I have three mysql tables, category,students and student_category. for each student there is 1 or more category will be there and it is stored in student_category as follows.
1) Categgory
----------------------------
id | category_name
---------------------------
1 | A
2 | B
3 | C
4 | D
2) Students
--------------------------
id | name
--------------------------
1 | John
2 | Kumar
3 | Ashok
4 | Jorge
5 | Suku
-------------------------
2) student_category
-----------------------------------------
id | student_id | category_id
-----------------------------------------
1 | 1 | 2
2 | 1 | 4
3 | 2 | 3
4 | 2 | 1
5 | 3 | 2
------------------------------------------
I need to select students which contain category_id 2 and 4.
i used query as follows but it return either students contain category 2 or category 4.
select A.name from students A, student_category B where A.id=B.student_id
and B.category_id IN (2,4)
Try this query:
SELECT t1.id,
t3.name
FROM students t1
INNER JOIN student_category t2
ON t1.id = t2.student_id
INNER JOIN students t3
ON t1.id = t3.id
WHERE t2.category_id IN (2, 4)
GROUP BY t1.id
HAVING COUNT(DISTINCT t2.category_id) = 2
Explanation:
This query joins together the students and student_category tables, and then removes all records which are not category 2 or 4. This means that each student would then only have category 2 and 4 records associated with him. The HAVING clause then restricts further by requiring that a student have two distinct categories, which if true must mean that the student has both category 2 and 4.
Demo here:
SQLFiddle
try this :
select name from Students where id in (select student_id from student_category where category_id in (2,4))
your query is fine btw.
Try this one:
select
s.name
from
Students s,
Categgory c,
student_category sc
where
sc.student_id = s.id
and sc.category_id = c.id
and c.id = 2
and c.id = 4
You can check it on SQL Fiddle.
Have to take distinct student name as it will repeat if a student falls in more than one category.
Related
I have three tables:
person_table
id| name | gender
1 | Joe | male
2 | Jane |female
3 | Janet | female
4| Jay | male
etc...
product_table
id| name
1 | magazine
2 | book
3 |paper
4 | novel
etc...
**person_product
person_id| product_id | quantity
1 | 1 | 1
1 | 3 | 3
2 | 3 | 1
4 | 4 | 2
etc...
I have tried to make a query that will return a table like this:
person_id| person_name | product_name| quantity
but i can't make it so that if lets say John has no books, it should display
(johns id) John|book|0
instead of just skipping this line.
Where did i go wrong?
here is what i managed to come up with:
SELECT p.*, f.name, l.quantity
FROM person_product AS l
INNER JOIN people_table AS p ON l.person_id=p.id
INNER JOIN product_table AS f ON l.product_id=f.id
ORDER BY id`
It seems that you're generating a report of all people, against all products with the relevant quantity; on a large data set this could take a while as you're not specifically joining product to person for anything other than quantity:
SELECT
p.id,
p.name,
p.gender,
f.name,
IFNULL(l.quantity,0) AS quantity
FROM person_table AS p
JOIN product_table AS f
LEFT JOIN person_product AS l
ON l.person_id = p.id
AND l.product_id = f.id
ORDER BY p.id, f.name
Which results in:
Is that more-or-less what you're after?
you need to start with people_table than using left join you need to bring other table data.
as you need 0 value if null than you can use function IFNULL
SELECT p.*, f.name, IFNULL(l.quantity,0)
FROM people_table AS p
LEFT JOIN person_product AS l ON l.person_id=p.id
LEFT JOIN product_table AS f ON l.product_id=f.id
ORDER BY p.id
if has no book shouldn't appear in the table , try this (easy to understand) :
SELECT NAME
,'0'
,'0'
FROM person_table
WHERE id NOT IN (
SELECT person_id
FROM person_product
)
UNION
SELECT person_id
,product_id
,quantity
FROM person_product;
Example Table Structure
Table 1
ID | Name | Price
-----------------------------
1 | Casio | 30
2 | Titan | 40
Table 2
ID | Place | Price
-----------------------------
1 | Cali | 30
2 | Mexi | 10
Operation to perform:
Table1(Price) - Table2(Price) for ID = 1
New Table 1
ID | Name | Price
-----------------------------
1 | Casio | 0
2 | Titan | 40
ID matches in both tables
You should consider another database design to handle this case.
But to answer your question, you can create a view :
create view Differences2 as (
select t1.id, t1.price - t2.price
from t1, t2
where t1.id = t2.id
)
As you told both table will have same ID column you can use following query.
SELECT table1.ID, table1.Name, (table1.Price-table2.Price) AS Price
FROM table1
INNER JOIN table2 ON table1.ID = table2.ID
If you want to update record you can use following:
UPDATE table1
INNER JOIN table2 ON table1.ID = table2.ID
SET table1.Price = (table1.Price-table2.Price)
First, apologies if the title doesn't match the question. Well, the problem is how to build this query...
