restore database in php - php

I'm trying to restore my database using this code and it doesn't work
$server_name = "localhost";
$username = "root";
$password = "admin";
$database_name = "uvatravelclone";
$file = basename($_POST["file_open"]);
//$cmd = "mysql -h {$server_name} -u {$username} -p{$password} {$database_name} $file";
$cmd = "mysql -e {$file}";
if (exec($cmd) == true){
echo "succes";
}
else{
echo " error";
}
i need to get the file name or file path of the data because i'm using
<input type=file>
to open the file.

When you use <input type="file" name="file_open">, the information about the uploaded file is put in $_FILES, not $_POST. The file contents are put into a temporary file, and $_FILES['file_open']['tmp_name'] contains the pathname to this temporary file. You can then redirect this to the mysql command, using < filename for shell input redirection.
$server_name = "localhost";
$username = "root";
$password = "admin";
$database_name = "uvatravelclone";
$file = $_FILES['file_open']['tmp_name']
$cmd = "mysql -h {$server_name} -u {$username} -p{$password} {$database_name} < $file";
if (exec($cmd)){
echo "success";
}
else{
echo " error";
}
Note that the return value of exec() is the last line of output of the command, not a true/false value that indicates success.

Things to be known, when you have a type=file in your HTML Form, its necessary to use method="post" and enctype="multipart/form-data"
Example
<form method="post" enctype="multipart/form-data">
<input type="file" name="filename" />
<button>Upload Now</button>
</form>
Render Using PHP
<?php
$getFile = $_FILES["filename"];
var_dump($getFile); //Prints uploaded file details
//Use copy or move_uploaded_file to store the uploaded file on server
//its always better to use move_uploaded_file for the purpose.
?>
Know more it in this link http://www.w3schools.com/php/php_file_upload.asp.

+1 to Barmar's answer, but here's another tip: exec() can fetch the exit status of the command you execute, and this is a more accurate indicator of success or failure.
Traditionally, when a command has an exit status of 0 it means success, and any nonzero value means some error.
exec($cmd, $output, $exitStatus);
if (0 == $exitStatus)){
echo "success";
}
else{
echo " error";
}
See http://php.net/manual/en/function.exec.php

Related

Mysqldump is created after headers are sent [duplicate]

