I have problem .i am making ajax call to a php file that will check credentials, if true i want to redirect to page , but if false i want to show error. I have little bit problem . Here is my code ajax Code.
function Login(val1, val2) {
alert(val1 + "\n" + val2);
$.ajax({
type: "POST",
url: "login.php",
data: 'username='+val1+'&password='+val2,
success: function(data) {
alert(data);
if(data=="true"){
window.location.replace('./admin/index.php');
}else
$("#Area").html(data);
}
});
and this is my php code.
<?php
require_once '/admin/DbHelper.php';
if (isset($_POST['password'])) {
$pass = $_POST['password'];
$name = $_POST['username'];
$query = "select * from user_login where userName='$name' and userPass='$pass'";
$result = mysqli_query($link, $query);
$row= mysqli_fetch_array($result);
if ($row > 0) {
$_SESSION['userName'] = $name;
echo "true"; } else {
echo '<label style="color:red"> Invalid User Name or Passowrd !</label>';
}
}
i can't understand where i should set session. please help me.
Related
how can I return a variable from a PHP query to AJAXA. I want the user to be redirected to the user panel using javascript after successfully entering the login and password. The query in PHP was successfully written but Ajax does not return any results.
Code Javascript:
$(document).ready(function() {
$("#btn-login").click(function() {
const loginAuth = $("#login-auth").val();
const passAuth = $("#pass-auth").val();
$.ajax({
type: "POST", //Request type
url: "http://localhost/game/login.php",
data: {
loginAuth: loginAuth,
passAuth: passAuth
},
cache: false,
success: function(data) {
console.log(data);
}
});
});
});
Code PHP:
<?php
require ('connect.php');
session_start();
// If form submitted, insert values into the database.
if (isset($_POST['loginAuth'])) {
// removes backslashes
$username = stripslashes($_REQUEST['loginAuth']);
// escapes special characters in a string
$username = mysqli_real_escape_string($con, $username);
$password = stripslashes($_REQUEST['passAuth']);
$password = mysqli_real_escape_string($con, $password);
// Checking is user existing in the database or not
$query = "SELECT * FROM `users` WHERE login='$username'
and password='" . md5($password) . "'";
$result = mysqli_query($con, $query) or die(mysql_error());
$rows = mysqli_num_rows($result);
if ($rows == 1) {
$_SESSION['username'] = $username;
// Redirect user to index.php
$arr = 'udało się';
header("Location: panel.php");
}
else {
$arr = false;
header("Location: panelLogin.php");
}
}
else {
}
echo json_encode($arr);
?>
Thank you very much for every help.
you cannot redirect the user from the php script that is being called from ajax call.
because it will redirect but not on your browser instance but the ajax one.
you need to redirect it from javascript.
so you can do
echo "true";
instead of
header("Location: panel.php");
and echo "false"; // in case login failed
as an example but you can print some json text and use more informative messages
and you can check these values from ajax success function then you can do
window.location.href = "the url you want to redirect to";
I know that this question is already answered a lot, but even the previous responses from php are working, this response cannot work and i cannot find the reason for this issue.
Although php was send the response succesfully, ajax cannot display without refreshing the page first.
Here is my jquery.ajax code in the file helpers.js:
function likeButton(commentId, userId) {
$.ajax({
url: "requests.php",
type: "POST",
data: {
like: "likeUp",
commentId: commentId,
userId: userId
},
success: function(response) {
$("#comment_body").append(response);
}
});
}
Here is my php code in requests.php:
if(isset($_POST['like'])) {
if($_POST['like'] == "likeUp") {
$commentId = $_POST['commentId'];
$userId = $_POST['userId'];
$sql = "SELECT gaming_comment_like FROM gaming_comments WHERE gaming_comment_id='$commentId'";
$result = mysqli_query($conn, $sql);
if($row = mysqli_fetch_assoc($result)) {
$gaming_comment_like = $row['gaming_comment_like'];
}
$gaming_comment_like = $gaming_comment_like + 1;
$sql_update = "UPDATE gaming_comments SET gaming_comment_like='$gaming_comment_like' WHERE gaming_comment_id='$commentId'";
$result_update = mysqli_query($conn, $sql_update);
exit();
}
}
here is the eventhandler that calling the likeButton function, which is in a php file:
<p><img src='like.png' class='like_button' onclick='likeButton(".$gaming_comment_id.", ".$user_id.");'>$gaming_comment_like</p>";
I have a problem with this my script.
