MySQL select from users where there are more matches [closed] - php

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I would like to know how to choose the users that have the highest number of columns to match the columns of the logged in user.

order by sum matches conditions ex:
SELECT * FROM table where fColumn = 'name' and column2='value2' or colmun3='value3'
ORDER BY (
(column2='value2') + (column3='value3')
) DESC

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Get products variation details [closed]

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I will developing e-commerce website but need some help from you.
When I run query "SELECT * FROM products_variations_option WHERE variations_id IN (31,41) ORDER BY product_variations_id ASC" then I am gating this output but I need 1 and second row, Means I want only product_variations_id= 75 because 31 and 41 both value found in only product_variations_id=75
The below query may give you desired output
SELECT variations_id, product_variations_id
FROM (SELECT *
FROM products_variations_option
WHERE variations_id IN (31,41)
ORDER BY product_variations_id ASC
) as t
GROUP BY variations_id

Get value from type point in php [closed]

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I have a field in the database of type POINT (phpMyAdmin). I use this column to save gps coordinates.
Now I want to extract the value of latitude and longitude from database.
Can I do that without having to add other fields?
$query="SELECT * FROM risk_disposal WHERE id=$id";
$result=mysqli_query($conn,$query);
while ($row2 = mysqli_fetch_array($result))
{echo "$row2['gps']";}
Database
Try it:
SELECT ST_X(point), ST_Y(point) FROM ...

Get the closest value of a column in MYSQL [closed]

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I have a table that have a CP value (numeric), for example, 28030, 28060, 27100 etc. And the user can introduce a number via PHP. I want to, having this number for example, 28050, order in MYSQL my table putting 28060 as the first position.
This is the basic of my table:
SELECT * FROM `tiendas` ORDER BY `CP`
ABS() will work. Here's a query that does the job:
SELECT
CP
FROM tiendas
ORDER BY ABS(CP- 28050) ASC

PHP Select MYSQL select id from Array [closed]

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Hello I have this array:
$_SESSION['id'] = array();
I would like to select all array ID'S and then select them from the database.
How to do it? I have no idea..
$sql='select name from table where id in ('.implode(",",$_SESSION['id']).')';

Selecting data from MySQL in random order [closed]

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I want to extract each row from a table, but in random order. How can I do that? I tried using rand(), but I was not successful.
My database is named "permis54_permis-online-date" and my table is named: "intrebari".
Use ORDER BY RAND() MySQL:
SELECT column FROM intrebari
ORDER BY RAND()
select * from intrebari order by rand();

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