10
Not the efficient solution but works
Simple query that has excellent performance and works with gaps:
SELECT * FROM tbl AS t1 JOIN (SELECT id FROM tbl ORDER BY RAND() LIMIT 10) as t2 ON t1.id=t2.id
This query on a 200K table takes 0.08s and the normal version (SELECT * FROM tbl ORDER BY RAND() LIMIT 10) takes 0.35s on my machine.
This is fast because the sort phase only uses the indexed ID column. You can see this behaviour in the explain:
SELECT * FROM tbl ORDER BY RAND() LIMIT 10:
SELECT * FROM tbl AS t1 JOIN (SELECT id FROM tbl ORDER BY RAND() LIMIT 10) as t2 ON t1.id=t2.id
Weighted Version: https://stackoverflow.com/a/41577458/893432
I am getting fast queries (around 0.5 seconds) with a slow cpu, selecting 10 random rows in a 400K registers MySQL database non-cached 2Gb size. See here my code: Fast selection of random rows in MySQL
$time= microtime_float();
$sql='SELECT COUNT(*) FROM pages';
$rquery= BD_Ejecutar($sql);
list($num_records)=mysql_fetch_row($rquery);
mysql_free_result($rquery);
$sql="SELECT id FROM pages WHERE RAND()*$num_records<20
ORDER BY RAND() LIMIT 0,10";
$rquery= BD_Ejecutar($sql);
while(list($id)=mysql_fetch_row($rquery)){
if($id_in) $id_in.=",$id";
else $id_in="$id";
}
mysql_free_result($rquery);
$sql="SELECT id,url FROM pages WHERE id IN($id_in)";
$rquery= BD_Ejecutar($sql);
while(list($id,$url)=mysql_fetch_row($rquery)){
logger("$id, $url",1);
}
mysql_free_result($rquery);
$time= microtime_float()-$time;
logger("num_records=$num_records",1);
logger("$id_in",1);
logger("Time elapsed: <b>$time segundos</b>",1);
From book :
Choose a Random Row Using an Offset
Still another technique that avoids problems found in the preceding
alternatives is to count the rows in the data set and return a random
number between 0 and the count. Then use this number as an offset
when querying the data set
$rand = "SELECT ROUND(RAND() * (SELECT COUNT(*) FROM Bugs))";
$offset = $pdo->query($rand)->fetch(PDO::FETCH_ASSOC);
$sql = "SELECT * FROM Bugs LIMIT 1 OFFSET :offset";
$stmt = $pdo->prepare($sql);
$stmt->execute( $offset );
$rand_bug = $stmt->fetch();
Use this solution when you can’t assume contiguous key values and
you need to make sure each row has an even chance of being selected.
Its very simple and single line query.
SELECT * FROM Table_Name ORDER BY RAND() LIMIT 0,10;
Well if you have no gaps in your keys and they are all numeric you can calculate random numbers and select those lines. but this will probably not be the case.
So one solution would be the following:
SELECT * FROM table WHERE key >= FLOOR(RAND()*MAX(id)) LIMIT 1
which will basically ensure that you get a random number in the range of your keys and then you select the next best which is greater.
you have to do this 10 times.
however this is NOT really random because your keys will most likely not be distributed evenly.
It's really a big problem and not easy to solve fulfilling all the requirements, MySQL's rand() is the best you can get if you really want 10 random rows.
There is however another solution which is fast but also has a trade off when it comes to randomness, but may suit you better. Read about it here: How can i optimize MySQL's ORDER BY RAND() function?
Question is how random do you need it to be.
Can you explain a bit more so I can give you a good solution.
For example a company I worked with had a solution where they needed absolute randomness extremely fast. They ended up with pre-populating the database with random values that were selected descending and set to different random values afterwards again.
If you hardly ever update you could also fill an incrementing id so you have no gaps and just can calculate random keys before selecting... It depends on the use case!
How to select random rows from a table:
From here:
Select random rows in MySQL
A quick improvement over "table scan" is to use the index to pick up random ids.
SELECT *
FROM random, (
SELECT id AS sid
FROM random
ORDER BY RAND( )
LIMIT 10
) tmp
WHERE random.id = tmp.sid;
I improved the answer #Riedsio had. This is the most efficient query I can find on a large, uniformly distributed table with gaps (tested on getting 1000 random rows from a table that has > 2.6B rows).