$("#login").click(function(event) {
event.preventDefault();
var email = $("#email").val();
var pass = $("#password").val();
$.ajax({
url : "login.php",
method: "POST",
data: {userLogin:1, userEmail:email, userPassword:pass},
success : function(data){
if(data == "1"){
alert(data);
}
}
})
I want it to alert a value that I am getting from an echo in another php file
<?php
if(isset($_POST['userLogin'])){
$email = mysqli_real_escape_string($con, $_POST['userEmail']);
$password = md5($_POST['userPassword']);
$sql_login = "SELECT * from database where email = '$email' AND password = '$password'";
$query_login = mysqli_query($con, $sql_login);
$count_login = mysqli_num_rows($query_login);
if($count_login == 1){
$row_login = mysqli_fetch_assoc($query_login);
$_SESSION['uid'] = $row_login['user_id'];
$_SESSION['name'] = $row_login['first_name'];
echo "1";
}
}
?>
If I didn't put the alert(data) in an if condition, it displays the value I echo, but I need the condition to enable the right user logged in.
What can IF can also ELSE.
In your ajax add the else conditions to see if it helps uncover the issue:
if (data == "1") {
alert('youre in');
} else {
alert('try again');
}
And in your php, also account for the else condition (and do strict checking on that count of rows with ===):
if ($count_login === 1) {
// code ...
echo '1';
} else {
echo 'Sorry, the login is incorrect';
}
It works fine for me, if i always echo "1", the alert(data) show 1, in an if condition and out, pls, echo something else if isset($_POST['userLogin']) or $count_login == 1 are false, or put an
error : function(data) {
$('body').append("<div>"+data.responseText+"</div>")
}
in your ajax, to debug the prob. Because in your .php file, when you echo nothing, it returns a data in error, not in success, maybe that's your prob.
I have built a login script that uses AJAX to submit form data.
The PHP part works fine without AJAX. But the system doesnt work with AJAX Implementation.
It always Displays the below message even though the PHP file returns true[correct username & password] ... Seems like the if condition in Jquery is not working.
Incorrect Username/Password
HTML Result Div
<div id="user-result" align="center"></div>
Jquery
<script type="text/javascript">
$(document).ready(function () {
var form = $('#loginform');
form.submit(function (ev) {
ev.preventDefault();
$.ajax({
type: form.attr('method'),
url: form.attr('action'),
cache: false,
data: form.serialize(),
success: function (data) {
if (data == "true") {
$("#user-result").html("<font color ='#006600'> Logged in | Redirecting..</font>").show("fast");
setTimeout(
function () {
window.location.replace("index.php");
}, 1500);
} else {
$("#user-result").html("<font color ='red'> Incorrect Username/Password</font>").show("fast");
}
}
});
});
});
</script>
fn_login.php
<?php
{
session_start();
include_once 'db_connect.php';
if (isset($_POST))
{
$email = filter_input(INPUT_POST, 'email', FILTER_SANITIZE_STRING);
$logpwd = filter_input(INPUT_POST, 'password', FILTER_SANITIZE_STRING);
$stmt = $conn->prepare("SELECT password FROM manager WHERE email = ? LIMIT 1");
$stmt->bind_param("s", $email);
$stmt->execute();
$stmt->store_result();
// get variables from result.
$stmt->bind_result($password);
$stmt->fetch();
// Check if a user has provided the correct password by comparing what they typed with our hash
if (password_verify($logpwd, $password))
{
$sql = "SELECT * from manager WHERE email LIKE '{$email}' LIMIT 1";
$result = $conn->query($sql);
$row=mysqli_fetch_array($result);
$id = $row['id'];
$conn->query("UPDATE manager SET lastlogin = NOW() WHERE id = $id");
$_SESSION['manager_check'] = 1;
$_SESSION['email'] = $row['email'];
$_SESSION['fullname'] = $row['fullname'];
$_SESSION['designation'] = $row['designation'];
$_SESSION['id'] = $row['id'];
echo "true";
}
else {
die();
}
}
}
?>
Can someone please point out the mistake in the code/practice.
EDIT
Just Tried disabling AJAX, the PHP file works correctly echoing true when username/pass is correct
You have spaces after ?>
So, the AJAX response is having spaces after true.
Solution:
Remove ?> from the end of PHP file.
It will not affect any PHP functionality.
And you AJAX response will be without spaces.
Excluding closing tag ?> from the end of PHP file is standard practice for modern PHP frameworks and CMSs.
Tips for debugging AJAX:
1) Always use Firefox (with Firebug Add) on Or Chrome.
2) Use Console tab of Firebug, to check which AJAX requests are going.
3) Here, you can see input parameters, headers and most important response.
4) So, in short you can debug a whole AJAX request life cycle.
