I have been trying to pull records based on a specified date. In the DB I have a column where I store unix timestamps. The user has the option to select records based on a date. The user inputs: 08/08/2016 (for example)
How would I write my SQL statement to handle this?
$query .= "`".$o."` = '".date("Y-m-d",strtotime($v))."' AND ";
Here we see the line where part of the SQL statement is built, because more than one column could be targeted by the user during their search request.
Somehow I need to be able to turn $o (which is a column storing unix timestamps) into the Y-m-d format for comparison, as shown above and make this work in an SQL statement.
Any help would be appreciated.
EDIT
Here is what worked for me:
$query .= "".$o.">= '".strtotime($v)."' AND".$o."< '".(strtotime($v)+(24*60*60))."' AND ";
You can do something like:
"WHERE DATE(`$o`) = '".date("Y-m-d",strtotime($v))."'"
However this won't use indexes, so if you have a large table it will be slower. If you want to be able to use indexes you can do:
"WHERE `$o` >= ".date("Y-m-d",strtotime($v))."
AND `$o` < ".date("Y-m-d",strtotime($v))." + INTERVAL 1 DAY"
You can also try this approach and use UNIX_TIMESTAMP on MySQL.
$v = '2016-08-04';
$query .= "'".$o."' = UNIX_TIMESTAMP('$v') AND ";
Related
I don't have too much experience with the PHP programming language, so I ask you for help solving a small problem.
I have several users in the tabele with their data and one column that lists the date when they need to report to the interview.
I need a sql query syntax to check the following:
Does the database have a user whose date in the table is the same or larger than it currently is. If a user is found, then my program will send an email to remind him.
I will use CRON JOB after to refresh the index.php, thats okay, but bothers me the most that I don't know the date comparison syntax.
Otherwise the date in mysql database for each user is entered in the format 2020-02-15
$datenow = date("Y-m-d");
echo $datenow;
$sql = "SELECT * FROM 'users' WHERE 'report_date' >= '".$datenow."'";
if ($result = mysqli_query ($con, $sql)) {
if (mysqli_num_rows($result)> 0) {
while($rows = mysqli_fetch_assoc ($result)) {
$id = $row['id'];
blablablabla
}
bothers me the most that I don't know the date comparison syntax
You seem to be looking for MySQL date function current_date(), which is the equivalent of php function call date("Y-m-d"):
SELECT * FROM users WHERE report_date >= current_date;
Side note: do not surround the column names with single quotes, otherwise it turns it to a literal string, so you end up comparing string 'report_date' with the date, which will not do what you want. Same goes for the table name, that should not be single quoted either.
I have this table and the query I give returns wrong results, I am not sure where the problem is
the date comparisons
or
structure of the query
The query if not clear in the image is :
select * from transact where item_code='msft234' or item_code='hp550x' and transact_date>=STR_TO_DATE('06-07-2013','%d-%m-%Y') and transact_date<=STR_TO_DATE('12-07-2013','%d-%m-%Y')
Your query employs a wrong syntax:
WHERE item_code='msft234' OR item_code='hp550x'
AND transact_date>=STR_TO_DATE('06-07-2013','%d-%m-%Y')
AND transact_date<=STR_TO_DATE('12-07-2013','%d-%m-%Y')
since AND priority is higher, it means that it will be satisfied if either you get hp550x in that date interval, or you get msft234 regardless of the date.
You have to put the OR'ed item codes in parentheses: (item_code='..' OR item_code='..' OR ..), or use IN: e.g.
SELECT * FROM transact
WHERE item_code IN ('msft234', 'hp550x')
AND transact_date BETWEEN
STR_TO_DATE('06-07-2013','%d-%m-%Y')
AND
STR_TO_DATE('12-07-2013','%d-%m-%Y')
Also, depending on the type you select for the date fields, consider that for a date to be "less or equal than 12-07-2013", it has to be less or equal than 12-07-2013 at 00:00, i.e., almost the latest date that will match is 11-07-2013 at 23:59:59.