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max := (SELECT MAX(id) FROM table)) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1)
Let me unpack what's going on.
#max := (SELECT MAX(id) FROM table)
I'm calculating and saving the max. For very large tables, there is a slight overhead for calculating MAX(id) each time you need a row
SELECT FLOOR(rand() * #max) + 1 as rand)
Gets a random id
SELECT id FROM table INNER JOIN (...) on id > rand LIMIT 1
This fills in the gaps. Basically if you randomly select a number in the gaps, it will just pick the next id. Assuming the gaps are uniformly distributed, this shouldn't be a problem.
Doing the union helps you fit everything into 1 query so you can avoid doing multiple queries. It also lets you save the overhead of calculating MAX(id). Depending on your application, this might matter a lot or very little.
Note that this gets only the ids and gets them in random order. If you want to do anything more advanced I recommend you do this:
SELECT t.id, t.name -- etc, etc
FROM table t
INNER JOIN (
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max := (SELECT MAX(id) FROM table)) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1)
) x ON x.id = t.id
ORDER BY t.id
All the best answers have been already posted (mainly those referencing the link http://jan.kneschke.de/projects/mysql/order-by-rand/).
I want to pinpoint another speed-up possibility - caching. Think of why you need to get random rows. Probably you want display some random post or random ad on a website. If you are getting 100 req/s, is it really needed that each visitor gets random rows? Usually it is completely fine to cache these X random rows for 1 second (or even 10 seconds). It doesn't matter if 100 unique visitors in the same 1 second get the same random posts, because the next second another 100 visitors will get different set of posts.
When using this caching you can use also some of the slower solution for getting the random data as it will be fetched from MySQL only once per second regardless of your req/s.
I've looked through all of the answers, and I don't think anyone mentions this possibility at all, and I'm not sure why.
If you want utmost simplicity and speed, at a minor cost, then to me it seems to make sense to store a random number against each row in the DB. Just create an extra column, random_number, and set it's default to RAND(). Create an index on this column.
Then when you want to retrieve a row generate a random number in your code (PHP, Perl, whatever) and compare that to the column.
SELECT FROM tbl WHERE random_number >= :random LIMIT 1
I guess although it's very neat for a single row, for ten rows like the OP asked you'd have to call it ten separate times (or come up with a clever tweak that escapes me immediately)
I needed a query to return a large number of random rows from a rather large table. This is what I came up with. First get the maximum record id:
SELECT MAX(id) FROM table_name;
Then substitute that value into:
SELECT * FROM table_name WHERE id > FLOOR(RAND() * max) LIMIT n;
Where max is the maximum record id in the table and n is the number of rows you want in your result set. The assumption is that there are no gaps in the record id's although I doubt it would affect the result if there were (haven't tried it though). I also created this stored procedure to be more generic; pass in the table name and number of rows to be returned. I'm running MySQL 5.5.38 on Windows 2008, 32GB, dual 3GHz E5450, and on a table with 17,361,264 rows it's fairly consistent at ~.03 sec / ~11 sec to return 1,000,000 rows. (times are from MySQL Workbench 6.1; you could also use CEIL instead of FLOOR in the 2nd select statement depending on your preference)
DELIMITER $$
USE [schema name] $$
DROP PROCEDURE IF EXISTS `random_rows` $$
CREATE PROCEDURE `random_rows`(IN tab_name VARCHAR(64), IN num_rows INT)
BEGIN
SET #t = CONCAT('SET #max=(SELECT MAX(id) FROM ',tab_name,')');
PREPARE stmt FROM #t;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
SET #t = CONCAT(
'SELECT * FROM ',
tab_name,
' WHERE id>FLOOR(RAND()*#max) LIMIT ',
num_rows);
PREPARE stmt FROM #t;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
END
$$
then
CALL [schema name].random_rows([table name], n);
Here is a game changer that may be helpfully for many;
I have a table with 200k rows, with sequential id's, I needed to pick N random rows, so I opt to generate random values based in the biggest ID in the table, I created this script to find out which is the fastest operation:
logTime();
query("SELECT COUNT(id) FROM tbl");
logTime();
query("SELECT MAX(id) FROM tbl");
logTime();
query("SELECT id FROM tbl ORDER BY id DESC LIMIT 1");
logTime();
The results are:
Count: 36.8418693542479 ms
Max: 0.241041183472 ms
Order: 0.216960906982 ms
Based in this results, order desc is the fastest operation to get the max id,
Here is my answer to the question:
SELECT GROUP_CONCAT(n SEPARATOR ',') g FROM (
SELECT FLOOR(RAND() * (
SELECT id FROM tbl ORDER BY id DESC LIMIT 1
)) n FROM tbl LIMIT 10) a
...
