How to pas array in loop in php? - php

Question

I am facing the problem is that I want to display all image by using array and loop,it is not showing all image ,it does show only one image.Here is my code
if($objResult['Image_Type'] == '01') {
$img11 = array($objResult['Image_Name']);
for ($i=0; $i < count($img11[$i]); $i++) {
$im_mouths = array($img11[$i]);
}
}
here is in the database to extract out all image
the out put is showing only one image by using this code
<? echo $im_mouths[0].'11111'.'<br>';?>
<? echo $im_mouths[1].'222222'.'<br>';?>
<? echo $im_mouths[2].'333333'.'<br>';?>
I am not sure I'm doing correctly or not ,help me out this problem.
Thanks :)

Answer 1

It's only showing one image because you're re-writing $im_mouths each time you loop. You should change your loop to do the following:
$im_mouths = array();
if($objResult['Image_Type'] == '01') {
$img11 = array($objResult['Image_Name']);
for ($i=0; $i < count($img11[$i]); $i++) {
$im_mouths[] = array($img11[$i]);
}
}
We initialize $im_mouths as an array, then add each element to the array as an element: $im_mouths[] = ....

Answer 2

You need to simplify your code a bit.
Assuming you have a outer loop for retrieving data from database:
$im_mouths = array();
while ($objResult = $res->fetch()) {
if($objResult['Image_Type'] == '01') {
$im_mouths[] = $objResult['Image_Name'];
}
}
Now you have $im_mouths array of elements of image names, as many as you have in database. So as you see you don't need unnecessary inner for loop
Finally to see what you have in your $im_mouths array, you can print_r it:
print_r($im_mouths);

Answer 3

In your example, the variable $im_mouths should contain only the last image ( that is, 20140923jaobangsaen01.png ). Because you are using simple variable to store the image, so that the variable may contain last image while the program flow comes out from the for loop. So that the output of your example is correct. If you want to show each images means, you should use array variable to store all the images and display back to the required place. Rearrange the code like following,
$im_mouths = array();
if($objResult['Image_Type'] == '01') {
$img11 = array($objResult['Image_Name']);
for ($i=0; $i < count($img11[$i]); $i++) {
$im_mouths[] = array($img11[$i]);
}
}
Hope it will work fine for you.
Use can use foreach to display the images instead of using echo for each image.
$num = 1111; //if required
foreach ( $im_mouths as $value ) {
echo $value.$num;
$num += 1111;
}