MYSQL Select IN query using text - php

Any quick assistance will be highly appreciated. I've table row in mysql named as mob_categories, now data is being is saved as '|' separated for instance (cat 1|cat 2|cat 3 and so on. Now i need to get the value from another column in the same table if the input value matches.
for instance if the value is cat 1 i need to select the value from another column is named as deveice_token wherever it matches with 'cat 1'
I tried this code but its not working somehow
SELECT * from table_name where find_in_set('cat 1',mob_categories) <> 0
so i modified a bit with the following code but it works with only numeric value if the value exits in this format in this format (i.e) 1,2,3
$userNotification = $wpdb->get_results("SELECT * from table_name where 1 IN (mob_categories); ");
What's i'm missing specifically?


Since data in mob_categories are separated by | rather than by comma (,) so you need to make it compatible for FIND_IN_SET first.
So replace all the | by comma (,) first.
SELECT * from table_name where find_in_set('cat 1', REPLACE(mob_categories,'|',',')) > 0

Related

How to fetch value from table as per multiple id using MySQL

I need one help. I need to fetch value from table as per multiple ids which are in comma separated string using MySQL. I am explaining my table and query below.
db_basic:
id special name
1 2,3,4,5 Raj
2 4,2,5,6 Rahul
3 3,5,6 Rocky
My code is given below.
$special=2;
$qry=mysqli_query($connect,"select * from db_basic where special='".$special."'");
Here I need where special=2 is present inside that comma separated string those value will be fetched. I need only proper query. Please help me.

use below query
May be work for u
Use LIKE instead of "="
"select * from db_basic where special LIKE '%".$special."%'"

use FIND_IN_SET function for ex.
select * from db_basic where FIND_IN_SET(2,special)

Try this once,
select * from db_basic where FIND_IN_SET($special, special);
It should work.

if you current code expeted to return the first and second line of your db, you can use the LIKE operator in the query like this :
$special=2;
$qry=mysqli_query($connect,"select * from db_basic where special LIKE '%,".$special.",%'");
or LOCATE like :
$special=2;
$qry=mysqli_query($connect,"select * from db_basic where LOCATE(".$special.",special)>0");
And FIND_IN_SET : From the docco here - "This function does not work properly if the first argument contains a comma (“,”) character".

Numeric value inside varchar MySQL in temporary table

Problem
I have a field with values like
"ABC1234"
"ABC5678/DEF"
"AB1298"
"AB1298/DEF"
I want to extract the numeric value from each one of it, such as:
1234
5678
1298
1298
NOTE: The numeric value is always "together" (1234) and is always composed by 4 digits only.
I was trying to delete first the double quotes to use RegEx: SELECT REPLACE(model_name,'''','') FROM ProductList Note: I replace using ' single quote instead of double quotes " , because that's the way the data was saved, and it works. And then I tried to use Patindex to get the numeric value: SELECT SUBSTRING(field, PATINDEX('%[0-9]%', field), LEN(field)) NOTE: However, PATINDEX does not work with MySQL
I'm trying to do this, because then I want to separate each value in two different columns by creating a temporary table:
SELECT SUBSTR(t.column_one, 1, INSTR(t.column_one, ' ')-1) AS col_one, SUBSTR(t.column_one, INSTR(t.column_one, ' ')+1) AS col_two FROM YOUR_TABLE t
val1 val2
12 34
56 78
12 98
Note: I'm using PHPMyAdmin within XAMPP.
After PATINDEX, I tried LOCATION, and POSITION. (You can see the sequence of the test print screen here ) SELECT SUBSTRING(model_name,LOCATE('%[^0-9]%',model_name),4) FROM ProductList NOTE: The LOCATE or POSITION function is returning a position 0, and that's why there is no result. I can imagine the problem is in "%[^0-9]%", because not LOCATE, POSITION nor MID accept RegEx.
My next problem is: I want to have the lval and rval inside the temporary table footprint, created at the beginning of the query. This, because I would like to create queries by getting input texts values, and have something like:
SELECT * FROM footprint WHERE lval=50;
model_name num_pos lval rval
''ABC1234'' 7 12 34
''ABC1234/DEF'' 7 50 78
''ABDCE1234'' 8 12 98
Solution Proposal
At the end, I want to search the name_model, depending on the values of lval and rval. So the next "query" works for me:
CREATE TEMPORARY TABLE IF NOT EXISTS footprint AS
(SELECT model_name,
LEAST (
if (Locate('0',model_name) >0,Locate('0',model_name),999),
if (Locate('1',model_name) >0,Locate('1',model_name),999),
if (Locate('2',model_name) >0,Locate('2',model_name),999),
if (Locate('3',model_name) >0,Locate('3',model_name),999),
if (Locate('4',model_name) >0,Locate('4',model_name),999),
if (Locate('5',model_name) >0,Locate('5',model_name),999),
if (Locate('6',model_name) >0,Locate('6',model_name),999),
if (Locate('7',model_name) >0,Locate('7',model_name),999),
if (Locate('8',model_name) >0,Locate('8',model_name),999),
if (Locate('9',model_name) >0,Locate('9',model_name),999)
) AS num_Pos
FROM ProductList) ;
SELECT name FROM (SELECT name, left(val,2) AS lval, right(val,2) AS rval FROM
(SELECT MID(pl.model_name, fp.num_Pos,4) AS val, pl.model_name AS name FROM ProductList AS pl INNER JOIN footprint AS fp ON fp.model_name=pl.model_name) p) n WHERE lval='50' and rval='50'
If you have any other suggestion about how this process could be done or improved, please let me know.
Thank you,
Best regards.

