I have another table called tableb and it has a user relationship defined through the user_id field.
I want to run a query against tableb where a certain date is within a certain range but then I want to grab the user table associated with that row but I only want it to grab the user if it's not been grabbed yet. I'm trying to do this all in 1 DB query. I have most of it done, but I'm having trouble with the unique part of it.
Here's what I have right now:
$tableB = TableB::select('users.*')
->join('users', 'tableb.user_id', '=', 'users.id')
->where('tableb.start_date', '>', date('Y-m-d'))
->get();
So right now I have 3 entries in tableB from the same user, and ideally I'd like to only get 1 entry for that user.
How would I go about doing this?
Since you're selecting only users data, just add a groupBy clause in your query.
$tableB = TableB::select('users.*')
->join('users', 'tableb.user_id', '=', 'users.id')
->where('tableb.start_date', '>', date('Y-m-d'))
->groupBy('users.id')
->get();
You should just add groupBy like this :
$tableB = TableB::select('users.*')
->join('users', 'tableb.user_id', '=', 'users.id')
->where('tableb.start_date', '>', date('Y-m-d'))
->groupBy('users.id')
->get
Try This Code
App/user.php
public function getrelation(){
return $this->hasMany('App\tableB', 'user_id');
}
In Your Controller
Controller.php
use App/user;
public funtion filterByDate(user $user)
{
$date = '2016-02-01';
$result = $user->WhereHas('getrelation', function ($query) use($date) {
$query->whereDate('tableb.start_date', '>', $date)
->first();
});
}
Related
I have two table (users and messages) .. I wrote a query to get all messages that users sent to me or I sent, using JOIN .. to get all the users I have contacted or they did.
as in the code below:
$users = Message::join('users', function ($join) {
$join->on('messages.sender_id', '=', 'users.id')
->orOn('messages.receiver_id', '=', 'users.id');
})
->where(function ($q) {
$q->where('messages.sender_id', Auth::user()->id)
->orWhere('messages.receiver_id', Auth::user()->id);
})
->orderBy('messages.created', 'desc')
->groupBy('users.id')
->paginate();
The problem here is when records grouped, I'm getting the old message not the new one according to its created_at .. So, I want to get the last record of the grouped records.
It seems like it would make more sense to make use of Eloquent's relationships here so that you can eager load the relationships instead of having to use join and group by:
$messages = Message::with('sender', 'receiver')
->where(function ($query) {
$query->where('sender_id', auth()->id())
->orWhere('receiver_id', auth()->id())
})
->orderByDesc('created') // is this meant to be 'created_at'?
->paginate();
The following is my query which may output more than one row. I need to store the user_id field in each row in the $send_user_id variable below, so that I will use a foreach loop in the blade. I'm currently receiving (Trying to get property of non-object) error.
$j_request = DB::table('grpusrs')
->join('users', 'users.id', '=', 'grpusrs.user_id')
->join('groups', 'grpusrs.group_id', '=', 'groups.id')
->where('groups.owner_id', $user_id)
->where('grpusrs.join_request', 1)
->get();
$send_user_id = $j_request->user_id;
Also this query joins two tables, so how do I specify the table that has the required field? (i.e. I want the user_id that is in the 'Grpusrs' table not in the 'Groups' table)
If you need to retrieve multiple user_id you can loop through $j_request object and collect every user_id inside an array.
$j_request = DB::table('grpusrs')
->join('users', 'users.id', '=', 'grpusrs.user_id')
->join('groups', 'grpusrs.group_id', '=', 'groups.id')
->where('groups.owner_id', $user_id)
->where('grpusrs.join_request', 1)
->select('users.*', 'contacts.phone', 'orders.price')
->get();
$send_user_id = [];
$j_request->each(function($item) use ($send_use_id){
$send_user_id[] = $item->user_id;
});
If you only need one user_id you should be more "precisely" in your query (get just one record). After that, you can get user_id simply with $j_request->user_id
I want to create a chat system on which i could list all the chats between specific 2 persons
I have 2 tables users and chats
my chats table have 3 columns - user_id, friend_id and chat
my User.php model file is like this
public function chats() {
return $this->hasMany('App\Chat');
}
For eg:
I want to list all the chat between user 1 and 3 without changing the order of the conversation
I can simply do it by doing $chats = Auth::user()->chats->where('friend_id', '=', $id); but this will only give the authenticated (which is user 1 or 3) users chats. But I want the conversation between both of them.
