Problems select mysqli - php

I am trying to make a select to my table 'detail' where I have 4 registers with id 0,1,2,3 but this only returns the ids 1,2,3. What will be?
$sqls = "
SELECT *
FROM details
WHERE ped = 4500088849";
$results = mysqli_query($conn, $sqls);
while($row = mysqli_fetch_array($results)) {
print $row['ebelp'];
}
My table

Your query is filtering for rows where the column ped contains the value 11.
Using the mysql command line perform the query
SELECT ped, ebelp FROM details;
And review the value in the ped column for register 0, it sounds like it has a value other then 11.
Using the query SELECT * FROM details will get you all rows with all columns from the details table.

Related

Select Data From Multiple MySQL Tables

Im searching for a function in MySQL in order to Select rows from multiple tables that have a similar name. For example: Proyect_1, Proyect_2, Proyect_3
All of the tables have the same column names, the only difference between the tables is the table name. It starts with the prefix 'proyect'. The issue is that the program doesn´t know how many 'proyect' tables there are, so i can´t make a list of them and select data like always
I need something like this:
SELECT mydata FROM TABLES LIKE 'Proyect_%';
Any ideas? Thanks!
To get all tables with a common prefix
SHOW TABLES LIKE 'Proyect_%';
This will return rows of tables that matched the prefix. Example:
Proyect_1
Proyect_2
Proyect_3
In PHP you can create a UNION query that will pick up the tables returned by the above query,
$sql = "SHOW TABLES LIKE 'Proyect_%'";
$result = $conn->query($sql);
$dataQuery = array();
$query = "";
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_array(MYSQLI_NUM)) {
$dataQuery[] = "SELECT * FROM {$row[0]}";
}
$query = implode(' UNION ', $dataQuery);
}
echo $query;
if you want to search for all tables with name like Proyect then you can get from MySQL information schema.
SELECT * FROM information_schema.tables
From here you can find table by table name

MySQL sequentially split results based on 2 columns

I'm displaying results from a MySQL table based on matching values in one column. I then need to separate these results based on the data in another column, when that data is different.
Here's a cut down example of the table I'm drawing data from:
customer_id customer_timestamp customer_order customer_email
27 2019-02-23 02:52:41 ABC123456789 admin#admin.com
28 2019-02-23 02:52:41 ABC123456789 admin#admin.com
32 2019-02-26 05:51:41 CBA987654321 admin#admin.com
From the above, I need to return all rows with the same customer_email then separate them by customer_order number.
Can this be achieved through a select statement alone and if so how?
Here's an example of a select statement I'm using which returns all rows with the same email;
$select = "select * from mytable where customer_email='admin#admin.com'";
The data I'm getting from the query is being fetched in an array so I need the array to generate a new loop based on the customer_order column.
I figured it out, might look a bit hacky but it works. I rolled back the idea of initially displaying any order data, now it requires user interaction to select a grouped order number to display details from that specific order.
Code below;
// Retrieve order number/s
$select_order = "select * from mytable where customer_email='admin#admin.com' group by customer_order";
$connect_order = mysqli_query($con, $select_order);
while ($row_order=mysqli_fetch_array($connect_order)) {
$customer_order = $row_order['customer_order'];
echo "
<form method='post'>
<input type='submit' value='$customer_order' name='order_current[]'>
</form>
";
}
// Make each grouped order number a separate query
if (isset($_POST['order_current'])) {
$order_all = $_POST['order_current'];
foreach ($order_all as $order_post) {
// Retrieve selected order details
$select_order = "select * from mytable where customer_email='admin#admin.coml' and customer_order='$order_post'";
$connect_order = mysqli_query($con, $select_order);
while ($row_order=mysqli_fetch_array($connect_order)) {
$name = $row_order['customer_name'];
$amount = $row_order['customer_amount'];
// Display selected order details
echo "
$name<br/>
$amount<br/>
";
}
}
}

Check which columns were modified in an UPDATE query

When we update a MySQL record with php, we can check if it has effect using:
$mysqli->affected_rows;
But how do I check which column has been modified?
Example, in my table have the columns: id / name / age
In a record we have the data: 1 / Woton / 18
If I send an: UPDATE mytable SET name = 'Woton', age = '20' WHERE id = '1'
Only the age field has changed. How can I determine this?
You cannot directly get the updated columns from the query result.
It can be get from some php query. Firstly we will have to select the row from database which we are going to update in a array variable. Than run the update query for the same row.
Lastly get the same row from database from select query in the new array variable.
Finally we get two arrays.
We can get the updated column with the array_diff_assoc php function.
See the below code for the same.
$sql = "SELECT * from mytable where id=1 limit 1";
$prev = mysqli_fetch_assoc(mysqli_query($conn, $sql));
//Get the column data in the array. Before update.
$sql = "UPDATE mytable SET name = 'Woton', age = '20' WHERE id = '1'";
$conn->query($sql);
// Update data
$sql = "SELECT * from mytable where id=1 limit 1";
$updated = mysqli_fetch_assoc(mysqli_query($conn, $sql));
// Again run the select command to get updated data.
$UpdatedColumns=array_diff_assoc($updated,$prev);
In a different note: If QueryLog has been enabled in the DB then you (or your script in PHP or Python or any) can easily see/read which part of the content has been updated and even you can monitor the DB.
The good news is, even you can target which table, which query etc.

