I am now using the following method to store an image to server from input file type
$image = $request->file('file');
$filename = $item->itemId . '.png';
Storage::disk('s3')->put('/'.$filename, file_get_contents($image), 'public');
and I found method to rotate the image with PHP
$filename = 'test.jpg';
$degrees = 180;
header('Content-type: image/jpeg');
$source = imagecreatefromjpeg($filename);
$rotate = imagerotate($source, $degrees, 0);
imagejpeg($rotate);
but I dont know how implement the code with $request->file('file')
Thanks!
I am not sure where you are getting your functions from, imagecreatefromjpeg() and imagerotate(), but if you just use PHP's own, available functions (provided by Imagick), you can do something much simpler...
$image = new Imagick();
$image_filehandle = fopen('some/file.jpg', 'a+');
$image->readImageFile($image_filehandle );
$image->rotateImage("FFFFFF", 90); # Rotate 90 degrees, keep background of "FFFFFF" (white)
$image_icon_filehandle = fopen('some/file-rotated.jpg', 'a+');
$image->writeImageFile($image_icon_filehandle);
The background color ("FFFFFF") is applied here if the image rotates and leaves a certain amount of background (does not happen for rotate degrees in increments of 90).
Related
I am trying to rotate an image through GD Library and a database value:
// Image for rotating
$image = 'images/weather-icons/windDir.png';
//degrees from database
$degrees = $row[WindDirDegrees];
// Create the canvas
$source = imagecreatefrompng($image) ;
// Rotate the image
$rotate = imagerotate($source, $degrees, 0) ;
// Outputs
imagepng($rotate) ;
But all I get as output is a huge amount of "gibbergabber" symbols.
Does anyone know why?
You are missing header('Content-Type: image/png');
See: http://www.php.net/manual/en/function.imagepng.php
using the example given at http://www.php.net/manual/en/function.imagecopyresized.php ... how to get image sizes afterward using getimagesize() function?
CODE:
<?php
if(isset($_FILES['images'])){
//TEST1:
$img = resize_this_image_now($_FILES['images']['tmp_name']);
//TEST2:
$img = resize_this_image_now($_FILES['images']['name']);/// This Drastically failed.
$new_image = getimagesize($img);
var_dump($new_image[0]);// I guessed this should have printed out the WIDTH_OF_THE_IMAGE... but, it prints some NON_READABLE stuffs (why?)
}
// The PHP.NET CODE in a Function
function resize_this_image_now($filename){
// File and new size
// $filename = 'test.jpg';
$percent = 0.5;
// Content type
header('Content-Type: image/jpeg');
// Get new sizes
list($width, $height) = getimagesize($filename);
$newwidth = $width * $percent;
$newheight = $height * $percent;
// Load
$thumb = imagecreatetruecolor($newwidth, $newheight);
$source = imagecreatefromjpeg($filename);
// Resize
imagecopyresized($thumb, $source, 0, 0, 0, 0, $newwidth, $newheight, $width, $height);
// Output
return imagejpeg($thumb);
}
?>
All I want is to get the Size of the Image.... also, is it possible to do something like:
$_FILES['images']['tmp_name'] = $the_newly_resized_image_returned_from_the_PHP_dot_NET_code'; .... So that the ['images']['tmp_name'] will now have as source this new image??
Any suggestion is highly appreciated...
I decided to spend sometime examining you question. What I found out is that, I don't think you'd need to return the resized image through imagejpeg() the way you did. You might also need to add a imagedestroy(), after you call imagejpeg() in you function, to destroy the temporary memory used.
You need to first fully Upload the Image before resizing it. If you'd like, you could send the image in a temporary storage while you do whatever you want to it so that Php does not have to deal with it in a 'tmp_name' format...Then You can destroy the image later on.
Once the image is fully uploaded, things become easier. The codes might look something like:
if(isset($_FILES['images'])){
//may be some random numbers to accompany it.
$rand = floor((mt_rand()+rand()+mt_rand())/3);
//Send it to the temporary folder you have had to create.
if(move_uploaded_file(
$_FILES['images']['tmp_name'],'temporary_storage/image_'.$rand.'.jpg')){
//Then run the `resize` function from here.
$image_resized = resize_this_image_now('temporary_storage/image_'.$rand.'.jpg');
//Now You can get the size if you wish.
list($width,$height) = getimagesize('temporary_storage/image_'.$rand.'.jpg');
// Out put
echo "W:".$width."<br>H:".$height;
//After you use it as desired, you can now destroy it using unlink or so.
unlink('temporary_storage/image_'.$rand.'.jpg');
}else{
echo "Upload Error goes here";
}
}
Note this answer is produced after several trials and errors... Please use this strategy wisely.
Hope it helps.
I am trying to rotate image using php imagerotate function but its not working.
GD Library is also on.
i have tried this ,
public function rotate()
{
$targ_w = 240;
$targ_h = 180;
$jpeg_quality = 100;
$degrees = 90;
$src = "/photos/sunset.jpg";
$image = imagecreatefromjpeg($src);
$rotatedImage = imagerotate($image,$degrees,0);
imagejpeg( $rotatedImage,$src,$jpeg_quality);
imagedestroy($rotatedImage);
die();
}
<?php
// File and rotation
$filename = 'test.jpg';
$degrees = 180;
// Content type
header('Content-type: image/jpeg');
// Load
$source = imagecreatefromjpeg($filename);
// Rotate
$rotate = imagerotate($source, $degrees, 0);
// Output
imagejpeg($rotate);
// Free the memory
imagedestroy($source);
imagedestroy($rotate);
?>
You're outputing the unchanged $image to file. You should output the rotated one.
imagejpeg( $rotatedImage,$name ,$jpeg_quality);
The second thing - your image is empty. It has only defined width and height but has no content inside it. You defined a $src variable but you don't use it at all.