Here's the information I have:
I am working with a Linux based system using MySQL and PHP5. I need to be able to generate a mysqldump from within a .php file, and then have that dump be stored in a file on the server in a location I would specify.
As I'm a PHP nooblet, I'd like someone to give me some assistance, guidance, or code, that would do what I require. This would have to be run remotely from the Internet.
You can use the exec() function to execute an external command.
Note: between shell_exec() and exec(), I would choose the second one, which doesn't return the output to the PHP script -- no need for the PHP script to get the whole SQL dump as a string : you only need it written to a file, and this can be done by the command itself.
That external command will :
be a call to mysqldump, with the right parameters,
and redirect the output to a file.
For example :
mysqldump --user=... --password=... --host=... DB_NAME > /path/to/output/file.sql
Which means your PHP code would look like this :
exec('mysqldump --user=... --password=... --host=... DB_NAME > /path/to/output/file.sql');
Of course, up to you to use the right connection information, replacing the ... with those.
If you want to create a backup to download it via the browser, you also can do this without using a file.
The php function passthru() will directly redirect the output of mysqldump to the browser. In this example it also will be zipped.
Pro: You don't have to deal with temp files.
Con: Won't work on Windows. May have limits with huge datasets.
<?php
$DBUSER="user";
$DBPASSWD="password";
$DATABASE="user_db";
$filename = "backup-" . date("d-m-Y") . ".sql.gz";
$mime = "application/x-gzip";
header( "Content-Type: " . $mime );
header( 'Content-Disposition: attachment; filename="' . $filename . '"' );
$cmd = "mysqldump -u $DBUSER --password=$DBPASSWD $DATABASE | gzip --best";
passthru( $cmd );
exit(0);
?>
Take a look here: https://github.com/ifsnop/mysqldump-php ! It is a native solution written in php.
You can install it using composer, and it is as easy as doing:
<?php
use Ifsnop\Mysqldump as IMysqldump;
try {
$dump = new IMysqldump\Mysqldump('database', 'username', 'password');
$dump->start('storage/work/dump.sql');
} catch (\Exception $e) {
echo 'mysqldump-php error: ' . $e->getMessage();
}
?>
It supports advanced users, with lots of options copied from the original mysqldump.
All the options are explained at the github page, but more or less are auto-explicative:
$dumpSettingsDefault = array(
'include-tables' => array(),
'exclude-tables' => array(),
'compress' => 'None',
'no-data' => false,
'add-drop-database' => false,
'add-drop-table' => false,
'single-transaction' => true,
'lock-tables' => false,
'add-locks' => true,
'extended-insert' => true,
'disable-foreign-keys-check' => false,
'where' => '',
'no-create-info' => false
);
For security reasons, it's recommended to specify the password in a configuration file and not in the command (a user can execute a ps aux | grep mysqldump and see the password).
//create a temporary file
$file = tempnam(sys_get_temp_dir(), 'mysqldump');
//store the configuration options
file_put_contents($file, "[mysqldump]
user={$user}
password=\"{$password}\"");
//execute the command and output the result
passthru("mysqldump --defaults-file=$file {$dbname}");
//delete the temporary file
unlink($file);
Here you can find a comprehensive solution to dump mysql structure and data like in PMA (and without using exec, passthru etc.):
https://github.com/antarasi/MySQL-Dump-with-Foreign-keys
It is fork of dszymczuk project with my enhancements.
The usage is simple
<?php
//MySQL connection parameters
$dbhost = 'localhost';
$dbuser = 'dbuser';
$dbpsw = 'pass';
$dbname = 'dbname';
//Connects to mysql server
$connessione = #mysql_connect($dbhost,$dbuser,$dbpsw);
//Set encoding
mysql_query("SET CHARSET utf8");
mysql_query("SET NAMES 'utf8' COLLATE 'utf8_general_ci'");
//Includes class
require_once('FKMySQLDump.php');
//Creates a new instance of FKMySQLDump: it exports without compress and base-16 file
$dumper = new FKMySQLDump($dbname,'fk_dump.sql',false,false);
$params = array(
//'skip_structure' => TRUE,
//'skip_data' => TRUE,
);
//Make dump
$dumper->doFKDump($params);
?>
works like a charm :-)
MajorLeo's answer point me in the right direction but it didn't worked for me. I've found this site that follows the same approach and did work.
$dir = "path/to/file/";
$filename = "backup" . date("YmdHis") . ".sql.gz";
$db_host = "host";
$db_username = "username";
$db_password = "password";
$db_database = "database";
$cmd = "mysqldump -h {$db_host} -u {$db_username} --password={$db_password} {$db_database} | gzip > {$dir}{$filename}";
exec($cmd);
header("Content-type: application/octet-stream");
header("Content-Disposition: attachment; filename=\"$filename\"");
passthru("cat {$dir}{$filename}");
I hope it helps someone else!
As long as you are allowed to use exec(), you can execute shell commands through your PHP code.
So assuming you know how to write the mysqldump in the command line, i.e.
mysqldump -u [username] -p [database] > [database].sql
then you can use this as the parameter to exec() function.
exec("mysqldump -u mysqluser -p my_database > my_database_dump.sql");
Well, you can always use PHP's system function call.
http://php.net/manual/en/function.system.php
http://www.php.net/manual/en/function.exec.php
That runs any command-line program from PHP.
<?php
exec('mysqldump --all-databases > /your/path/to/test.sql');
?>
You can extend the command with any options mysqldump takes ofcourse. Use man mysqldump for more options (but I guess you knew that ;))
global $wpdb;
$export_posts = $wpdb->prefix . 'export_posts';
$backupFile = $_GET['targetDir'].'export-gallery.sql';
$dbhost=DB_HOST;
$dbuser=DB_USER;
$dbpass=DB_PASSWORD;
$db=DB_NAME;
$path_to_mysqldump = "D:\xampp_5.6\mysql\bin";
$query= "D:\\xampp_5.6\mysql\bin\mysqldump.exe -u$dbuser -p$dbpass $db $export_posts> $backupFile";
exec($query);
echo $query;
To dump database using shell_exec(), below is the method :
shell_exec('mysqldump -h localhost -u username -ppassword databasename | gzip > dbname.sql.gz');
None of the above codes worked for me. I am using windows.
Below Code worked for me...
$sql = "SELECT * FROM $tableName WHERE yourclause";
$result = $conn->query($sql);
if($result){
if ($result->num_rows > 0) {
$myfile = fopen("daily_events_$district.sql", "w") or die("Unable to open file!");
while($row = $result->fetch_assoc()) {
$rowToString = implode("','",$row);
$writeToFile = "INSERT INTO $tableName VALUES('$rowToString');". PHP_EOL;
fwrite($myfile,$writeToFile);
}
echo "File saved successfully";
}
} else {
echo "No result found";
}
This will save file in your project folder according to your query whatever data you want.
<?php
$toDay = date('d-m-Y');
$dbhost = "localhost";
$dbuser = "YOUR DB USER";
$dbpass = "USER PASSWORD";
$dbname = "DB NAME";
exec("mysqldump --user=$dbuser --password='$dbpass' --host=$dbhost $dbname > /home/....../public_html/".$toDay."_DB.sql");
?>

How to confirm mysql database backup using mysqldump in PHP

Here is my code:
<?php
$backupfile = 'bkp_dbcreditors_' . date("Y-m-d-H-i-s") . '.sql';
$command = "C:\wamp\bin\mysql\mysql5.6.17\bin\mysqldump -u root -pare048 dbcreditors > $backupfile";
system($command);
echo "Backup taken.";
exit();
?>
Is there a way to confirm that backup is not taken, if such happens?
Read the return value of the system($command). http://php.net/manual/en/function.system.php
It returns false on failure.