So "less or equal than 12-07" will actually never select any row from 12-07-2013 unless it happens to have been inserted exactly at midnight.
If you insert rows by only specifying the date, then it will very probably work - the rows will be input at midnight and matched at midnight. But if (some) rows are entered with the full datetime, e.g. because they're type datetime and updated with NOW(), then they will not match.
put the item conditions between ()
(ítem_code = 'msft234' OR ítem_code = 'hp550x') AND transact_date>=STR_TO_DATE('06-07-2013','%d-%m-%Y') and transact_date<=STR_TO_DATE('12-07-2013','%d-%m-%Y')
(ítem_code = 'msft234' OR ítem_code = 'hp550x') AND transact_date BETWEEN STR_TO_DATE('06-07-2013','%d-%m-%Y') and STR_TO_DATE('12-07-2013','%d-%m-%Y')
For security I will put with 2 ()
(ítem_code = 'msft234' OR ítem_code = 'hp550x') AND (transact_date BETWEEN STR_TO_DATE('06-07-2013','%d-%m-%Y') and STR_TO_DATE('12-07-2013','%d-%m-%Y'))
I have my SQL statement like this trying to get the difference in 2 timestamps greater than 10 minutes. "timestamp" is a column in MYSQL which I hold a timstamp as such "1365793346"
SELECT * FROM table WHERE TIMESTAMPDIFF(MINUTE,timestamp,NOW()) AS thisisit
Im not sure if using "AS thisisit" is a current function of TIMESTAMPDIFF but I was able to find some old posts that how it used as such. I am not sure if its supported anymore because I an a syntax error at "AS thisisit"
I have also tried using
SELECT * FROM table WHERE TIMESTAMPDIFF(MINUTE,timestamp,NOW()) > 10
Where I am not sure what is going on is first is my syntax correct and second how to do associate this query with a label so I can echo it. My full PhP code looks like this
SELECT * FROM table WHERE TIMESTAMPDIFF(MINUTE,timestamp,NOW()) > 10
$result = mysql_query($sql);
while($row = mysql_fetch_array($result)) {
echo $row[0];
}
I was assuming I could use something like this to echo the results, but I get nothing to the screen. Can anyone point me in the right direction?
echo $row[0];
AS thisisit in this case have to be used to set an alias to your column.
So, you should use the following:
SELECT timestamp AS 'thisisit'
FROM table
WHERE TIMESTAMPDIFF(MINUTE, timestamp, NOW()) > 10;
I am unable to get the following code to work:
// dd/mm/yyyy for dates in SQL queries
$todayforw = date('d/m/Y');
$aweekago = date('d/m/Y', time() - 604800);
$week_e_check = mysql_query("SELECT * FROM earningslog WHERE user_id = '".$info['id']."' WHERE day >='".$aweekago."' AND day <'".$todayforw."'");
while ($week_e_info = mysql_fetch_array($week_e_check)) {
$week_e = $week_e + $week_e_info['user_earnings_amnt'];
}
The query returns zero rows, however, it should be returning data that matches the criteria.
Check your date format:
Should be:
YYYY-mm-dd HH:mm:ss
E.G.
2012-01-01 00:00:00 (January 1, 2012 at midnight local time)
Other date formats MAY work, but the best way to go about it is to use the same format that MySQL uses when they display the date, that's the only way I know that works every time.
http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html
Also your syntax is incorrect, you have two wheres, you should use AND.
Take a closer look at your query:
SELECT * FROM earningslog WHERE user_id = '".$info['id']."' WHERE day >='".$aweekago."' AND day <'".$todayforw."'"
Your Where clause appears twice.
Two things to think about - when you are selecting data, try and stay away from select * - you may get unexpected results of the table is ever modified.
Second, try and create the query as a parameterized query, instead of injecting the parameters directly into the where clause. By directly injecting your criteria the way you have, you are opening yourself up to a SQL injection attack.
