only can insertes last row data of table into session - php

Question

Here is my code
<?php
$count = 1;
$sql = "SELECT * FROM `scheduledata`
WHERE `departdate` = '$departdatephp'
AND `orginplace_id` = '$orginplacephp'
AND `desplace_id` = '$desplacephp' ";
$result = mysqli_query($conn, $sql);
while($row = mysqli_fetch_assoc($result))
{
?>
<tr>
<th><?php echo $count;?></th>
<th><?php echo $row["departtime"];?><input type="hidden" name="departtime" value="<?php echo $row['departtime'];?>" method="post"></th>
<th><?php echo $row["returntime"];?><input type="hidden" name="returntime" value="<?php echo $row['returntime'];?>" method="post"></th>
<th><?php echo $row["adultprice"]; ?>MYR<input type="hidden" name="adultprice" value="<?php echo $row['adultprice'];?>" method="post"></th>
<th><?php echo $row['schedule_id'];?><input type="hidden" name="scheduleid" value="<?php echo $row['schedule_id'];?>" method="post"></th>
<th><?php echo $row['flight_id'];?><input type="hidden" name="flightid" value="<?php echo $row['flight_id'];?>" method="post"></th>
<th><button type="submit" class="submit-button" method="post" name="departbtn[]">booking</button></th>
<?php
$count = $count+1;}
?>
</tr>
Lest says i had 3 choice of booking like this
3 booking button
Here is my output code
<?php
if(isset($_POST['departbtn']))
{
$departtimephp = $_POST['departtime'];
$returntimephp = $_POST['returntime'];
$price = $_POST['adultprice'];
$scheduleid = $_POST['scheduleid'];
$flightid = $_POST['flightid'];
$_SESSION['departtime'] = $departtimephp ;
$_SESSION['returntime'] = $returntimephp ;
$_SESSION['adultprice'] = $price ;
$_SESSION['scheduleid'] = $scheduleid ;
$_SESSION['flightid']= $flightid ;
print_r($_SESSION['departtime']);
print_r($_SESSION['returntime']);
print_r($_SESSION['adultprice']);
print_r($_SESSION['scheduleid']);
print_r($_SESSION['flightid']);
}
?>
No matter which choice I select, the out put is always the last row of table, I guess its because there all had same variable name so system direct insert last row data.
My problem is a bit same like here, they suggest using array[] to solve this but I got error when i add a foreach inside a isset, so any idea how to get the correct data?
Appreciate for any solution.

Answer 1

The code shown doesn't explicitly show this, but I strongly suspect that the entire table is your form. Which means that no matter which button you click, all values are being submitted.
For starters, the browser wouldn't know which one you "meant" and any given value would just overwrite the previous one in the form POST. (Which explains the behavior you're seeing... you always get the last record.) But, aside from that... Why? Why submit all of the data when you really just need a single identifier of the record which was selected?
For each row in the table, put an entire self-contained form. Something like this:
<tr>
<!--- your other table cells --->
<th>
<form method="post" action="someAction.php">
<input type="hidden" name="flightid" value="<?php echo $row['flight_id'];?>" />
<button type="submit" class="submit-button" method="post" name="departbtn">booking</button>
</form>
</th>
</tr>
(You can put more of those hidden form fields there, as many as you like really. Though honestly you should just need an identifier. The server already has the rest of the data. And the more fields you use is just more opportunities for users to mess with the system.)
That way when you click a button, there's no ambiguity on the option being selected. Each form is entirely self-contained and has only the data it needs to post.