how to create table with dynamic column using php - php

Question

Suppose there is a number of item in array.which may be odd or even like I have an array which contain item from a to z Now I want to display that item in table . But As you know That There are 23 alphabets I want to display these alphabets in table which contains only 5 column in the last you got only three alphabets I want to display them in table . In the last I want that there should be three column not 5.
Here is my code i could not get that what should i do?
But the problem I faced in the below code is that the second loop is not correct.
<?php
$arr=array('a','b','c','d','e','f','g','h');
$count= sizeof($arr);
$row=ceil($count/5);
echo "<table border='1'>";
for($r=0;$r<$row;$r++){
echo "<tr>";
for($j=0;$j<=5;$j++){
echo "<td>'".$arr[$j]."'</td>";
}
echo "</tr>";
}
echo "</table>";
?>

Answer 1

My approach uses array_slice to take out pieces of the source and build rows:
$arr=array('a','b','c','d','e','f','g','h');
$offset = 0;
$num_columns = 5; //adjust number of columns
$table_html = "<table border='1'>";
while($slice = array_slice($arr,$offset,$num_columns)){
$offset += $num_columns;
$row_html = '';
foreach($slice as $n) $row_html .= "<td>$n</td>";
$table_html .= "<tr>$row_html</tr>";
}
$table_html .= '</table>';
echo $table_html;
Live demo

Answer 2

Try below code. Declaring number of column required in a variable, so which can be changed any time. closing the tr tag when loop count is same as number of columns to be displayed.
<?php
$arr=array('a','b','c','d','e','f','g','h');
$columnLength = 5;
echo "<table border='1'>";
echo "<tr>";
for($r=0;$r<count($arr) ; $r++){
echo "<td>'".$arr[$r]."'</td>";
if($r + 1 == $columnLength ) {
echo "</tr>";
}
}
echo "</table>";
?>