SELECT * FROM tbl WHERE id IN ($result);
FYI: To get 10 random rows from a 200k table, it took me 1.78 ms (including all the operations in the php side)
I used this http://jan.kneschke.de/projects/mysql/order-by-rand/ posted by Riedsio (i used the case of a stored procedure that returns one or more random values):
DROP TEMPORARY TABLE IF EXISTS rands;
CREATE TEMPORARY TABLE rands ( rand_id INT );
loop_me: LOOP
IF cnt < 1 THEN
LEAVE loop_me;
END IF;
INSERT INTO rands
SELECT r1.id
FROM random AS r1 JOIN
(SELECT (RAND() *
(SELECT MAX(id)
FROM random)) AS id)
AS r2
WHERE r1.id >= r2.id
ORDER BY r1.id ASC
LIMIT 1;
SET cnt = cnt - 1;
END LOOP loop_me;
In the article he solves the problem of gaps in ids causing not so random results by maintaining a table (using triggers, etc...see the article);
I'm solving the problem by adding another column to the table, populated with contiguous numbers, starting from 1 (edit: this column is added to the temporary table created by the subquery at runtime, doesn't affect your permanent table):
DROP TEMPORARY TABLE IF EXISTS rands;
CREATE TEMPORARY TABLE rands ( rand_id INT );
loop_me: LOOP
IF cnt < 1 THEN
LEAVE loop_me;
END IF;
SET #no_gaps_id := 0;
INSERT INTO rands
SELECT r1.id
FROM (SELECT id, #no_gaps_id := #no_gaps_id + 1 AS no_gaps_id FROM random) AS r1 JOIN
(SELECT (RAND() *
(SELECT COUNT(*)
FROM random)) AS id)
AS r2
WHERE r1.no_gaps_id >= r2.id
ORDER BY r1.no_gaps_id ASC
LIMIT 1;
SET cnt = cnt - 1;
END LOOP loop_me;
In the article i can see he went to great lengths to optimize the code; i have no ideea if/how much my changes impact the performance but works very well for me.
You can easily use a random offset with a limit
PREPARE stm from 'select * from table limit 10 offset ?';
SET #total = (select count(*) from table);
SET #_offset = FLOOR(RAND() * #total);
EXECUTE stm using #_offset;
You can also apply a where clause like so
PREPARE stm from 'select * from table where available=true limit 10 offset ?';
SET #total = (select count(*) from table where available=true);
SET #_offset = FLOOR(RAND() * #total);
EXECUTE stm using #_offset;
Tested on 600,000 rows (700MB) table query execution took ~0.016sec HDD drive.
EDIT: The offset might take a value close to the end of the table, which will result in the select statement returning less rows (or maybe only 1 row), to avoid this we can check the offset again after declaring it, like so
SET #rows_count = 10;
PREPARE stm from "select * from table where available=true limit ? offset ?";
SET #total = (select count(*) from table where available=true);
SET #_offset = FLOOR(RAND() * #total);
SET #_offset = (SELECT IF(#total-#_offset<#rows_count,#_offset-#rows_count,#_offset));
SET #_offset = (SELECT IF(#_offset<0,0,#_offset));
EXECUTE stm using #rows_count,#_offset;
I know it is not what you want, but the answer I will give you is what I use in production in a small website.
Depending on the quantity of times you access the random value, it is not worthy to use MySQL, just because you won't be able to cache the answer. We have a button there to access a random page, and a user could click in there several times per minute if he wants. This will cause a mass amount of MySQL usage and, at least for me, MySQL is the biggest problem to optimize.
I would go another approach, where you can store in cache the answer. Do one call to your MySQL:
SELECT min(id) as min, max(id) as max FROM your_table
With your min and max Id, you can, in your server, calculate a random number. In python:
random.randint(min, max)
Then, with your random number, you can get a random Id in your Table:
SELECT *
FROM your_table
WHERE id >= %s
ORDER BY id ASC
LIMIT 1
In this method you do two calls to your Database, but you can cache them and don't access the Database for a long period of time, enhancing performance. Note that this is not random if you have holes in your table. Having more than 1 row is easy since you can create the Id using python and do one request for each row, but since they are cached, it's ok.
