Unexpected output for filename - php

Question

<?php
error_reporting(E_ALL);
ini_set('display_errors' ,1);
//expression to be found in file name
$find = '.5010.';
//directory name
//we will store renamed files here
$dirname = '5010';
if(!is_dir($dirname))
mkdir($dirname, 0777);
//read all files from a directory
//skip directories
$directory_with_files = './';
$dh = opendir($directory_with_files);
$files = array();
while (false !== ($filename = readdir($dh)))
{
if(in_array($filename, array('.', '..')) || is_dir($filename))
continue;
$files[] = $filename;
}
//iterate collected files
foreach($files as $file)
{
//check if file name is matching $find
if(stripos($file, $find) !== false)
{
//open file
$handle = fopen($file, "r");
if ($handle)
{
//read file, line by line
while (($line = fgets($handle)) !== false)
{
//find REF line
$refid = 'REF*2U*';
if(stripos($line, $refid) !== false)
{
//glue refernce numbers
//check if reference number is not empty
$refnumber = str_replace(array($refid, '~'), array('', ''), $line);
if($refnumber != '')
{
$refnumber = '_'. $refnumber .'_';
$filerenamed = str_replace($find, $refnumber, $file);
copy($file, $dirname . '/' . $filerenamed);
}
echo $refnumber . "\n";
}
}
//close file
fclose($handle);
}
}
}
?>
I have this code, the output should be the replacement of ".5010." with "ref" in the final name, however, when I run the code, it just shows me up to ref not the rest of the file name, I tried it on my computer putty and turns out there's a "?" after the ref number, is there any way I could fix this?
For example; My file is 4867586.5010.476564.ed
After the code executes and reads the file, the output should be: 4867586_SMIL01_476564.ed but instead its: 4867586_SMIL01
And when I checked it out on putty the file name was: 4867586_SMIL01?_476564.ed

Answer 1

The ? in the filename denotes that there's a a non-printable character somewhere in the refnumber line.
This is most likely a line-ending character, or something else.
If it's the former, then that can be solved by changing the line:
$refnumber = str_replace(array($refid, '~'), array('', ''), $line);
to
$refnumber = str_replace(array($refid, '~'), array('', ''), $line);
$refnumber = trim($refnumber); // remove any whitespaces or line endings.
If it's the latter, then you'll need to sanitize your $refnumber variable using one of the file sanitizer functions available online.