Hi im trying to use this date picker but i want it to allow user to only pick between two dates from php variables min is the earliest pickable date and max is the latest this is one variant of what i have tried but none have worked so far.
Any help is apreciated in advance
<form>
<label>
Choose your preferred party date (required, April 1st to 20th):
<input type="date" name="party" min="<?= echo date($minLanding)>" max="<?= echo date($maxLanding)>" required>
<span class="validity"></span>
</label>
<p>
<button>Submit</button>
</p>
</form>
You're using the shorthand echo syntax <?= and echo together. Use one or the other. Also note that the proper closing tag is ?>. And you'll likely have to provide a date format, though I'm not sure which off the top of my head.
<?= date('Y-m-d', $minLanding) ?>
Or:
<?php echo date('Y-m-d', $minLanding) ?>
If your values are already formatted dates:
$Today = date('y:m:d')
$minLanding = Date('y:m:d', strtotime('+14 days'));
$maxLanding = Date('y:m:d', strtotime('+9 months'));
Then just:
<input type="date" min="<?= $minLanding ?>" max="<?= $maxLanding ?>">
But note I think you'll have to use Y-m-d as the format instead of y:m:d.
I have an HTML form that has a date input as below
<div class="col-sm" id="old">
<label for="startDateOld">Current Start Date</label>
<input type="date" class="form-control" id="startDateOlds" name="startDateOld" readonly value="<?php echo $startDate; ?>">
</div>
When the page loads, it is actually querying the startDate into a php variable called $startDate. I need this $startDate to be shown in my date input field. But somehow it is not showing anything.
In my MySQL database, this date is a timestamp. I format it the following php way to match the HTML date input
$startDate = date('Y/m/d', strtotime($startDate));
But somehow it is not loading the date value although $startDate contains a value in YYYY/MM/DD format which matches HTML date input format.
Does anyone know why I can't show the date value?
HTML date inputs need to be in YYYY-MM-DD form, not YYYY/MM/DD (see the manual). So change your:
$startDate = date('Y/m/d', strtotime($startDate));
to
$startDate = date('Y-m-d', strtotime($startDate));
and it should work fine.
Demo of YYYY-MM-DD and YYYY/MM/DD format in HTML:
<div class="col-sm" id="old">
<label for="startDateOld">Current Start Date</label>
<input type="date" class="form-control" id="startDateOlds" name="startDateOld" readonly value="2020-01-16"><br/>
<label for="startDateOld2">Current Start Date</label>
<input type="date" class="form-control" id="startDateOlds" name="startDateOld2" readonly value="2020/01/16">
</div>
I try to show a standard date as value in my date type input field. For some reason they way I thought it would work doesn't work, already searched on google and stackoverflow for any solutions but couldn't really find anything. Maybe you guys have an idea? It is now like this , and I want to have it like this.
My code:
<?php $date = "1996-06-25";
$newDate = date("d-m-Y", strtotime($date)); ?>
<input type="date" name="date" value="<?php echo date($newDate);?>">
You need to change the date format, so try following
<?php $date = "1996-06-25";
$newDate = date("Y-m-d", strtotime($date)); ?>
<input type="date" name="date" value="<?php echo $newDate;?>">
Edited
Your current date format is not correct that's why it does not working.
#AniketSahrawat Thank you for letting me know. I modified my answer after your comment
The date format is wrong, try this out :
<?php
$date = "25-06-1996";
$newDate = date("Y-m-d", strtotime($date)); ?>
<input type="date" name="date" value="<?php echo $newDate; ?>">
Edit
Here's the proof that it works
The format like I said should be Y-m-d
I tried this:
<input type="datetime-local" value="<?php echo $row['Time']; ?>" class="date" name="start" REQUIRED>
How can I set the value of this input field with the data from the database?
It doesn't work!!
I need to make it possible to edit too.
Or should I use another type of input?
$row['Time'] is from the database!
I don't know exacly what is in $row['Time'] but it should be as follows:
Definition
A valid date-time as defined in RFC 3339 with these
additional qualifications:
the literal letters T and Z in the date/time syntax must always be uppercase
the date-fullyear production is instead defined as four or more digits representing a number greater than 0
Examples
1990-12-31T23:59:60Z
1996-12-19T16:39:57-08:00
Solution
To create RFC 3339 format in PHP you can use:
echo date('Y-m-d\TH:i:sP', $row['Time']);
or in another way:
echo date("c", strtotime($row['Time']));
or if you prefer objective style:
echo (new DateTime($row['Time']))->format('c');
In your code
So in your code it would look as follows:
<input type="datetime-local" value="<?php echo date('Y-m-d\TH:i:sP', $row['Time']); ?>" class="date" name="start" REQUIRED>
or
<input type="datetime-local" value="<?php echo date("c", strtotime($row['Time'])); ?>" class="date" name="start" REQUIRED>
Manual
More informations can be found here
PHP date Manual
PHP DateTime Manual
When submitting <form> using <input type="datetime-local">
the value format you will get is look like this.
2019-09-06T00:21
To set new value in your input type box.