If you have too many holes in your table, you can try the same approach, but now going for the total number of records:
SELECT COUNT(*) as total FROM your_table
Then in python you go:
random.randint(0, total)
And to fetch a random result you use the LIMIT like bellow:
SELECT *
FROM your_table
ORDER BY id ASC
LIMIT %s, 1
Notice it will get 1 value after X random rows. Even if you have holes in your table, it will be completely random, but it will cost more for your database.
If you want one random record (no matter if there are gapes between ids):
PREPARE stmt FROM 'SELECT * FROM `table_name` LIMIT 1 OFFSET ?';
SET #count = (SELECT
FLOOR(RAND() * COUNT(*))
FROM `table_name`);
EXECUTE stmt USING #count;
Source: https://www.warpconduit.net/2011/03/23/selecting-a-random-record-using-mysql-benchmark-results/#comment-1266
This is super fast and is 100% random even if you have gaps.
Count the number x of rows that you have available SELECT COUNT(*) as rows FROM TABLE
Pick 10 distinct random numbers a_1,a_2,...,a_10 between 0 and x
Query your rows like this: SELECT * FROM TABLE LIMIT 1 offset a_i for i=1,...,10
I found this hack in the book SQL Antipatterns from Bill Karwin.
The following should be fast, unbiased and independent of id column. However it does not guarantee that the number of rows returned will match the number of rows requested.
SELECT *
FROM t
WHERE RAND() < (SELECT 10 / COUNT(*) FROM t)
Explanation: assuming you want 10 rows out of 100 then each row has 1/10 probability of getting SELECTed which could be achieved by WHERE RAND() < 0.1. This approach does not guarantee 10 rows; but if the query is run enough times the average number of rows per execution will be around 10 and each row in the table will be selected evenly.
If you have just one Read-Request
Combine the answer of #redsio with a temp-table (600K is not that much):
DROP TEMPORARY TABLE IF EXISTS tmp_randorder;
CREATE TABLE tmp_randorder (id int(11) not null auto_increment primary key, data_id int(11));
INSERT INTO tmp_randorder (data_id) select id from datatable;
And then take a version of #redsios Answer:
SELECT dt.*
FROM
(SELECT (RAND() *
(SELECT MAX(id)
FROM tmp_randorder)) AS id)
AS rnd
INNER JOIN tmp_randorder rndo on rndo.id between rnd.id - 10 and rnd.id + 10
INNER JOIN datatable AS dt on dt.id = rndo.data_id
ORDER BY abs(rndo.id - rnd.id)
LIMIT 1;
If the table is big, you can sieve on the first part:
INSERT INTO tmp_randorder (data_id) select id from datatable where rand() < 0.01;
If you have many read-requests
Version: You could keep the table tmp_randorder persistent, call it datatable_idlist. Recreate that table in certain intervals (day, hour), since it also will get holes. If your table gets really big, you could also refill holes
select l.data_id as whole
from datatable_idlist l
left join datatable dt on dt.id = l.data_id
where dt.id is null;
Version: Give your Dataset a random_sortorder column either directly in datatable or in a persistent extra table datatable_sortorder. Index that column. Generate a Random-Value in your Application (I'll call it $rand).
select l.*
from datatable l
order by abs(random_sortorder - $rand) desc
limit 1;
This solution discriminates the 'edge rows' with the highest and the lowest random_sortorder, so rearrange them in intervals (once a day).
Another simple solution would be ranking the rows and fetch one of them randomly and with this solution you won't need to have any 'Id' based column in the table.
SELECT d.* FROM (
SELECT t.*, #rownum := #rownum + 1 AS rank
FROM mytable AS t,
(SELECT #rownum := 0) AS r,
(SELECT #cnt := (SELECT RAND() * (SELECT COUNT(*) FROM mytable))) AS n
) d WHERE rank >= #cnt LIMIT 10;
You can change the limit value as per your need to access as many rows as you want but that would mostly be consecutive values.
However, if you don't want consecutive random values then you can fetch a bigger sample and select randomly from it. something like ...