Trouble with mysqldump when backing up db as xml

I'm trying to backup one of my databases with mysqldump and I'm trying to export it to an xml file which already exists. Here is what I have:
<?php
$dbUser = 'user'; // db User
$dbPass = 'pass'; // db User Password
$dbName = 'db'; // db name
$dest = $_SERVER['DOCUMENT_ROOT'] . 'backup'; // Path to directory
class MySQLDump {
private $cmd;
function MySQLDump($dbUser,$dbPass,$dbName,$dest) {
$fname = $dbName.'.xml';
$this->cmd='mysqldump -X -u'.$dbUser.' -p'.$dbPass.' '.$dbName.
' >'.$dest.'/'.$fname;
}
public function backup() {
system($this->cmd, $error);
if($error) {
trigger_error ('Backup failed: ' . $error . '<br />Attempted: ' . $this->cmd);
}
}
} // end class def
$mysqlDump = new MySQLDump($dbUser, $dbPass, $dbName, $dest);
$mysqlDump->backup();
?>
This always generates the error thrown in the backup function. Here is a sample of $cmd's output:
mysqldump -X -udan -pdanPass danDB >/var/www/prod/dan/web/backup/danDB.xml
Any idea what's going wrong? I've never really used mysqldump so I'm not sure if I'm approaching this correctly. Any help is greatly appreciated.
try adding a space between -u and your $dbUser.
According to Does mysqldump return a status? something is going wrong, yes. We can not say if a warning or an error because you didn't share the return code.
Apart from that you can easily learn what exactly goes wrong by looking into STDERR output returned from the mysqldump command. E.g. you can pipe it into database.err:
mysqldump -X -udan -pdanPass danDB >/path/to/backup/danDB.xml 2>database.err
^^^^^^^^^^^^^^
This one work for me
mysqldump --user=xxx --password=xxx databasename --xml > file.xml

php fails to restore backup sql

i'm creating a restore database script in php but its not working. this is the code so far
<form action = '' method = 'POST'>
<h2>Restore</h2>
<table>
<tr><td><input type=file name="file"></td></tr>
<tr><td><input type = 'submit' name = "restore" value="restore"></tr></td>
</table>
</form>
<?php
$host = 'localhost';
$user = 'root';
$pass = ' ';
$dbname = 'itravel';
//date_default_timezone_set('Asia/Kuala_Lumpur');
//$currentdate = date('YmdGis');
$restore_name = $_POST['file'];
$custompath = $_POST['path'];
if(isset($_POST['restore']))
{
$restore = "c:/xampp/mysql/bin/mysql -h $host -u $user $dbname < $backup_name";
system($restore);
}
?>
nothing happening after clicking the restore button. please help
$restore = "c:/xampp/mysql/bin/mysql -h $host -u $user $dbname < $backup_name";
^^^^^^^^^^^
nowhere do you define $backup_name. Shouldn't it be $restore_name?
Uploads also do not appear in $_POST. They show up via $_FILES.
You should also NEVER assuming an upload succeeded. Especially for a mysql dump file. It is possible that the upload was truncated, yet you blindly feed the file back into MySQL, which could leave you with a partially/totally trashed database.
ALWAYS check for upload errors:
if ($_FILES['files']['error'] !== UPLOAD_ERR_OK) {
die("Upload failed with error " . $_FILES['files']['error']);
}
$restore_name = $_FILES['files']['tmp_name']; // temp file PHP stores upload in

MySQL backup doesn't work

I am trying to backup a MySQL database called Reserveboxto a .gzip file. I got this script from a tutorial, and I changed the values according to my values. The problem is when I click submit nothing happens. I do not know where did I go.
<form id="form1" name="form1" method="post" action="backup.php">
<input type="submit" name="Backup" id="Backup" value="Backup" />
</form>
<p> </p>
<?php
include ("functions_cp/f_connection.php");
Sqlconnection();
$dbname = "Reservebox";
$dbhost = "localhost";
$dbuser = "root";
$dbpass = "123";
function backup() {
$backupFile = $dbname . date("Y-m-d-H-i-s") . '.gz';
$command = "mysqldump --opt -h $dbhost -u $dbuser -p $dbpass $dbname | gzip > $backupFile";
system($command);
}
if(isset($_POST['backup'])) {
backup();
}
if(isset($_POST['backup'])) {
I think the backup on this line needs a capital B!
If that doesn't sort it, try adding error_reporting(E_ALL); on a new line after <?php.
Try removing the space between the -p and $dbpass.
Also, remove --opt. That is not strictly necessary.

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