I am using the following code to get the difference between two dates. I'm having issues with it returning the correct amount of days left.
<?php
$nextservicedate = FrmProDisplaysController::get_shortcode( array( 'id' => 3451 ) );
$currentdate = date("d/m/Y");
$daysremaining = $nextservicedate - $currentdate;
echo $nextservicedate. " | ";
if ( strpos($nextservicedate, 'None registered') !== false )
{
echo "None Registered";
}
elseif ($daysremaining < "0")
{
$negativedays = str_replace('-', ' ', $daysremaining);
echo $negativedays. " days overdue";
}
elseif ($daysremaining <= "30")
{
echo $daysremaining. " days (upcoming service)";
}
else
{
echo $daysremaining. " days";
}
?>
The entry
FrmProDisplaysController::get_shortcode( array( 'id' => 3451 ) )
returns a date from a wordpress form plugin (FormidablePro) as 30/10/2016.
The code is returning there are 23 days remaining which I believe is taking it to the end of this month.
I know I'm missing something and think it probably has something to do with the working out the days remaining part of the code.
Can anyone see any glaring errors? Do I need to declare the $nextservicedate like I've done with $currentdate?
Any help would be greatly recieved!
Regards
Matt
PHP's date() returns date string which cannot be used to perform arithmetic operations on date.
What you need to do is create DateTime object of service date from String using createFromFormat() and create current DateTime() object.
Then use diff() function of DateTime object to find the difference between two days.
So your code would look something like this,
$nextservicedate=DateTime::createFromFormat("d/m/Y",$nextservicedate);
$todaydate=new DateTime();
$difference=$nextservicedate->diff($todaydate);
To get the difference in days,
echo $difference->format('%R%a days');
Related
Using WIndows, XAMPP 5.6.8 I am building a simple web app in HTML and PHP.
I would like to compare a date retrieved from a database with today's date.
I have a function that successfully returns a string value (in the UK date format d-m-y).
My code so far is;
$expDate = get_api_data($id); // returns a string
var_dump($expDate); // this prints string(8) "31-12-19"
Using this $expDate value I would like to achieve something like;
if (strtotime('d-m-y', $expDate) > time()) { // if date > than today
echo 'date is greater than today';
}
elseif (strtotime('d-m-y', $expDate) < time()) { // if date < than today
echo 'date is less than today';
}
else {
echo 'date not found';
}
Currently I am receiving date is less than today - even though the date is 31-12-19. I'm not sure if I am approaching this the correct way?
Any help would be greatly appreciated as I have alreday spent a lot of time researching answers to no avail.
I got this error when executing your code
PHP Notice: A non well formed numeric value encountered
You should look at the doc in order to make a good usage of this function: http://php.net/manual/fr/function.strtotime.php
The first param should be a time, not a format.
By the way, i prefer use DateTime class to compare dates, you can do:
<?php
$expectedDate = \DateTime::createFromFormat('d-m-y', get_api_data($id));
$nowDate = new \DateTime();
if ($expectedDate > $nowDate) { // if date > than today
echo 'date is greater than today';
}
elseif ($expectedDate < $nowDate) { // if date < than today
echo 'date is less than today';
}
else {
echo 'date not found';
}
$formattedDate = DateTime::createFromFormat('d-m-y', $expDate);
$expDate= $formattedDate->getTimestamp();
if ($expDate > time()) { // if date > than today
echo 'date is greater than today';
.....
Try above code sample, try to use DateTime class if you have PHP 5.2.0 or higher http://php.net/manual/en/datetime.createfromformat.php . Then using that dateTime object you can do comparisons in a way you want e.g. in my sample I am doing it by time.
Your code will show a notice. if you turn on the php error reporting, you will observer it.
I'm a PHP beginner and been struggling unsuccessfully with the php documentation. Seems a lot of ways to do what I want.
Basically I need a php page to check an "ugly" date/time variable appended to a URL - it must convert it into a usable format and subtract it from the current date/time. If the result is less than 48hrs then the page should redirect to "Page A" otherwise it should redirect to "Page B"
This is what the URL and variable looks like.
http://mysite.com/special-offer.php?date=20130527212930
The $date variable is the YEAR,MONTH,DAY,HOUR,MINUTE,SECOND. I can't change the format of this variable.
I'm guessing PHP can't use that string as it is. So I need to split it somehow into a date format PHP can use. Then subtract that from the current server date/time.
Then put the result into an if/else depending on whether the result is more or less than 48hrs.
Am I right in theory? Can anyone help me with the "practise"?
Thanks!
Take a look at the DateTime class and specifically the createFromFormat method (php 5.3+):
$date = DateTime::createFromFormat('YmdHis', '20130527212930');
echo $date->format('Y-m-d');
You might need to adjust the format depending on the use of leading zeros.