SELECT * FROM (
SELECT d.* FROM (
SELECT c.*, #rownum := #rownum + 1 AS rank
FROM buildbrain.`commits` AS c,
(SELECT #rownum := 0) AS r,
(SELECT #cnt := (SELECT RAND() * (SELECT COUNT(*) FROM buildbrain.`commits`))) AS rnd
) d
WHERE rank >= #cnt LIMIT 10000
) t ORDER BY RAND() LIMIT 10;
One way that i find pretty good if there's an autogenerated id is to use the modulo operator '%'. For Example, if you need 10,000 random records out 70,000, you could simplify this by saying you need 1 out of every 7 rows. This can be simplified in this query:
SELECT * FROM
table
WHERE
id %
FLOOR(
(SELECT count(1) FROM table)
/ 10000
) = 0;
If the result of dividing target rows by total available is not an integer, you will have some extra rows than what you asked for, so you should add a LIMIT clause to help you trim the result set like this:
SELECT * FROM
table
WHERE
id %
FLOOR(
(SELECT count(1) FROM table)
/ 10000
) = 0
LIMIT 10000;
This does require a full scan, but it is faster than ORDER BY RAND, and in my opinion simpler to understand than other options mentioned in this thread. Also if the system that writes to the DB creates sets of rows in batches you might not get such a random result as you where expecting.
I think here is a simple and yet faster way, I tested it on the live server in comparison with a few above answer and it was faster.
SELECT * FROM `table_name` WHERE id >= (SELECT FLOOR( MAX(id) * RAND()) FROM `table_name` ) ORDER BY id LIMIT 30;
//Took 0.0014secs against a table of 130 rows
SELECT * FROM `table_name` WHERE 1 ORDER BY RAND() LIMIT 30
//Took 0.0042secs against a table of 130 rows
SELECT name
FROM random AS r1 JOIN
(SELECT CEIL(RAND() *
(SELECT MAX(id)
FROM random)) AS id)
AS r2
WHERE r1.id >= r2.id
ORDER BY r1.id ASC
LIMIT 30
//Took 0.0040secs against a table of 130 rows
SELECT
*
FROM
table_with_600k_rows
WHERE
RAND( )
ORDER BY
id DESC
LIMIT 30;
id is the primary key, sorted by id,
EXPLAIN table_with_600k_rows, find that row does not scan the entire table
I Use this query:
select floor(RAND() * (SELECT MAX(key) FROM table)) from table limit 10
query time:0.016s
This is how I do it:
select *
from table_with_600k_rows
where rand() < 10/600000
limit 10
I like it because does not require other tables, it is simple to write, and it is very fast to execute.
Use the below simple query to get random data from a table.
SELECT user_firstname ,
COUNT(DISTINCT usr_fk_id) cnt
FROM userdetails
GROUP BY usr_fk_id
ORDER BY cnt ASC
LIMIT 10
I guess this is the best possible way..
SELECT id, id * RAND( ) AS random_no, first_name, last_name
FROM user
ORDER BY random_no

Calculate ranking in mysql using update query

We have calculated ranking using following query.
set #rank = 0;
Update rank_table
set position= (select #rank := #rank + 1)
order by points DESC, points_new DESC, points_old DESC;
And it calculates ranking in sequence.
eg.
I want that id's having same criteria should assign same ranking.
so let say,
here id 1 and 2 have same criteria then should have position=1 and then id 3 should have position=3.
Not like current flow.
Currently -> Id 1:position 1 , Id 2:position 2 , Id 3:position 3
but as Id 1 and 2 have same data it should be..
Id 1:position 1 , Id 2:position 1 , Id 3:position 3
Thanks for your help.
What you want is technically rank() rather than row_number(). This is something of a pain, but possible:
set #rn := 0;
set #rank := 0;
set #p := -1;
Update rank_table
set position = if(#rn := #rn + 1,
if(#p = points, #rank,
if(#p := points, #rank := #rn, #rank := #rn)
),
NULL -- never should happen
)
order by points DESC, points_new DESC, points_old DESC;
This is tricky because you need to calculate both the rank and the row number -- the rank stays the same and then it must "jump" to the row number.

Display dynamic ranges from a database table and count the rows within each range

I have database table like this:
I want to display different 5-year age ranges and the counts of students that are in that range like below:
Here, the lowest age is 10 so we first calculate the range 10-15. There are 5 students within that range. For the second range, we need to find the age>15 which is 18. So, the second range is from 18-23, and so on. I would appreciate any help where the range is automatically calculated and count the data within that range.
