Disable radio button based on PHP function - php

Question

I want to call the javascript function based on the result coming from a PHP script.
if ($verify == 'Y' and $approve== 'Y' and $approve_2=='Y') {
$state = "disable";
} else {
$state = "undisable";
}
Below is my javascript function
function disable() {
document.getElementById("approvedd1").disabled = true;
document.getElementById("approvedd2").disabled = true;
}
function undisable() {
document.getElementById("approvedd1").disabled = false;
document.getElementById("approvedd2").disabled = false;
}
document.onreadystatechange = <?php echo $state; ?>()
This does not work.
I want to call function that can disable radio button, when the page has loaded.

Answer 1

The current output of your java script will be
function disable() {
document.getElementById("approvedd1").disabled = true;
document.getElementById("approvedd2").disabled = true;
}
function undisable() {
document.getElementById("approvedd1").disabled = false;
document.getElementById("approvedd2").disabled = false;
}
document.onreadystatechange = disabled/undisabled()
better you can try
php
if ($verify == 'Y' and $approve== 'Y' and $approve_2=='Y') {
$state = "true";
} else {
$state = "false";
}
Java Script
document.onreadystatechange = MyFun() {
document.getElementById("approvedd1").disabled = <?php echo $state; ?>;
document.getElementById("approvedd2").disabled = <?php echo $state; ?>;
}