XML malformed via MySQL multi-query - php

Question

I need to use multiple queries and send them out as well formed xml for as3 purposes.
When I use only one query everything works fine.
Problem starts when multi-query operates.
Right now when //XML header is hidden I get a structure printed on screen and it looks good.
But when header goes enabled, nothing works!
Please take a look at my code:
<?php
$dbHost = "localhost";
$dbUser = "root";
$dbPass = "";
$dbName = "test";
$dbTable = "pizzaroma";
$mysqli = mysqli_connect($dbHost, $dbUser, $dbPass, $dbName);
if ($mysqli->connect_errno)
echo "la conection ha fallado: ".$mysqli->connect_errno;
$query = "SELECT * FROM ".$dbTable." WHERE cat='pizza' AND act='1' ORDER BY ID ASC; ";
$query .= "SELECT * FROM ".$dbTable." WHERE cat='pasta' AND act='1' ORDER BY ID ASC; ";
if ($mysqli->multi_query($query)) {
// header("Content-type: text/xml");
echo "<?xml version='1.0' encoding='UTF-8'?>";
echo "<pics>";
do {
echo "<theme name='temporaly'>";
if ($result = $mysqli->store_result()) {
while ($row = $result->fetch_assoc()) {
echo "<pic name='".$row['NAME']."' desc='".$row['DESCES']."' price='".$row['PRICE']."'/>";
echo "</pic>";
}
$result->free();
}
echo "</theme>";
if ($mysqli->more_results()) {
}
}
while ($mysqli->next_result());
echo "</pics>";
}
$mysqli->close();
?>

Answer 1

earlier i were using "echo",.. now instead ive put "printf" there,.. but only some lines, i am not sure if that was the reason.. but now works. it was throwing me the
"Strict Standards: mysqli_next_result(): There is no next result set. Please, call mysqli_more_results()/mysqli::more_results() to check whether to call this function/method" so looking for help i have found this line there :
do{} while(mysqli_more_results($db) && mysqli_next_result($db));
that solved the problem for xml error.
<?php
$dbHost = "localhost";
$dbUser = "root";
$dbPass = "";
$dbName = "test";
$dbTable = "pizzaroma";
$mysqli = mysqli_connect($dbHost, $dbUser, $dbPass, $dbName);
if ($mysqli->connect_errno)
echo "la conection ha fallado: ".$mysqli->connect_errno;
$query = "SELECT * FROM ".$dbTable." WHERE cat='pizza' AND act='1' ORDER BY ID ASC; ";
$query .= "SELECT * FROM ".$dbTable." WHERE cat='pasta' AND act='1' ORDER BY ID ASC; ";
$query .= "SELECT * FROM ".$dbTable." WHERE cat='carne' AND act='1' ORDER BY ID ASC; ";
if ($mysqli->multi_query($query)) {
header("Content-type: text/xml");
printf( "<?xml version='1.0' encoding='UTF-8'?>");
printf( "<pics>");
do {
printf( "<theme name='temporaly'>");
if ($result = $mysqli->store_result()) {
while ($row = $result->fetch_assoc()) {
echo "<pic name='".$row['NAME']."'/>";
}
$result->free();
}
echo "</theme>";
}
while (mysqli_more_results($mysqli) && mysqli_next_result($mysqli));
echo "</pics>";
}
$mysqli->close();
?>
later on i´ve had to serialize the xml output it was easy :D
>> $i=1; and ... do {printf( "<theme name='".$i++."'>");
but now ,.. how do I associate output serialIDs to elements from array that contains category names. something like...
if name="1" then name="firtsArrayChild"
any idea?
but i think that is another song for another question out there! thanks