You can use a condition inside of a SUM() statement to get a count where that condition holds. I would count the conditions where the age is BETWEEN() the necessary range. Try this:
SELECT
SUM(age BETWEEN 10 AND 15) AS '10-15',
SUM(age BETWEEN 18 AND 23) AS '18-23',
SUM(age BETWEEN 26 AND 31) AS '26-31',
SUM(age BETWEEN 34 AND 39) AS '34-39'
FROM myTable;
This will only return one row, but it will have everything you need. Here is an SQL Fiddle example.
EDIT I misunderstood your question to automatically calculate the various ranges. I will leave my previous answer here because it may be beneficial to future readers looking for hard coded ranges. To do this, you'll have to set up a variable. I made a sort of running total type approach to get the groups. I started by setting #a to 0 before the query. Then, I needed to get two values:
The minimum age from the table where age > #a
5 greater than that variable.
I did this by changing the value of #a as necessary:
#a := (SELECT MIN(age) FROM myTable WHERE age >= #a)
#a := #a + 5
Then, I included these in a CONCAT() block and casted these values as chars in order to get the groups that I needed. It may look complicated, so I hope I explained the concept:
SELECT CONCAT
(CAST(#a := (SELECT MIN(age) FROM myTable WHERE age > #a) AS CHAR),
' - ',
CAST((#a := #a + 5) AS CHAR)) AS ageRange
FROM myTable
WHERE #a <= (SELECT MAX(age) FROM myTable);
Doing this gave me four rows, each with the age ranges you expect. I had to add the where clause because otherwise I would get one result row for each row in the table, which would give us several null rows.
Last, I included a subquery to get the count of students whose age is within the necessary range. Note that the first part changes the values of #a, so instead of checking from #a to #a + 5, I check from #a-5 to #a. Here is the final query:
SET #a = 0;
SELECT CONCAT(CAST(#a := (SELECT MIN(age) FROM myTable WHERE age > #a) AS CHAR), ' - ', CAST((#a := #a + 5) AS CHAR)) AS ageRange,
(SELECT COUNT(*) FROM myTable WHERE age BETWEEN #a - 5 AND #a) AS numStudents
FROM myTable
WHERE #a <= (SELECT MAX(age) FROM myTable)
GROUP BY ageRange;
It worked beautifully in SQL Fiddle. Completely dynamic and returns the various groups of 5 without any prior knowledge of which groups to take.
SELECT
CASE
WHEN age>=10 AND age<=15 THEN '10-15'
WHEN age>=18 AND age<=23 THEN '18-23'
WHEN age>=26 AND age<=31 THEN '26-31'
WHEN age>=34 AND age<=39 THEN '34-39'
ELSE 'OTHER'
END
AS age_range,
COUNT(*) as number_of_students
FROM table
GROUP BY age_range

Mysql group by where delta between records X

I need help to write MySQL query.
I have table full of logs where one of the column is unix timestamp.
I want to group (GROUP BY) those records so that events that were made in close range time (i.e. 5 sec) between each of them are in one group.
For example:
Table:
timestamp
----------
1429016966
1429016964
1429016963
1429016960
1429016958
1429016957
1429016950
1429016949
1429016943
1429016941
1429016940
1429016938
Become to groups like that:
GROUP_CONCAT(timestamp) | COUNT(*)
-----------------------------------------------------------------------------
1429016966,1429016964,1429016963,1429016960,1429016958,1429016957 | 6
1429016950,1429016949 | 2
1429016943,1429016941,1429016940,1429016938 | 4
Of course I can work with the data array afterwards in php, but I think that mysql would do it faster.