SUM values of specific column from all tables LIKE table_%

I need help to create an SQL query in order to SUM the values of specific column from all tables LIKE table_% as the tables will grow over time and this must cater for new table names based on the format below
Scheme Name: database_01
Table Names: tb_data_'YEAR'_'MONTH'
YEAR and MONTH are both values which range from all 12 months and years from 2011 to 2018.
Each Table contains a column called TOTAL_VALUE. I have a php script that triggers an SQL query to pull data from the database.
I would like to SUM the total of each tables TOTAL_VALUE column and save the value for my script below to push the array.
$sql = "SELECT TOTAL_VALUES FROM tb_data_2017_october";
$result = mysqli_query($conn, $sql);
$data = array(); while($enr = mysqli_fetch_assoc($result)){
$a = array($enr['TOTAL_VALUES']);
foreach ($a as $as){
echo "'".$as."', ";}
array_push($data, $as); }
I have been trying to alter the SQL with options such as:
SELECT id FROM table1
UNION
SELECT id FROM table2
UNION
SELECT id FROM table3
UNION
SELECT id FROM table4
However i need to cater for the ability to check all tables that are like tb_data_%
See this question for information about getting the list of tables: Get table names using SELECT statement in MySQL
You can get the list of tables in one query result, and then query each table. I'll rework your code slightly to give an example:
// Get the tables
$tables_sql = "SELECT table_name
FROM information_schema.tables
WHERE table_schema='<your DB>'
AND table_name LIKE 'tb_data%'";
$tables = mysqli_query($conn, $sql);
// Iterate over the tables
while($table = mysqli_fetch_assoc($tables)){
{
/*
* Your code
*/
// This query assumes that you can trust your table names not to to an SQL injection
$sql = "SELECT TOTAL_VALUES FROM " . $table['table_name'];
$result = mysqli_query($conn, $sql);
$data = array(); while($enr = mysqli_fetch_assoc($result)){
$a = array($enr['TOTAL_VALUES']);
foreach ($a as $as){
echo "'".$as."', ";
array_push($data, $as); }
}
You can do whatever you need once your have your list of tables. You can build one big union query (which would be more efficient than querying each table individually), or feed the tables to the MERGE engine, as in barmar's answer
Use the MERGE storage engine to create a virtual table that combines all the monthly tables.
CREATE TABLE tb_all_data (
...
) ENGINE=MERGE UNION=(tb_data_2017_october, tb_data_2017_november, ...);
List all the tables in the UNION= list, and update it whenever you create a new table.
Then you can just query from tb_all_data.
Try this- it will loop through all the tables with the pattern you want and create sums for you:
declare #table table (rowid int identity, name varchar(max))
insert #table
select name from sys.tables where name like '%yourname%'
declare #holding table (name varchar(max), sumvalue int)
declare #iterator int = 1
declare #tablename varchar(max)
while #iterator<=(select max(rowid) from #table)
begin
select #tablename=name from #table where rowid=#iterator
insert #holding
exec('select '+#tablename+' sum(TOTAL_VALUE)TOTAL_VALUE from '+#tablename+' group by +'+#tablename+'')
set #iterator=#iterator+1
end
select * from #holding

SELECT a few rows out of MYSQL

I need to select category ids from my sql database.
I have a variable $product_id and for each product id there are three rows in a table that i need to select using PHP.
If I do "SELECT * FROM table_name WHERE product_id='$prodid'"; I only get the one on the top.
How can I select all three category_ids which contain the same product_id?
I suppose you are using PHP's mysql functions, is this correct? I am figuring that your query is actually returning all three rows but you aren't fetching all of them.
$sql = "SELECT * FROM table_name WHERE product_id='$prodid'";
$r = mysql_query($sql, $conn); //where $conn is your connection
$x = mysql_fetch_SOMETHING($r); //where something is array, assoc, object, etc.
The fetch function gives only one row at a time. You say you need three so it needs to be executed three times.
$x[0] = mysql_fetch_assoc($r);
$x[1] = mysql_fetch_assoc($r);
$x[2] = mysql_fetch_assoc($r);
OR this would be better
while($curRow = mysql_fetch_assoc($r)) //this returns false when its out of rows, returns false
{
$categoryIds[] = $curRow['category_id'];
}
If this doesn't do it then your query is actually returning only one row and we need to see your tables/fields and maybe sample data.
SQL seems to be correct, but Why do you store product_id in categories table? if it's one-to-many relation it would be better to store only category_id in products table.
The SQL query is correct for what you want to do. It will select all the records in table_name with the field product_id = $prodid (not only 1 or 3 but any that matches the variable)
To select a few records you should use the LIMIT keyword
You should look inside your table structure and the variable $prodid to find problems.

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