You can echo json_encode(array('success'=>true)) from php code and modify your if condition in jquery with if(data.success){} Your modified code becomes
<?php
{
session_start();
include_once 'db_connect.php';
if (isset($_POST))
{
$email = filter_input(INPUT_POST, 'email', FILTER_SANITIZE_STRING);
$logpwd = filter_input(INPUT_POST, 'password', FILTER_SANITIZE_STRING);
$stmt = $conn->prepare("SELECT password FROM manager WHERE email = ? LIMIT 1");
$stmt->bind_param("s", $email);
$stmt->execute();
$stmt->store_result();
// get variables from result.
$stmt->bind_result($password);
$stmt->fetch();
// Check if a user has provided the correct password by comparing what they typed with our hash
if (password_verify($logpwd, $password))
{
$sql = "SELECT * from manager WHERE email LIKE '{$email}' LIMIT 1";
$result = $conn->query($sql);
$row=mysqli_fetch_array($result);
$id = $row['id'];
$conn->query("UPDATE manager SET lastlogin = NOW() WHERE id = $id");
$_SESSION['manager_check'] = 1;
$_SESSION['email'] = $row['email'];
$_SESSION['fullname'] = $row['fullname'];
$_SESSION['designation'] = $row['designation'];
$_SESSION['id'] = $row['id'];
echo json_encode(array('success'=>true));
}
else {
die();
}
}
}
AND JQuery becomes
<script type="text/javascript">
$(document).ready(function () {
var form = $('#loginform');
form.submit(function (ev) {
ev.preventDefault();
$.ajax({
type: form.attr('method'),
url: form.attr('action'),
cache: false,
data: form.serialize(),
success: function (data) {
if (data.success) {
$("#user-result").html("<font color ='#006600'> Logged in | Redirecting..</font>").show("fast");
setTimeout(
function () {
window.location.replace("index.php");
}, 1500);
} else {
$("#user-result").html("<font color ='red'> Incorrect Username/Password</font>").show("fast");
}
}
});
});
});
</script>
I have 2 php file, one is "Db_function.php" and "index.php", "index.php" will make a function call in "Db_function.php".
I want to make a call to "index.php" by ajax, here's my code
Html file
<Html>
<body>
<script type="text/javascript" src="js/index.js"></script>
<input type="button" value="Get" onclick="get()">
</body>
</html>
Js file
function get() {
$.ajax({ url: 'index.php',
data: {tag:'get_backup', email:'mail#mail.com', password:'123'},
type: 'post',
datatype:'json'
success: function(output) {
alert(output);
}
});
}
index.php
/*with connect value*/
if ($tag == 'get_backup'){
// store user
$email = $_POST['email'];
$password = $_POST['password'];
$user = $db->get_backup($email, $password);
Db_funtion.php
public function get_backup($email, $password) {
$result = mysql_query("SELECT * FROM users WHERE email = '$email'") or die(mysql_error());
// check for result
$no_of_rows = mysql_num_rows($result);
if ($no_of_rows > 0) {
$result = mysql_fetch_array($result);
$salt = $result['salt'];
$encrypted_password = $result['encrypted_password'];
$hash = $this->checkhashSSHA($salt, $password);
// check for password equality
if ($encrypted_password == $hash) {
// user authentication details are correct
$response = array();
$result2 = mysql_query("SELECT * FROM contact_store WHERE (email ='$email' AND backup_name='$email')") or die(mysql_error());
if (mysql_num_rows($result2) > 0) {
// looping through all results
// contact_stores node
$response["contact_stores"] = array();
while ($row = mysql_fetch_array($result2)) {
// temp user array
$contact_store = array();
$contact_store["backup_name"] = $row["backup_name"];
$contact_store["email"] = $row["email"];
$contact_store["data"] = $row["data"];
// push single contact_store into final response array
array_push($response["contact_stores"], $contact_store);
}
// success
$response["success"] = 1;
// echoing JSON response
echo json_encode($response);
} else {
// no contact_stores found
$response["success"] = 0;
$response["message"] = "No contact_stores found";
// echo no users JSON
echo json_encode($response);
}
}
} else {
// user not found
return false;
}
}
Json return like this
{"contact_stores":[{"backup_name":"nhi#gmail.com","email":"nhi#gmail.com","data":"[]"}],"success":1}
But my problem is when i press get button in html file, nothing happen.
Any help for me ?
It seems like you are not defining the get() function that you provide in the input element.
Try this HTML:
<input id="get" type="button" value="Get">
with this javascript:
$('#get').click(function() {
$.ajax({ url: 'index.php',
data: {tag:'get_backup', email:'mail#mail.com', password:'123'},
type: 'post',
datatype:'json'
success: function(output) {
alert(output);
}
})
});