I started by using a variable to get the position of each row, where 1 is the highest time column and ending with the lowest, like this:
SET #a := 0;
SELECT timeCol, #a := #a + 1 AS position
FROM myTable
ORDER BY timeCol DESC;
For simplicity, we will call this positionsTable so that the rest of the query will be more readable. Once I created that table, I used a 'time_group' variable that checked if a previous row was within the last 5 seconds. If it was, we keep the same time_group. It sounds ugly, and looks kind of ugly, but it's like this:
SELECT m.timeCol, m.position,
CASE WHEN (SELECT p.timeCol FROM positionsTable p WHERE p.position = m.position - 1) <= m.timeCol + 5
THEN #time_group
ELSE #time_group := #time_group + 1 END AS timeGroup
FROM positionsTable m;
And then ultimately, using that as a subquery, you can group them:
SELECT GROUP_CONCAT(timeCol), COUNT(*)
FROM(
SELECT m.timeCol, m.position,
CASE WHEN (SELECT p.timeCol FROM positionsTable p WHERE p.position = m.position - 1) <= m.timeCol + 5
THEN #time_group
ELSE #time_group := #time_group + 1 END AS timeGroup
FROM positionsTable m) tmp
GROUP BY timeGroup;
Here is an SQL Fiddle example.
http://sqlfiddle.com/#!9/37d88/20
SELECT GROUP_CONCAT(t1.t) as `time`,
COUNT(*)
FROM (SELECT *
FROM table1
ORDER BY t) as t1
GROUP BY CASE WHEN (#start+5)>=t THEN #start
ELSE #start:=t END

MySQL return every nth record from selected range [duplicate]

I have a series of values in a database that I need to pull to create a line chart. Because i dont require high resolution I would like to resample the data by selecting every 5th row from the database.
SELECT *
FROM (
SELECT
#row := #row +1 AS rownum, [column name]
FROM (
SELECT #row :=0) r, [table name]
) ranked
WHERE rownum % [n] = 1
You could try mod 5 to get rows where the ID is multiple of 5. (Assuming you have some sort of ID column that's sequential.)
select * from table where table.id mod 5 = 0;
Since you said you're using MySQL, you can use user variables to create a continuous row numbering. You do have to put that in a derived table (subquery) though.
SET #x := 0;
SELECT *
FROM (SELECT (#x:=#x+1) AS x, mt.* FROM mytable mt ORDER BY RAND()) t
WHERE x MOD 5 = 0;
I added ORDER BY RAND() to get a pseudorandom sampling, instead of allowing every fifth row of the unordered table to be in the sample every time.
An anonymous user tried to edit this to change x MOD 5 = 0 to x MOD 5 = 1. I have changed it back to my original.
For the record, one can use any value between 0 and 4 in that condition, and there's no reason to prefer one value over another.
SET #a = 0;
SELECT * FROM t where (#a := #a + 1) % 2 = 0;
I had been looking for something like this. The answer of Taylor and Bill led me to improve upon their ideas.
table data1 has fields read_date, value
we want to select every 2d record from a query limited by a read_date range
the name of the derived table is arbitrary and here is called DT
query:
SET #row := 0;
SELECT * FROM ( SELECT #row := #row +1 AS rownum, read_date, value FROM data1
WHERE read_date>= 1279771200 AND read_date <= 1281844740 ) as DT WHERE MOD(rownum,2)=0
If you're using MariaDB 10.2, MySQL 8 or later, you can do this more efficiency, and I think more clearly, using common table expressions and window functions.
WITH ordering AS (
SELECT ROW_NUMBER() OVER (ORDER BY name) AS n, example.*
FROM example ORDER BY name
)
SELECT * FROM ordering WHERE MOD(n, 5) = 0;
Conceptually, this creates a temporary table with the contents of the example table ordered by the name field, adds an additional field called n which is the row number, and then fetches only those rows with numbers which are exactly divisible by 5, i.e. every 5th row. In practice, the database engine is often able to optimise this better than that. But even if it doesn't optimise it any further, I think it's clearer than using user variables iteratively as you had to in earlier versions of MySQL.
You can use this query,
set #n=2; <!-- nth row -->
select * from (SELECT t.*,
#rowid := #rowid + 1 AS ID
FROM TABLE t,
(SELECT #rowid := 0) dummy) A where A.ID mod #n = 0;
or you can replace n with your nth value
SELECT *
FROM (
SELECT #row := #row +1 AS rownum, posts.*
FROM (
SELECT #row :=0) r, posts
) ranked
WHERE rownum %3 = 1
where posts is my table.
If you don't require the row number in the result set you can simplify the query.
SELECT
[column name]
FROM
(SELECT #row:=0) temp,
[table name]
WHERE (#row:=#row + 1) % [n] = 1
Replace the following placeholders:
Replace [column name] with a list of columns you need to fetch.
Replace [table name] with the name of your table.
Replace [n] with a number. e.g. if you need every 5th row, replace it with 5

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