Filter string from inside an array - php

Question

I tried this:-
function sum_array($arr_sum){
$string= "";
$length= count($arr_sum);
$sum= NULL;
if(is_string($arr_sum)){
echo "You cannot use string";
}else{
for($i=0; $i<$length; $i++){
$sum = $sum + $arr_sum[$i];
}
echo " The Sum is ". $sum;
}
}
$array_summation=["string",12.6,25.2,10,12];
sum_array($array_summation);
I want to know what should i do if i want only integer or float value inside an array, and if string come inside array it gives error that no string wanted or something like that

Answer 1

Use array_map to get the type of each value present in the array -
$type = array_map('gettype', $array_summation);
if (!empty($type) && in_array('string', $type) {
echo "You can't use string.";
}

Answer 2

Try this
function sum_array($arr_sum){
$sum = 0;
foreach($arr_sum as $value){
if(!is_numeric($value)){
echo 'Array Contain non numeric data';
exit;
}
$sum += $value;
}
echo 'The sum is '.$sum;
}
$array_summation=["string",12.6,25.2,10,12];
sum_array($array_summation);

Answer 3

PHP has a built-in array_sum function, which ignores non-numeric strings.
$arr = [1,2,'3','apple'];
var_dump(array_sum($arr)); // int(6)
Or if you really need them to produce an error you can use array_map:
function sum_array($arr) {
if (array_sum(array_map('is_numeric', $arr)) !== count($arr)) {
echo "You cannot use string";
return;
}
echo array_sum($arr);
}
sum_array([1,2,'3','apple']); // You cannot use string
sum_array([1,2,'3','5.2']); // 11.2
Or if you want to make sure that all values in the array are either floats or integers, and not numeric strings, you can do:
function is_non_string_number($n) {
return is_float($n) || is_int($n);
}
function sum_array($arr) {
if (array_sum(array_map('is_non_string_number', $arr)) !== count($arr)) {
echo "You cannot use string";
return;
}
echo array_sum($arr);
}
sum_array([1,2,'3','apple']); // You cannot use string
sum_array([1,2,'3','5.2']); // You cannot use string
sum_array([1,2,3]); // 6