How to insert same data into database after update in ORM?
For example i have function save() and inside this function i have update and it's working, but i don't know how to make insert with old update data. I mean it should make something like history in database. I only hope you can understand what i mean. Thanks for help.
public function save(Validation $validation = NULL)
{
if ($this->loaded()) {
// UPDATE TRIGGER
DB::update($this->_table_name)
->set(array('ud_status' => 'D'))
->where('ud_status', '=', 'A')
->where('ud_uId', '=', $this->ud_uId)
->execute($this->_db);
return false;
} else {
// INSERT TRIGGER
return parent::save($validation);
}
}
$query = DB::insert('users', array('username', 'password'))->values(array('fred', 'p#5sW0Rd'));
https://kohanaframework.org/3.3/guide/database/query/builder#insert
Related
I want to delete a row from likes_table if the table already has a row which contain requested shop_id and user_id combination.
Or, make a new row if it not exists.
However, this following code always executes delete method (returns 204) even if there is no row.
Would you give me any advice?
public function store(Request $request)
{
$liked_id = Like::where('shop_id', $request->shop_id)
->where('user_id', $request->user_id)
->get('id');
$liked = Like::find($liked_id);
if (!empty($liked)) {
Like::where('shop_id', $request->shop_id)
->where('user_id', $request->user_id)->delete();
return 204;
} else {
return Like::create($request->all());
}
}
I solved it myself.
OK：
if ($liked->isEmpty())
NG:
if (!empty($liked))
So i'm trying to run an query by using a transaction but it's not working somehow i did check all the posts but no fixes seems to be working ! whenever i remove the transaction the insert query works just fine.
Here's the controller :
public function addEmployee(){
$field = array(
'NomClient'=>$this->input->post('fullName'),
'TelClient'=>$this->input->post('tel'),
'WilayaClient'=>$this->input->post('wilaya'),
'CommuneClient'=>$this->input->post('commune'),
'AdresseClient'=>$this->input->post('adresse'),
'StatusID'=>$this->input->post('statusCommande'),
'TelevendeuseID'=>$this->input->post('televendeuse')
);
$result= $this->m->addEmployee($field);
$msg['success'] = false;
$msg['type'] = 'add';
if($result){
$msg['success'] = true;
}
echo json_encode($msg);
}
My model :
public function addEmployee($field){
$this->db->trans_start();
return $this->db->insert('Clients',$field);
$this->db->trans_complete();
}
Please note that when i switch the model to :
public function addEmployee($field){
return $this->db->insert('Clients',$field);
}
The record gets inserted successfully ! Which means that something is wrong with the transaction. I'm currently using one query to test if it's working so i can use multiples onces after that. Note that the tables are InnoDB tables so the problem isn't with the table type. Please help me out !
When you call return it will end the function, so when it hits
return $this->db->insert('Clients',$field);
it will not get to
$this->db->trans_complete();
so perhaps...
$this->db->trans_start();
$return = $this->db->insert('Clients',$field);
$this->db->trans_complete();
return $return;
I have an update function in my Model which I call from My controller as
if($_POST)
{
$this->User_model->update('user_about',$_POST,$this->session->userdata['id']);
}
takes three parameters, table name, post data and user id. The function is defined in the Model as
public function update($table,$data,$id)
{
$row=$this->db->select('*')->from($table)->WHERE('user_id',$id)->row();
if($row)
{
$this->db->WHERE('user_id',$id)->UPDATE($table,$data);
}
else
{
$data['user_id']=$id;
$this->db->insert($table,$data);
}
}
What I am doing here is checking if the record of particular user doesn't exist it should insert, otherwise update. Works like a charm
Question
Is there a way to skip the IF condition block?. Is there any provision in query builder which performs the check itself?
Here is a custom generic insert and update on duplicate function that I always used in my programming.
public function updateOnDuplicate($table, $data )
{
if (empty($table) || empty($data)) return false;
$duplicate_data = array();
foreach($data AS $key => $value) {
$duplicate_data[] = sprintf("%s='%s'", $key, $value);
}
$sql = sprintf("%s ON DUPLICATE KEY UPDATE %s", $this->db->insert_string($table, $data), implode(',', $duplicate_data));
$this->db->query($sql);
return $this->db->insert_id();
}
You can use the above function in the model and call it in the controller. The function will update the value if the duplicate occurs. Check out following blog post if you need detail explanation A Generic CodeIgniter Function for both Update and Insert.
Here's my function to load submissions created by a user.
public function viewSubs()
{
$user = User::find(Input::get('id'));
$submissions = Submission::find($user)->sortByDesc('created_at');
$submissions->load('user')->load('votes')->load('suggestions.votes');
return view('submissions.index' , compact('submissions'));
}
This returns with an error
Call to a member function load() on null
when there are no records on the submission.
How to handle if there are no submission on the DB?
Just check if its null first using an if statement:
public function viewSubs()
{
$user = User::find(Input::get('id'));
if ($submissions = Submission::find($user)->sortByDesc('created_at')) {
$submissions->load('user')->load('votes')->load('suggestions.votes');
}
return view('submissions.index' , compact('submissions'));
}
Also, depending on your DB structure I'm pretty sure you can cut out a lot of the code by utilising your models' relationships by doing something like this:
$user = User::find(Input::get('id'))
->with(['submissions' => function($query) {
$query->orderBy('created_at', 'asc');
}, 'submissions.votes', 'submissions.suggestions.votes']);
Then pass the $user variable to the view, or:
$submissions = Submission::with('user', 'votes', 'suggestions.votes')
->where('user_id', Input::get('id'))
->sortByDesc('created_at')
->first();
Not entirely sure the code will work perfectly, but I'm sure you can tweak it. The point is your code can be a lot shorter and still/or more readable by using relationships you've already set up.
I am trying to get the value of a row in the database but not working out that well. I not sure if can work like this.
I am just trying to get the value but also make sure it from the group config and the key.
Model
function getTitle() {
return $this->db->get('setting', array(
->where('group' => 'config'),
->where('key' => 'config_meta_title'),
->where('value'=> ) // Want to be able to return any thing in the value
))->row();
}
In the controller I would do this:
function index() {
$data['title'] = $this->document->getTitle();
$this->load->view('sample', $data);
}
First, you have this line set to this:
$data['title'] $this->document->getTitle();
That should be an = assignment for $this->document->getTitle(); like this:
$data['title'] = $this->document->getTitle();
But then in your function you should actually return the setting value from your query with row()->setting:
function getTitle() {
return $this->db->get('setting', array(
->where('group' => 'config'),
->where('key' => 'config_meta_title'),
->where('value'=> ) // Should return this row information but can not.
))->row()->setting;
}
But that said, I am unclear about this:
->where('value'=> ) // Should return this row information but can not.
A WHERE condition is not a SELECT. It is a condition connected to a SELECT that allows you to SELECT certain values WHERE a criteria is met. So that should be set to something, but not really sure what since your code doesn’t provide much details.
Found Solution Working Now. For Getting Single Item From Database In Codeigniter
Loading In Library
function getTitle($value) {
$this->CI->db->select($value);
$this->CI->db->where("group","config");
$this->CI->db->where("key","config_meta_title");
$query = $this->CI->db->get('setting');
return $query->row()->$value;
}
Or Loading In Model
function getTitle($value) {
$this->db->select($value);
$this->db->where("group","config");
$this->db->where("key","config_meta_title");
$query = $this->db->get('setting');
return $query->row()->$value;
}