So I have a PHP form that seems to only want to work sometimes. I really don't understand what is wrong with it or why. I will submit test data successfully, but 5 minutes later I will do another test and I get the error message.
I'm not an PHP or SQL expert so help me out!
<?php
$host="localhost"; // Host name
$username="user"; // Mysql username
$password="pass"; // Mysql password
$db_name="database"; // Database name
$tbl_name="table"; // Table name
// Connect to server and select database.
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");
// Get values from form
$title=$_POST['title'];
$body=$_POST['body'];
$date=$_POST['date'];
$tags=$_POST['tags'];
// Insert data into mysql
$sql="INSERT INTO $tbl_name(title, body, date, tags)VALUES('$title', '$body', '$date', '$tags')";
$result=mysql_query($sql);
// if successfully insert data into database, displays message "Successful".
if($result){
echo "Successful";
echo "<BR>";
echo "<a href='insert.php'>Back to main page</a>";
}
else {
echo "ERROR";
}
?>
<?php
// close connection
mysql_close();
?>
Thank you!
Louie
For first enable error reporting:
ini_set('display_errors', 1);
ini_set('display_startup_errors', 1);
error_reporting(E_ALL);
And check what's going on in your code.
Maybe problem is not in PHP but in MySQL Server.
Related
I am trying to delete an item from my database but it isnt working.
I thought I had it working but it was deleting the first item in the database but not the item selected.
Here is what I have.
A link to delete.php then I have this for delete.php
<?php
ob_start();
include_once('../mysql_connect.php');
// contact to database
$host = "localhost";
$username = "admin";
$password = "password";
$database="database";
$tbl_name="new_equip";
// Connect to server and select databse.
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$database")or die("cannot select DB");
// get value of id that sent from address bar
$id=$_GET['id'];
// Delete data in mysql from row that has this id
$sql="DELETE FROM $tbl_name WHERE id='$id'";
$result=mysql_query($sql);
// if successfully deleted
if($result){
echo "Deleted Successfully";
echo "<BR>";
echo "<a href='inventory.php'>Back to main page</a>";
}
else {
echo "ERROR";
}
?>
I know this is probably something simple and I have been searching and trying everything I can find, but I cannot seem to get it working. I believe the delete.php link needs to have the item number in it. Here is what the link is
"delete.php?id=<?php echo $eid; ?>"
I also have this on the top of the delete.php
<?php
$eid = (int) $_GET['id'];
if ($eid < 1)
?>
Do not put the GET directly in your variable that might cause SQL Injections
Do not use mysql... use mysqli instead!
Format your code more
Than back to the main problem:
Echo your $id to see if it is the correct one ;) I could not see some other problem at your code.
I know this has been asked hundreds of times, however, I couldn't find how this specific error applied to many of the other examples.
I have many form fields on a PHP page and they update into my database just fine when I hit submit, until I use http://somewebsite.net in one of the fields.
The field I post my form, field flightaware is posted to bijwerkvlucht_post.php as flightaware='$flightaware'.
I do not get the above error message when I test with plain text or remove the http:// . Thus deducing that it is an issue related to http:// in the wording.
How would I fix the code to resolve this particular issue?
The code on the post page:
<?php
$host="localhost"; // Host name
$username="xxxxx"; // Mysql username
$password="xxxxx"; // Mysql password
$db_name="xxxxx"; // Database name
$tbl_name="tbl_vluchtgegevens"; // Table name
// Connect to server and select database.
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");
// update data in mysql database
$sql="UPDATE $tbl_name SET reisID='$reisID', vertrekdatum2='$vertrekdatum2',
vertrektijd='$vertrektijd', vertrektijdactueel='$vertrektijdactueel',
vertrekluchthaven='$vertrekluchthaven', aankomstdatum2='$aankomstdatum2',
aankomsttijd='$aankomsttijd', aankomstluchthaven='$aankomstluchthaven',
luchtvaartmaatschappij='$luchtvaartmaatschappij', toestel='$toestel',
inschrijvingnmr='$inschrijvingnmr', vluchttijd='$vluchttijd',
vluchttijddec='$vluchttijddec',reisklasse='$reisklasse', stoel='$stoel', prijs='$prijs',
vluchtnmr='$vluchtnmr', vluchttype='$vluchttype', upgrade='$upgrade',
boekingcode='$boekingcode', eticketnmr='$eticketnmr', farecode='$farecode',
flightaware='$flightaware', route='$route' WHERE gegevenID='$id'";
$result=mysql_query($sql);
// if successfully updated.
if($result){
echo "Successful";
echo "<BR>";
}
else {
echo "ERROR";
}
?>
Am not being able to get any information into my wamp server database nor will it display the welcome page below is my code can someone please tell me what am doing wrong or if my wamp maybe configured wrong?
php code below
<?
