PHP insert and Update on Multiple Query and table - php

Question

in there i want to make update and create on one condition,so when I create a new record, automatically update my Data if have i success make new.
here my PHP :
<?php
require "dbconnection.php";
$a = array();
$a['transidmerchant'] = $_POST['TRANSIDMERCHANT'];
$a['totalamount'] =$_POST['AMOUNT'];
$a['words'] = $_POST['WORDS'];
$a['payment_channel'] = $_POST['PAYMENTCHANNEL'];
$a['session_id'] = $_POST['SESSIONID'];
$a['payment_date_time'] = $_POST['REQUESTDATETIME'];
$a['trxstatus'] = 'Requested';
$query = "INSERT INTO doku (transidmerchant,totalamount,words,payment_channel,session_id,payment_date_time,trxstatus)
VALUES ('$_POST[TRANSIDMERCHANT]','$_POST[AMOUNT]','$_POST[WORDS]','$_POST[PAYMENTCHANNEL]','$_POST[SESSIONID]','$_POST[REQUESTDATETIME]','Requested')";
$sql = "UPDATE orders SET status='Paid' where id='$_POST[TRANSIDMERCHANT]'";
if(mysqli_query($con,$query)) {
mysqli_connect($con,$sql);
echo 1;
}else{
echo("Error description: " . mysqli_error($con));
}
my query : $query and $sql
i want my $sql its update when $query is success create

Answer 1

if (mysqli_query($con, $query) === true) {
mysqli_query($con, $sql);
echo 1;
} else {
echo('Error description: ' . mysqli_error($con));
}

Answer 2

Create a stored procedure for insert then update. You may want to do something like this to get you away from issuing regular queries checking sub-queries and move you to creating a stored procedure.
Create your procedure to something similar below and run it in your sql dialog. Once you're done, run it:
DELIMITER //
CREATE PROCEDURE Payment
(
a_transidmerchant int,
a_atotalamount float,
a_words varchar(200),
a_payment_channel varchar(200),
a_session_id int,
a_payment_date_time datetime,
etc...
)
BEGIN
insert into doku(field_name1, field_name2, field_name3, field_name4) values(a_field1, a_field2, a_field3, a_field4);
END //
DELIMITER;
Now, in your php file, do the following:
if(isset($_POST[transidmerchantid])) /**** start a post check ****/
//before you touch the db
{
$con = mysqli_connect("localhost","user","pass","database");
//start defining variables
$transidmerchantid = $_POST[name];
$totalamount = $_POST[course];
$words = $_POST[words];
//calling stored procedure - call values for parameters in stored procedure
$sql = "CALL Payment('$transidmerchantid','$totalamount','$words')"; // <----
//in the order of operation, meaning once you have inserted the data,
//you can update the table. you're automatically updating the table row
//based on a successful insert, which is after calling the insert row
//stored procedure.
$result = mysqli_query($con,$sql);
if($result) //insert successful.
echo "Record Added Successfully!";
$sql = "UPDATE orders SET status='Paid' where id='$_POST[TRANSIDMERCHANT]'";
mysqli_query($con,$query);
}else{
echo("Error description: " . mysqli_error($con));
}else{
echo "Record Not added!"; //insert unsuccessful.
}
} /**** end post check ****/