You must use:
date('Y-m-d\TH:i', strtotime($exampleDate)) //2019-08-18T00:00
Solution Example:
$exampleDate = "2019-08-18 00:00:00"; //sql timestamp
$exampleDate = strtotime($exampleDate); //convert to unix timestamp
$newDate = date('Y-m-d\TH:i', $exampleDate); //format unix to date
or
$exampleDate = "2019-08-18 00:00:00";//sql timestamp
$newDate = date('Y-m-d\TH:i', strtotime($exampleDate));
If you don't use strtotime() you will get an error of
Notice: A non well formed numeric value encountered
**Tested**:
- $exampleDate = 2019-08-18 00:00:00 ;
- //Not Working - output(1970-01-01T01:33:39)
- <?php echo date('Y-m-d\TH:i:s', $exampleDate);?>
- //Not Working - output(1970-01-01T01:33:39+01:00)
- <?php echo date('Y-m-d\TH:i:sP', $exampleDate);?>
- //Not Working - output(2019-08-18T00:00:00+02:00)
- <?php echo date("c", strtotime($exampleDate));?>
- //Not Working - output(2019-09-23T19:36:01+02:00)
- <?php echo (new DateTime($row['Time']))->format('c');?>
- //Working Perfect - output(2019-08-18T00:00:00)
- <?php echo date('Y-m-d\TH:i:s', strtotime($exampleDate));?>
it's simple is that and working for me
first convert your php value to this format
<?php $datetime = new DateTime($timeinout[0]->time_in); ?>
then in value of html input element
use this format
<input type="datetime-local" id="txt_time_in" placeholder="Time In" name="timein" value = "<?php echo $datetime->format('Y-m-d\TH:i:s'); ?>" class="form-control" />
this will set your value to input element
The answer of Karol Gasienica is a great explanation but somehow did not work for me even in their replies
date('Y-m-d\TH:i:s', $row['Time']); //Gives me 1970-01-01 00:00
date('Y-m-d\TH:i:sP', $row['Time']); //Gives me no display
date("c", strtotime($row['Time'])); //No display too
What worked for me is this
$t = $row['Time'];
date('Y-m-d\TH:i:s', strtotime($t)); // This got it perfectly
However I still voted it up becauce of the explanation.
None of the above solutions worked for me as of 2019 using Google Chrome Version 78.0.3904.70 (Official Build) (64-bit)
What worked for me is.
<input type="datetime-local" value="2017-06-13T13:00">
As you can see the format is 2017-06-13T13:00 or Y-m-dTH:i.
As of PHP you can do like.
<input type="datetime-local" value="<?php echo Date('Y-m-d\TH:i',time()) ?>">
Hope this will save someone's time. :)
You can use
date('Y-m-d\TH:i'); //Example result: '2017-01-01T01:01'
if use \T instead of T (not working)
date('Y-m-dTH:i'); //Example result: '2017-01-01UTC01:01'
Better use timezone feature
function getCurrentDateTime(){
$date = new DateTime();
$date->setTimezone(new DateTimeZone('GMT+6')); //Time Zone GMT +6
$dt= $date->format('Y-m-d\TH:i:s');
return $dt;
}
Try that. I get that in Bootstrap 4. (Google Translate: prueba con eso, a mi me sale con eso en Bootstrap 4. )
<input class="form-control" type="datetime-local" name="fecha_e" id="fecha_e" value="
<?php echo date('Y-m-d\TH:i', strtotime($data['fecha_e_tarea'])); ?>" required>
The simple way working for me is
<input type="datetime-local" value="<?= str_replace(' ', 'T', $date) ?>" name="date" required />
Easiest way! Here's how to set a value using php for input field with type="datetime-local"
setting value using php in type="datetime-local"
$date_now_time = date("Y-m-d H:i:s", strtotime('+5 hours'));
$from_for_val= date("Y-m-d\TH:i:s", strtotime($date_now_time));
Below is html form input field with type="datetime-local" and its showing how to set value inside input field
<input type="datetime-local" name="submit_from" value="<?=$from_for_val;?>" >
$tripid=$_REQUEST['tripid'];
$sql="SELECT * FROM tripdetails WHERE trip_id='".$tripid."'";
$trpresult=mysqli_query($connect,$sql);
if(mysqli_num_rows($trpresult)==1)
{
$trpdetails=mysqli_fetch_assoc($trpresult);
}
$trpstartdate = substr_replace($trpdetails['trip_start_date'],T,11,0);
$string = preg_replace('/\s+/', '', $trpstartdate);
This is Html part
<input type="datetime-local" name="trip_start_date" id="cal" value="<?php echo $string?>">
This will convert datetime from database to datetime-local
str_replace(" ","T",substr_replace($string ,"", -3))
Try it:
<input type="datetime-local" value="<?php $row['Time'] = preg_replace("/\s/",'T',$row['Time']); echo $row['Time']?>" class="date" name="start" REQUIRED>
for everybody on 2021 the working format is Y-m-d\TH:i
all other old format is just a hussel.
if you are using carbon library
\Carbon\Carbon::parse($data->chosen_date,$timezone)->format('Y-m-d\TH:i')
after that you can just pass to value like this
if are using ajax or fetch api
document.getElementById('chosen_date').value = data.chosen_date
I'm creating a form with two date selectors. Currently, they look like:
<input type="date" class="form-control" name="contract_start" value="<?php echo $contract_start; ?>">
<input type="date" class="form-control" name="contract_end" value="<?php echo $contract_end; ?>">
Right now, on the form, the default values for the date selectors just say "mm/dd/yyyy". I'd like to know how I can alter this so that the contract_start input is the current date, and the contract_end input is 10 months from the current date by default. How can I do this?
Just set $contract_end to: date('m/d/Y', strtotime('+10 months', strtotime($contract_start)))
First strtotime call will convert raw date to timestamp, second will add ten months to your timestamp, and date function will format it back.
Strtotime reference
Date reference
You can use a single strtotime() function also in date function like this :
<?php
$contract_start = date('Y-m-d');
$contract_end = date('Y-m-d', strtotime($contract_start.' +10 months'));
?>
<input type="date" class="form-control" name="contract_start" value="<?=$contract_start;?>">
<input type="date" class="form-control" name="contract_end" value="<?=$contract_end;?>">