PHP 5 >= 5.3.0
$uglydate = '20130527212930';
// change ugly date to date object
$date_object = DateTime::createFromFormat('YmdHis', $uglydate);
// add 48h
$date_object->modify('+48 hours');
// current date
$now = new DateTime();
// compare dates
if( $date_object < $now ) {
echo "It was more than 48h ago";
}
You can use a regular expression to read your string and construct a meaningful value.
for example
$uglydate = "20130527212930";
preg_match("/([0-9]{4})([0-9]{2})([0-9]{2})([0-9]{2})([0-9]{2})([0-9]{2})/", $uglydate, $matches);
$datetime = $matches[1] . "-" . $matches[2] . "-" . $matches[3] . " " . $matches[4] . ":" . $matches[5] . ":" . $matches[6];
//then u can use $datetime in functions like strtotime etc
Whoa! you all have WAY too much time on your hands... Nice answers... oh well, i'll pop-in a complete solution...
<?php
$golive = true;
if (preg_match('|^(\d{4})(\d{2})(\d{2})(\d{2})(\d{2})(\d{2})|', $_GET['date'], $matches)) {
list($whole, $year, $month, $day, $hour, $minute, $second) = $matches;
// php: mktime function (using parameters derived
$timestamp = mktime($hour,$minute,$second,$month,$day,$year);
$diff = time()-$timestamp;
$diffInHours = $diff / 3600 ;
// if less, than 48
if ( $diffInHours < 48 ) {
$location = "http://bing.com";
} else {
$location = "http://google.com";
}
//
if ( $golive ) {
header("Location: ".$location);
exit();
} else {
echo "<p>You are would be sending the customer to:<br><strong>$location</strong>";
}
} else {
echo "<p>We're not sure how you got here, but... 'Welcome!'???</p>";
}
That oughta do it.
By the way, on another note, I'd heavily suggest you go back to the sending party of that URL and definitely reconsider how this is being done. As this is VERY easily tweakable (URL date= value), thus not really protecting anything, but merely putting the keys on the front porch next to the 'Guardian Alarms Installed at This House' {sign} :).
Assuming the input is in the correct format (correct number of characters and all of them digits) you'll need 1 substring of length 4 and the rest of lenght 2. For simplicity I'll ignore the first 2 chars (the 20 part from 2013) with substr
$input=substr($input, 2, strlen($input));
Now I can treat all the remaining elements in the string as 2-char pairs:
$mydate=array(); //I'll store everything in here
for($i=0; $i<=strlen($input)-2; $i+=2){
$mydate[$a]=substr($input, $i, $i+2);
$a++;
}
Now I have year, month, day etc. in an array indexed from 0 to 5. For the date difference I'll put the array into mktime:
$timestamp = mktime(mydate[3], mydate[4], mydate[5], mydate[1], mydate[2], mydate[0]);
Finally compare the two timestamps:
if($old_ts - $timestamp > (60*60*48)){
//more than 48 hours
}else{ ... }
I've been doing a good amount of research with this, and used a few codes to get to know how to make this work, but nothing has worked the way I wanted it to, or hasn't worked at all.
The code is:
<?php
$time1 = $user['last_active'];
$time2 = "+5 minutes";
if (strtotime($time1) > strtotime($time2)) {
echo "Online!";
}else{
echo "Offline!";
}
?>
It is supposed to compare the two variables, and find out if the last active variable is greater or less than 5 minutes, and if it is greater, appear offline. I do not know what's wrong as the NOW() updates on each page and stops if the user is not logged in. Any suggestions or help? Thanks.
The $time1 variable is coming from a fetched array that gets the ['last_active'] information that updates on each page.
I fixed my code, but it still doesn't work right, however, I think I have managed to get further than I was..
<?php
$first = new DateTime();
$second = new DateTime($user['last_active']);
$diff = $first->diff( $second );
$diff->format( '%H:%I:%S' );
if($diff->format( '%H:%I:%S' ) > (strtotime("5 minutes"))){
echo "Offline";
}else{
echo "Online";
}
?>
What can I do at this point?
Nobody pointed out that you actually have a bug. The "current time" will never be greater than "the current time +5 minutes"
Your first code sample will work right if you instead use "-5 minutes" as the "online threshold."
Also, comparing a timestamp without date to the output of strtotime() as you do in the second code is not a proper comparison. It has two problems:
Each time a new day comes around, the same time value will be repeated.
The output of strtotime is an integer representing seconds-since-epoch; the output of format() is a textual representation of hours:minutes:seconds within the current date.
As for your question how to calculate time between 2 dates / time, please view the solution on the following posts, that should give you enough information! (duplicate ? )
Calculate elapsed time in php
And here
How to get time difference in minutes in PHP
EDIT AS YOU PLEASE
<?