So I have found an alternate way to do that by
$first = Chat::all()->where('user_id', '=', Auth::user()->id)->where('friend_id', '=', $id);
$second = Chat::all()->where('user_id', '=', $id)->where('friend_id', '=', Auth::user()->id);
$chats = $first->merge($second);
But this way has some problems. This will not get the chats in the correct order. I think it is impossible to order it correctly.
So my question is how can I list the conversation between two persons in the correct order easily?
If you want more details about my problem you can just ask.
You should be able to do it in one query with parameter grouping, rather than executing two separate queries and then merging them.
Chat::where(function ($query) use ($id) {
$query->where('user_id', '=', Auth::user()->id)
->where('friend_id', '=', $id);
})->orWhere(function ($query) use ($id) {
$query->where('user_id', '=', $id)
->where('friend_id', '=', Auth::user()->id);
})->get();
This might also return your results in the correct order, just because without any sort criteria specified, databases will often return rows in the order they were inserted. However, without adding something to your chat table to sort by, (either a timestamp or an autoincrement id), there's no way to guarantee it.
Try like this
$first = Chat::all()->where('user_id', '=', Auth::user()->id)
->where('friend_id', '=', $id)->get();
$second = Chat::all()->where('user_id', '=', $id)
->where('friend_id', '=', Auth::user()
->id)->get();
$chats = $first->merge($second)
->sortBy('created_at');//created_at is timing added change if other
First of all, you should not do all() before filtering. This is bad because fetches all the table data and then does the filtering in PHP.
You should consider doing this:
In your migration:
Schema::create("chat", function (Blueprint $table) {
//Other creation lines
$table->timestamps();
})
Then in your chat model:
public function scopeInvolvingUsers($query, $userId,$friendId) {
return $query->where([ ["user_id",$userId],["friend_id",$friendId] ])
->orWhere([ ["user_id",$friendId],["friend_id",$userId] ]);
}
Then you can do the following:
$chats = Chat::involvingUsers(\Auth::id(),$otherId)->latest()->get();
Note that latest or earliest requires the timestamps to be present on the table.
I will add timestamps in chat table which will ensure the order.
To add timestamp into chat table just add
$table->timestamps();
and the you can select the chat related to the user and sort it by created_at.
In laravel 5.3+ use
Chats::where(['user_id', '=', Auth::id()], ['friend_id', '=', $id])->orWhere(['user_id', '=', $id], ['friend_id', '=', Auth::id()])->sortBy('created_at');
Chat::whereIn('user_id', [$id, Auth->user()->id])
->whereIn('friend_id', [$id, Auth->user()->id])->get();
I have 3 tables: posts, votes and users. I have written a neat code with Eloquent to retrieve just the posts where the user has not voted yet on.
$posts = Post::whereDoesntHave("votes")
->where('user_id', '=', $user_id)
->whereBetween('posts.created_at', array(Carbon::now()->subHours(48), Carbon::now()))
->take(20)
->get();
return response()->json(['posts' => $posts])->withCallback($request->input('callback'));
But also I want to retrieve user name from table users. I want to pass the data with json.
If I try to do it with query builder, it is hard to eliminate posts that have been voted already by the user.
You can do a join manually to the user table
$posts = Post::join('users', 'users.id', '=', 'posts.user_id')
->whereDoesntHave("votes")
->where('user_id', '=', $user_id)
->whereBetween('posts.created_at', array(Carbon::now()->subHours(48), Carbon::now()))
->take(20)
->get();
Or you could define a relationship in the Post model class.
public function user()
{
return $this->belongsTo('App\User');
}
Then you use with('user') to retrieve data from user table.
$posts = Post::with('user')
->whereDoesntHave("votes")
->where('user_id', '=', $user_id)
->whereBetween('posts.created_at', array(Carbon::now()->subHours(48), Carbon::now()))
->take(20)
->get();
I'm struggling to get unique results when using the DISTINCT method in laravel. This is my query
//Get users that are part of this sector
$users = DB::table('users')->distinct()
->join('projects', 'users.id', '=', 'projects.userID')
->where('projects.sectorID', '=', $sector->sectorID)
->get();
dd($users);
The result shows 3 users with the same ID, when I only want one of them in the results.
How should I change my query?
Try to use group by id
$users = DB::table('users')
->join('projects', 'users.id', '=', 'projects.userID')
->where('projects.sectorID', '=', $sector->sectorID)
->groupBy('users.id')
->get();
dd($users);