// Test if submit button was pressed
if (isset($_POST['sub_button'])) {
$fname=$_POST['fname'];
$lname=$_POST['lname'];
$sex=$_POST['sex'];
$address=$_POST['add'];
$email=$_POST['e_address'];
$years=$_POST['n_years'];
$favSong=$_POST['f_song'];
// Create the connection to the server
$db_host="localhost";
$db_username="root";
$db_password="";
$con=mysqli_connect($ db_host, $db_username, $db_passwod); // to connect to the database server
// to check the connection to the server
if(mysqli_connect_errno($con)) {
echo"Failed to connect to my SQL:" .mysqli_connect_errno();// if there is an error this shows up.
}
// this selects the database
mysqli.select_db($con, 'fan'); // ensure that the database has the same name as your created database.
//Insert Statement
//Values of fname, lname etc is the exact name spelling from the html file.
//Values of $title $fname are the values from the php which stores the variables name.
$sql="INSERT INTO information(fname, lname, sex, add, e_address, n_years, f_song)
VALUES('$fname','$lname','$sex','$address','$email','$years','$favSong')";
//Check if insert successful.
if(mysqli_query($con, $sql)) {
header("Location:welcome.html");
mysqli_close($con);
}
else
{
echo "Error;".mysqli_error($con);
}
}//closing the "IF isset" statement.
//php closing.
?>
After looking at my code over and over i notice i was missing
Correct code
<?php
?>
instead I had
<?
?>
I am have been trying to setup this code to delete a row on the mysql database as well as the photo that was uploaded with it. It is working GREAT to remove the row data, but it will not get rid of the photo, and I cannot figure out what I am doing wrong. To simplify things, im using the variable $id which is the number of the row entered in the form which triggers this php file:
<?php
$host="localhost"; // Host name
$username="blahblah_plans"; // Mysql username
$password="password"; // Mysql password
$db_name="blahtbl_name"; // Database name
$tbl_name="plans"; // Table name
// Connect to server and select databse.
$conn = mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");
// get value of id that sent from address bar
$id=$_GET['idnum'];
$compositesql="SELECT composite FROM plans WHERE ID ='$id'";
$compositeresult = mysql_query($compositesql) or die(mysql_error());
$compositefilename = "/composite/" + $compositeresult;
$unlink = unlink($compositefilename);
if($unlink) {
echo 'Successfully deleted file: ';
echo $compositefilename;
} else {
echo 'Error deleting file: ';
echo $compositefilename;
}
// Delete data in mysql from row that has this id
$sql="DELETE FROM $tbl_name WHERE ID ='$id'";
$result = mysql_query($sql);
if($result){
header("location:planentry.php");
}
else {
echo "ERROR";
}
?>
<?php
// close connection
mysql_close();
?>
Make sure the path is right, $compositefilename = "/composite/" + $compositeresult; should be the path in the server, it most likely to be
$compositefilename = PATH_TO_YOUR_WEB_ROOT . "/composite/" . $compositeresult;
And php does not use + to concat strings.
The problem is that $compositeresult contains a resource rather than a result set. This line is what's causing it:
$compositeresult = mysql_query($compositesql) or die(mysql_error());
To fix that, store the resource on a variable, then store the result set on another variable, like this:
$compositequery = mysql_query($compositesql) or die(mysql_error());
$compositeresult = mysql_fetch_array($compositequery) or die(mysql_error());
Also, I highly recommend that you start using mysqli or PDO instead of mysql, since it's safer. Also, as xdazz said, PHP's concatenation operator is the dot, not the plus sign. So your $compositefilename should be declared as (note that $compositeresult is an array of data and therefore should have its correct key explicitly written):
$compositefilename = "/composite/" . $compositeresult['composite'];
Hi there doing a small project with databases ( don't have too much experience with them). I'm working with mySQL and php, having a little bit of trouble with the php and posting the info from the HTML form to the database.
Here is the code:
<?php
$host=""; // Host name
$username=""; // Mysql username
$password=""; // Mysql password
$db_name=""; // Database name
$tbl_name="tags"; // Table name
// Connect to server and select database.
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");
// get data that sent from form
$s_name=$_GET['name'];
$s_system=$_GET['system'];
$s_cate=$_GET['cate'];
$sql="INSERT INTO $tbl_name(name,system,cate)VALUES('$s_name', '$s_system', '$s_cate')";
$result=mysql_query($sql);
if($result){
echo "Successful<BR>";
echo "<a href=mainforum.php>View your topic</a>";
}
else {
echo "ERROR";
}
mysql_close();
?>
If anyone could help explain to me what I am doing wrong, much would very be appreciated.
THANKS
Here is a link to what I am trying to do:
http://socialsoftware.purchase.edu/roger-p.king/database2/enter_gamertag.html
u should use $_POST['variable'], not $_GET
because $_GET is variables array on the link
such as "http://example.com/?var=123", the value of $_GET['var'] is 123
the variable in form can get by $_POST['var'] or $_REQUEST['var']
$query = mysql_query("INSERT INTO '$tbl_name'(name,system,cate)VALUES('$s_name', '$s_system', '$s_cate')";
That should do, or if you do it your way in 2 lines,
$sql="INSERT INTO '$tbl_name'(name,system,cate)VALUES('$s_name', '$s_system', '$s_cate')";
$result=mysql_query($sql);