$first = new DateTime(); // this would hold your [last active]
//$first->modify("-6 minutes");
$second = new DateTime("NOW");
$difference = $second->diff( $first ); // second diff first
if ($difference->format('%i') > 5) { // comparing minutes only in example ( %i )
echo "The user is AFK";
} else {
echo "user might still be active";
}
?>
Im having some bizarre results in regards to the php date() function. Basically Im getting a date from a Mysql database which is in a string format, split into three elements. This would be Day, Month, Year (15 september 2012 for example) Im ultimately comparing two dates to see if it has expired. But the issue is that only certain dates are allowing the code to work, and some do not work at all (or allow the if statement to work effectively) Below is my code, any help would be great.
$today = date("d-m-Y");
$expire = date("d-m-Y",strtotime($this->getData('date_day')."-".
$this->getData('date_month')."-".$this->getData('date_year'))) ;
if ($expire < $today)
{
echo 'expired';
}
else
{
echo 'Not expired';
}
Im sure its something simple, but for some reason I cannot solve it.
You need to compare the Unix timestamps.
$today = time();
$expire = strtotime($this->getData('date_day')."-".
$this->getData('date_month')."-".$this->getData('date_year')) ;
if ($expire > $today)
{
echo 'expired';
}
else
{
echo 'Not expired';
}
It looks like strtotime is expected a US date format; you need to swap the month and the day around to generate a valid date:
$today = date("d-m-Y");
$expire = date("d-m-Y",strtotime($this->getData('date_month')."-".
$this->getData('date_day')."-".$this->getData('date_year'))) ;
On the other hand, see Stephen305's answer - it's a much better solution to your problem.
I have a date returned from an sql query (a datetime type field) and want to compare it to today's date in PHP. I have consulted php manual and there are many ways to do it. I finally came up with a solution comparing strings, but I would like to know if there are either any 'better' (best practice), cleaner or faster ways to do it. This is my solution:
// $sql_returned_date='2008-10-17 11:20:04'
$today = new DateTime("now");
$f_today=$today->format('Y-m-d'); //formated today = '2011-03-09'
$sql_date=substr($sql_returned_date,0,9); //I get substring '2008-10-17'
if($f_today==$sql_date)
{
echo "yes,it's today";
}else{
echo "no, it's not";
}
thanks
Seriously guys?
//$mysql_date_string= '2013-09-20' OR '2013-09-20 12:30:23', for example
$my_date = new DateTime($mysql_date_string);
if($my_date->format('Y-m-d') == date('Y-m-d')) {
//it's today, let's make ginger snaps
}
You could factor this into the data returned from your database query:
SELECT `DateOnDB`,
DATE(`DateOnDB`) = DATE(CURDATE()) AS isToday
FROM `dbTable`
and simply use PHP to test the value of the isToday column
Excuse me for being a question-digger, but I was trying to achieve the same thing, and I found a simple solution - if you want to select only rows with today's date you can do :
WHERE DATE(datetime_column)=CURDATE()
in your mySQL query syntax.
You'd have three solutions :
Working with strings, like you are doing ; which seems like a solution that works ; even if it doesn't feel clean.
Working with timestamps, using strtotime() and time() ; which is a bad idea : UNIX Timestamps only work for dates that are greater than 1970 and lower than 2038
Working with DateTime everywhere ; which would both work and feel clean.
If I need to make any calculation on the PHP-side, I would probably go with the third solution -- but the first one would be OK in most cases, I suppose.
As a sidenote : instead of formating your date to Y-m-d, you could check if it's :
Greater of equal than today
Less than tomorrow.
If SQL returned date is in this format 2011-03-09 (date format without timing),
$sqlret = "2011-03-05";
$curdate = date('Y-m-d');
echo $diff = strtotime($curdate) - strtotime($sqlret);
echo $no_diff = $diff/(60*60*24);
If the date with time like:
$sqlret = "2011-03-05 12:05:05",
Just make your current date format also like that:
$curdate = date('Y-m-d H:i:s');
If it doesn't satisfies your need, ask your question with some example.
You can use new DateTime php Object that way.
$date1 = new DateTime('2012-01-21');
$date2 = new DateTime ( 'now');
$interval = $date1->diff($date2);
if( $interval->format('%R%a ') == 0){
echo 'it s today';
}
I'd do that:
# SQL
SELECT DATE_FORMAT(date_col, "%Y-%m-%d") AS created_at FROM table
# PHP
if ( date('Y-m-d') == $sql_date ) { // assuming $sql_date is SQL's created_at
echo 'today';
}
$time = //your timestamp
$start = mktime(0,0,0,date("j"),date("n"),date("Y"));
$end = mktime(23,59,0,date("j"),date("n"),date("Y"));
if($time > $start && $time < $end){
//is today
}