PHP count function - php

Question

I have to count the numbers which is divisible by 5.
Here is my code,
$num = array(4, 25, 60, 7, 8);
foreach ($num as $numbers) {
if (($numbers % 5) == 0) {
echo count($numbers);
}
}
Output of above program is 11. But output should be 2. Please give me solution. Thanks in advance.

Answer 1

$nums = array(4, 25, 60, 7, 8);
To only count:
-Basic:
$count = 0;
foreach ($nums as $num) {
if ( $num % 5 == 0 ) $count++;
}
-Playing with types:
$count = 0;
foreach ($nums as $num) {
$count += !($num % 5);
}
$num % 5 returns an integer, !($num % 5) returns a boolean but since it is used as operand with the + operator, false and true act like 0 and 1.
-Functional version using array_reduce:
$count = array_reduce($nums, function($c, $i) { return $c + !($i % 5); });
To filter items, use the well named array_filter:
$result = array_filter($nums, function ($i) { return $i % 5 == 0; });
and count the number of items after if you want:
$count = count($result);

Answer 2

You can use this way also,
function divisibleby5($var){
return $var % 5 == 0;
}
$num = array(4, 25, 60, 7, 8);
echo count(array_filter($num,'divisibleby5');

Answer 3

I think you need to do something more like the following perhaps.
$num = array(4, 25, 60, 7, 8);
$numbers=array();
foreach( $num as $number ) {
if( $number % 5 == 0 ) $numbers[]=$number;
}
echo count( $numbers );
or alternatively using array_walk and a custom callback function
function mod5($item,$key,$arr){
if($item %5==0)$arr[]=$item;
}
array_walk( $num,'mod5',&$numbers);
echo count($numbers);

Answer 4

Here Output is 1 and 1. Not 11 (eleven)
You can try it
echo count($numbers)."<br>";
your solution:
Output will be 2 if you increment count variable value after enter the if condition
<?php
$num = array(4, 25, 60, 7, 8);
$count = 0;
foreach($num as $numbers) {
if (($numbers % 5) == 0) {
$count++;
}
}
echo $count;
?>

Answer 5

in the event you want to print the numbers also
$a=array(); //initialized empty array
$num = array(4, 25, 60, 7, 8);
foreach($num as $numbers){
if(($numbers % 5) == 0){
$a=$numbers; //store values into the array
}
}
echo count($a); // echo the count of the array
echo implode('<br>',$a);
OR if you just need the count
$a=0; //initalize $a
$num = array(4, 25, 60, 7, 8);
foreach($num as $numbers){
if(($numbers % 5) == 0){
$a++; //increment a
}
}
echo $a