Disable errors when getting postal code using ipapi.co [closed] - php

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I'm retrieving the postal code by using -
<?php $pstcde = file_get_contents('https://ipapi.co/'.$_SERVER['REMOTE_ADDR'] . '/postal/'); ?>
It works great but if the postal code is not found, it says, "None". I can't find a way to disable the message.

You can empty the variable if the respond is None. With a simple check.
<?php
$pstcde = file_get_contents('https://ipapi.co/'.$_SERVER['REMOTE_ADDR'] . '/postal/');
if($pstcde === "None")
$pstcde = ""; //Empty string. Or you can use unset($pstcde); if you want to unset the variable.
?>

Related

isset($_SESSION['id']) is not working properly [closed]

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Closed 6 years ago.
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I am trying to use the condition:
isset($_SESSION['id'])
So i just tried
echo isset($_SESSION['id']); and echo $_SESSION['id'];
But this gives output different. In fact true result gives by
echo $_SESSION['id'];
Any one have idea why this is happening?
Note: I use session_start(); at the beginning of page.
isset is used in if condition, in case you want to check if session is set or not:
<?php
if(isset($_SESSION['id'])) { // check if session named 'id' is exist
echo $_SESSION['id'];
}
?>

Cannot put $url; on "define" PHP [closed]

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Closed 7 years ago.
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Im newbie in php im learning it since some weeks ago but i didnt understand one thing.
I have a
$url = "http://example.com/";
define('LOCATION', '<?php echo $url; ?>');
but it is not working. I didnt understand why "define" term cannot read
<?php
$url = "http://example.com/";
define('LOCATION', $url);
1.You are alreay in php tag,so no need of any extra php tag.
2.And when assigning value to a variable , we never use echo in php . Its used to display value in html only.

How to access $_Get variable in PHP based on another input value [closed]

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Closed 8 years ago.
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I need to access the input value of a dynamic variable based on another input field.
Sample code:
$upid=$_GET['upid'];
$check_box_name='c'.$upid;
echo $upid;
$check=$_GET[$check_box_name];
any idea how do i access it??...Please help
The code you entered should work, but, it is vulnerable to errors, as you are dealing with a user input, you should either do a validation or a failover value.
If you are using PHP5.3+, you can easily do this as follows:
if ($check = #$_GET['c' . (#$_GET['upid'])]? : false !== false) {
//do something with $check
} else {
//failed
}
The # sign is used to omit any error or exception from being thrown. Also, it maybe a good thing to escape the $check variable for more security.

find and replace special characters in PHP [closed]

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Closed 8 years ago.
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Please tell me how to do a find and replace in PHP.
I nee to find Entry="OK" and replace with OK in a xml file.
I tried str_replace but confused because of the = and " in it.
Even though I'm not sure of the environment you're working in, here's a php sample that I think does what you want:
<html>
<?php
$teststr = "Entry=\"OK\"";
print $teststr . "<br>";
$newanswer = str_replace($teststr, "Entry=OK", $teststr);
print $newanswer . "<br>";
?>
</html>
Try this way
str_replace('Entry="OK"','OK',$var);
You can use str_replace its working
$r = 'Entry="OK" tyyuu hhh';
echo str_replace($r,'Entry="OK"','OK');
if any error found then u use preg_replace with corresponding patteren

Add text directly next to PHP variable? [closed]

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Closed 8 years ago.
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I have a variable inside an inline style -
style='color:$custom_color;font-size:$custom_icon_size;'
And am trying to add the letters px directly after the $custom_icon_size. This obviously does not work? Any ideas what is the correct method?
thanks
you need to use {} around your PHP vaariable
style='color:$custom_color;font-size:${custom_icon_size}px;'
Assuming that you're echoing it, you have two options:
echo "style='color:$custom_color;font-size:{$custom_icon_size}px;'";
echo "style='color:" . $custom_color . ";font-size:" . $custom_icon_size . "px;'";
$style = 'color:'.$custom_color.'; font-size: '.$custom_icon_size.'px';
echo 'style="'.$style.'"';

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