I have a table called category It contains categories of my stuff(movies). It's like this...
--------------------------------
ID | name | parent_category
--------------------------------
1 | love | 0
2 | action | 0
3 | fear | 0
4 | passion| 1
5 | danger | 2
6 | death | 3
--------------------------------
So, as you see, each category has a parent category. Except the first 3. They're parents.
And movies table is like this...
--------------------------------
ID | name | category
--------------------------------
1 | aaaa | 1
2 | bbbbbb | 2
3 | cccc | 2
4 | ddddddd| 1
5 | eeeeee | 3
6 | fffff | 3
--------------------------------
So, what i want to do is, to select movies by parent category. Which means if I click category, love, it should select all the movies of categories that having love as the parent category.
So, how to write this in a single query ?
If the parents are only one level deep, then you can use joins:
select m.*,
coalesce(cp.id, c.id) as parent_id,
coalesce(cp.name, c.name) as parent_name
from movies m left join
categories c
on m.category = c.id left join
categories cp
on c.parent_category = cp.id;
Actually, if you only want the id, you don't need two joins:
select m.*,
(case when c.parent_id > 0 then c.parent_id else c.id end) as parent_id
from movies m left join
categories c
on m.category = c.id ;
Or, more simply:
select m.*, greatest(c.parent_id, c.id) as parent_id
. . .
to select rows filtered by condition on secend table use join in FROM clause or subquery in condition with IN or EXISTS function. To compare field with some string you can use LIKE operator.
If you are filtering based on parent_category -
SELECT b.*, a.name FROM movies b
LEFT JOIN categories a ON a.id = b.category
WHERE a.parent_category = 1;
Category table:
id, name
---------
1 cat1
2 cat2
3 cat3
4 cat4
Article table:
id, cid, title
--------------
1 1 title1
2 3 title2
3 1 title3
4 2 title4
How to select all categories and count number of each category articles in MySQL? I need a mysql query that will select all category and total count of articles belonging to each category and order by category id.
Expected output table:
+-------+-------+
| name | count |
+-------+-------+
| cat1 | 2 |
| cat2 | 1 |
| cat3 | 1 |
| cat4 | 0 |
+-------+-------+
SELECT
c.`name`,
COUNT(a.cid) AS `count`
FROM
categories c
LEFT JOIN article a ON c.id = a.cid
GROUP BY
c.`name`
ORDER BY
c.`name`
You can also use subquery like
SELECT c.name,(select count(*) from article where cid = c.id) as count FROM cat c WHERE 1 GROUP BY c.id
Try this:
SELECT c.`name`, count(a.cid) as count FROM category
LEFT JOIN article
ON c.id = a.cid
GROUP BY a.cid
select c.name,count(b.title)count from category a, article b where c.id = a.cid group by c.name order by a.cid;
I hope this will work. Please check.
select
Category.name.
ifnull(count(Article.cid),0) as count
FROM
Category
LEFT JOIN
Article
on
Article.cid=Category.id
group by
Category.Id
I want to query my database and get counts of the occurences of each id in a single column.
The two tables related to this query are:
categories: this table has a list of all categories with titles
id | title
----------
1 | project
2 | tech
3 | other
category_news: this table is used to assign news items to categories, each news item can be in multiple categories
id | category_id | news_id
--------------------------
1 | 1 | 2
2 | 1 | 5
3 | 1 | 3
4 | 2 | 4
5 | 3 | 2
6 | 3 | 1
I would like to get a result of (doesnt have to be an array, I can sort out the results of a query, just using an array below for an example of the returned results):
array(
'project' => 3
'tech' => 1
'other' => 2
);
Where the key is the category title and the value is the total number of news items in each category. I know that I could do it with a query for each category:
select count(cn.category_id), c.title from category_news cn join categories c on c.id = cn.category_id where category_id = 1
But my question is, can I do it with one query to get all the counts? As if I have 100 categories thats 100 queries my way and I would love to do it in one.
Any help would be much appreciated
Regards
Luke
Try this:
SELECT c.title, count(cn.category_id)
FROM categories c
LEFT JOIN categories_news cn
ON c.id = cn.category_id
GROUP BY c.title
This will work(tested):
SELECT COUNT(cn.category_id), c.title
FROM category_news cn
JOIN categories c ON c.id = cn.category_id
GROUP BY cn.category_id
Yes, you can. You have to use a query like the following (tested)
SELECT count( * ) , c.title
FROM category_news cn
JOIN categories c ON c.id = cn.category_id
WHERE 1
GROUP BY cn.category_id