By turning it into a parameterized query, you get the side benefit of being able to debug the queries directly against the database, reducing the amount of effort needed to copy it from a query tool into your code.
Your issue appears to be with your query syntax. You are stating WHERE twice, whereas you should only state it once and then use the AND or OR operators for further criteria. I would also suggest that you either move your statement into a variable or use die() to assist with debugging.
$week_e_check = mysql_query("SELECT * FROM earningslog WHERE user_id = '".$info['id']."' AND day >='".$aweekago."' AND day <'".$todayforw."'") or die(mysql_error());
In addition, you should not be using the mysql extension as use of this extension is discouraged. Instead, use the MySQLi or PDO_MySQL extension. Using one of these alternative extensions will help serve as the first step in preventing SQL injection. I would also suggest that you avoid using * and specify the column names to be returned instead.
Using PDO:
<?php
/* Execute a prepared statement by passing an array of values */
$sth = $dbh->prepare('SELECT * FROM earningslog WHERE user_id = ? AND day >= ? AND day < ?');
$sth->execute(array($info['id'], $aweekago, $todayforw));
$results = $sth->fetchAll();
?>
Try change the format of your strings from from d/m/Y to Y-m-d.
MySQL might be expecting it year first. In which case it could be doing the wrong thing with d/m/Y.
Also don't use the WHERE clause twice. Instead, combine conditions using AND, eg:
WHERE user_id = '".$info['id']."'
AND day >='".$aweekago."'
AND day <'".$todayforw."'
By the way, you can also try saying WHERE day BETWEEN ".$aweekago." AND ".$todayforw.", which might be easier syntax to read (as long as you change $todayforw to be the day before).
I've built a small application which has User Management, a frontend console to enter data and a backend console to control parts of the frontend. The frontend adds rows to a MySQL database which are timestamped. The backend needs to be able to select rows from the database between X and Y dates.
Everything works so far, except the date part which I'm really struggling with.
The frontend SQL input looks like this (simplified with spurious code removed):
$date = time();
$top_level_category = $_POST['top_level_category'];
$sub_level_category = $_POST['sub_level_category'];
$company = $_POST['company'];
$agent_name = $_POST['agent_name'];
$ticket_id = $_POST['ticket_id'];
$sql = "INSERT INTO dacc_data ("
. "id, top_level_category, sub_level_category, "
. "agent_name, date, ticket_id, company"
. ") VALUES ("
. "NULL, '$top_level_category', '$sub_level_category', "
. "'$agent_name', FROM_UNIXTIME('$date'), '$ticket_id', '$company'"
. ")"
;
$result = mysql_query($sql) or die (mysql_error());
That seems to work ok, the timestamp is being picked up and added to a DATETIME column in my table. It displays as dd/mm/yyyy hh:mm:ss within the database.
So ... my first question is - is this the right way to do it?
The second question being, what sort of SQL statement would I need to pull out an array of rows between X and Y date.
Apologies if this is rambling a bit, hope it's clear but if you need more information let me know.
MySQL datetime should be formatted with dashes:
YYYY-MM-DD HH:MM:SS
http://dev.mysql.com/doc/refman/5.0/en/datetime.html
Then you can query for date ranges a couple of ways:
select *
from table
where date >= '[start date]' and date <= '[end date]';
or
select *
from table
where date between '[start date]' and '[end date]';
where "table" is the name of your database table and "date" is the name of your datetime field.
You are correct. I can confirm that the Database has "YYYY-MM-DD HH:MM:SS" - I am using SQLWave editor for browsing the DB quickly, it auto-formats the DATETIME column.
// Initial questions still stand :)
Or not, just noticed you updated the answer - thank you very much! I had actually tried that very same query several times to no avail, mainly because my WHERE was specifying the date format incorrectly. Misled by SQLWave :(
Back to using command line from now on !!!
"what sort of SQL statement would I need to pull out an array of rows between X and Y date?"
SELECT * FROM `dacc_data` where `date` between "2008-11-01" and "2008-12-01"