Maybe you want to replace imagecreatetruecolor with this:
$src = "/photos/sunset.jpg";
$image = imagecreatefromjpeg($src);
You must output the rotated image (pass $rotatedImage instead of $image):
$rotatedImage = imagerotate($image,$degrees,0);
header('Content-type: image/jpeg'); //Header is required to output the image.
imagejpeg($rotatedImage,$name ,$jpeg_quality);
imagedestroy($rotatedImage);
die();
If you are trying to show the image then you need to change that:
header('Content-type: image/jpeg'); //Add jpeg header
imagejpeg( $rotatedImage, NULL, 100); //<-- Notice i remove the $src parameter
If you want to update your jpg file then your code will work, but the user that runs the php file need permissions to write the file. Of course your current image will be overwritten.
And as i said in comments you will need GD version 1.8 or later to work with jpeg files according to php.net
How can I get the width and height of the image after rotating it using imagerotate() in PHP?
Here is my code:
<?php
// File and rotation
$filename = 'test.jpg';
$degrees = 180;
// Content type
header('Content-type: image/jpeg');
// Load
$source = imagecreatefromjpeg($filename);
// Rotate
$rotate = imagerotate($source, $degrees, 0);
// Output
imagejpeg($rotate);
// Free the memory
imagedestroy($source);
imagedestroy($rotate);
?>
But what I want to do before doing the output, is that I want to get the width and height of the rotated image. How can I do that?
I'm sure you can do something similar to this:
$data = getimagesize($filename);
$width = $data[0];
$height = $data[1];
Another option is this:
list($width, $height) = getimagesize($filename);
imagerotate returns an image ressource. Hence you cannot use getimagesize which works with an image file.
Use
$width = imagesx($rotate);
$height = imagesy($rotate);
instead.
I have a PHP script to re size image file as below;
$file = "test.bmp";
$ext = pathinfo($file, PATHINFO_EXTENSION);
$info = pathinfo($file);
$file_name = basename($file,'.'.$info['extension']);
$thumbname = "thumb/".$file_name.".".$ext;
$maxh = 200;
$maxw = 200;
$quality = 100;
list($width,$height)=getimagesize($file);
$src = imagecreatefromwbmp($file);
$tmp = imagecreatetruecolor($maxw,$maxh);
imagecopyresampled($tmp,$src,0,0,0,0,200,200,$width,$height);
imagejpeg($tmp,$thumbname,$quality);
imagedestroy($tmp);
The script is suppose to resize a Windows bitmap image to 200x200 thumbnail. But instead, I am getting a black 200x200 image. I am using PHP with Apache in Windows PC. How can I fix this?
.bmp and wbmp are VERY, VERY different file types.
Note the content-type headers:
Content-Type: image/x-xbitmap
Content-Type: image/vnd.wap.wbmp
Calling imagecreatefromwbmp($file) where $file is a .bmp will fail every time.
See this thread for info on how to load a .bmp file. It's not pretty.
As pointed out in PHP imagecopyresampled() docs:
Note:
There is a problem due to palette image limitations (255+1 colors). Resampling or filtering an image commonly needs more colors than 255, a kind of approximation is used to calculate the new resampled pixel and its color. With a palette image we try to allocate a new color, if that failed, we choose the closest (in theory) computed color. This is not always the closest visual color. That may produce a weird result, like blank (or visually blank) images. To skip this problem, please use a truecolor image as a destination image, such as one created by imagecreatetruecolor().
To see if it's the case you can use imageistruecolor() and copy the contents to a new truecolor image before "copyresampling" it:
if( !imageistruecolor($src) ){
$newim = imagecreatetruecolor( $width, $height );
imagecopy( $newim, $src, 0, 0, 0, 0, $width, $height );
imagedestroy($src);
$src = $newim;
}
There is a new opensource project on Github that allows reading and saving of BMP files (and other file formats) in PHP.
The project is called PHP Image Magician.
<?php
//Create New 'Thumbnail' Image
$newImageWidth = 200;
$newImageHeight = 200;
$newImage = imagecreatetruecolor($newImageWidth, $newImageHeight);
$newImageFile = 'output.jpg';
$newImageQuality = 100;
//Load old Image(bmp, jpg, gif, png, etc)
$oldImageFile = "test.jpg";
//Specific function
$oldImage = imagecreatefromjpeg($oldImageFile);
//Non-Specific function
//$oldImageContent = file_get_contents($oldImageFile);
//$oldImage = imagecreatefromstring($oldImageContent);
//Get old Image's details
$oldImageWidth = imagesx($oldImage);
$oldImageHeight = imagesy($oldImage);
//Copy to new Image
imagecopyresampled($newImage, $oldImage, 0, 0, 0, 0, $newImageWidth, $newImageHeight, $oldImageWidth, $oldImageHeight);
//Output to file
imagejpeg($newImage, $newImageFile, $newImageQuality);