for loop - print values in order - PHP [closed] - php

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I need to print the below statement.
Thanks for updating your PH_NUMBER, ADDRESS, OFFICE NUMBER and EMAIL.
Where PH_NUMBER, ADDRESS, OFFICE_NUMBER and EMAIL are variables.
For example, if value is empty for variable "OFFICE_NUMBER" the sentence should be like below:
Thanks for updating your PH_NUMBER, ADDRESS and EMAIL.
For example, if value is empty for variable "EMAIL" the sentence should be like below:
Thanks for updating your PH_NUMBER, ADDRESS and OFFICE NUMBER.
$a = "Address";
$b = "Mobile";
$c = "email";
$array = array($a, $b, $c);
$length = count($array);
for ($i = 0; $i < $length; $i++) {
$total = $array[$i];
}
echo "Thanks for udpating " . $total ;
How can this be done ?
Any suggestions would be helpful.

Answer 1

You don't need to use a loop.
<?php
/* Collect all parameters to the array */
$variables = [
'PH_NUMBER',
'ADDRESS',
'EMAIL',
'OFFICE_NUMBER',
];
/* Sorting the array if need */
/* Pop the element off the end of array */
$variables = array_filter($variables);
$count = count($variables);
$lastVariable = array_pop($variables);
if($count > 1) {
printf('Thanks for updating your %s and %s', implode(', ', $variables), $lastVariable);
}elseif($count === 1){
printf('Thanks for updating your %s', $lastVariable);
}else{
print 'Nothing for update';
}
?>
Update: Small improvement in order to catch cases with only 1 variable and empty array (nothing for update).