Use error outside catch block - php

Question

Let's work with an example like this:
try {
if( $var == false ) {
throw new Exception('Fail');
}
} catch (Exception $e) {
$error = $e->getMessage();
}
Is there any way i can use $error outside the catch block?
If i try to print it outside,it shows nothing , so i'm sure i'm doing this wrong. Any help would be apreciated.
EDIT: This is my exact situation of the code click
I need to use $error , in another piece of code , outside of the class

Answer 1

Actually you are returning the error message, if you remove the return false statement, and try to print outside the loop it will print.
you can do that in 2 way:
Option1:
try {
if( $var == false ){
throw new Exception('Fail');
}
} catch (Exception $e){
$error = $e->getMessage();
// return false;
}
print_r($error);
Option 2:
try {
if( $var == false ){
throw new Exception('Fail');
}
} catch (Exception $e){
return $error = $e->getMessage();
}

Answer 2

This will return true if no error happens. Else it will return the error.
$error = false;
try {
if( $var == false ){
throw new Exception('Fail');
}
} catch (Exception $e){
$error = $e->getMessage();
}
return $error;
It depends on your implementation whether to return true or false.

Answer 3

You should not
The $error is declard inside the catch.
You your function throws a Exception don't use try cactch. just throw the Exception
Your function should return just one type;
If it returns boolean, return aways boolean
Maybe if you need to print the error, print it inside the catch