To split the numeric and the string part of your values you can use trim, like this:
SELECT trim(field, 'ABCDEFGHIJKLMNOPQRSTUVWXYZ"') AS col0, trim(field, '1234567890"') AS col1 FROM table
Hope it help.
P.S.
This solution also work on sqlite database where the function PATINDEX doesn't exisit.

a double quote is a distinct character not simply 2 single quotes so to strip off the double quotes try.
SELECT REPLACE(model_name,'"','') FROM ProductList
you are sooo close with the code above. given that your numeric portion will always be 4 chars you could use something like this
declare #t as table(field varchar(15))
insert into #t
values
('"ABC1234"'),
('"ABC5678/DEF"'),
('"AB1298"'),
('"AB1298/DEF"')
select left(val,2) as lval, right(val,2) as rval
from
(select SUBSTRING(field, PATINDEX('%[0-9]%', field), 4) val
from #t) t
so with the context of your database it would be something like
select left(val,2) as lval, right(val,2) as rval
from
(select SUBSTRING(model_name, POSITION('%[0-9]%', model_name), 4) val
from ProductList) p

According to all the description I wrote, the next code ended working for me.
A lot of hints are hiding in the description, but if you have any suggestion about the query, be my guest.
CREATE TEMPORARY TABLE IF NOT EXISTS footprint AS
(SELECT model_name,
LEAST (
if (Locate('0',model_name) >0,Locate('0',model_name),999),
if (Locate('1',model_name) >0,Locate('1',model_name),999),
if (Locate('2',model_name) >0,Locate('2',model_name),999),
if (Locate('3',model_name) >0,Locate('3',model_name),999),
if (Locate('4',model_name) >0,Locate('4',model_name),999),
if (Locate('5',model_name) >0,Locate('5',model_name),999),
if (Locate('6',model_name) >0,Locate('6',model_name),999),
if (Locate('7',model_name) >0,Locate('7',model_name),999),
if (Locate('8',model_name) >0,Locate('8',model_name),999),
if (Locate('9',model_name) >0,Locate('9',model_name),999)
) AS num_Pos
FROM ProductList) ;
SELECT name FROM (SELECT name, left(val,2) AS lval, right(val,2) AS rval FROM
(SELECT MID(pl.model_name, fp.num_Pos,4) AS val, pl.model_name AS name FROM ProductList AS pl INNER JOIN footprint AS fp ON fp.model_name=pl.model_name) p) n WHERE lval='50' and rval='50'

How to search for a comma-separated string in a database table in mySQL

How to search for a comma-separated string in a database table in mySQL.
Suppose, I have a string in variable $facilities='breakfast,dinner,lunch' and in my database I have a string saved in a field called facilities having values breakfast,dinner,clothing,lunch,hot water.
How do I get the row having values $facilities?

Work like this i hope this is your requirement
select * from table where field_name like '%$fieldname%'

You're going to need to break apart the comma separated string first, and include a clause for each, so for that input you'd generate SQL like (assuming you want rows that have all three, and maybe other flags set):
SELECT *
FROM YourTable
WHERE FIND_IN_SET('breakfast', facilities)
AND FIND_IN_SET('dinner', facilities)
AND FIND_IN_SET('lunch', facilities)
You can break the string apart in PHP with something a little like:
$facilities='breakfast,dinner,lunch';
$desired = explode ( "," , $facilities );
And just use a loop to build your SQL

SELECT *
FROM tableName
WHERE FIND_IN_SET('lunch', 'breakfast,dinner,lunch')
EDIT:
SELECT *
FROM tableName
WHERE FIND_IN_SET('lunch', food_column)
food_column is the name of the column where the string 'breakfast,dinner,lunch' is stored

Need help in php mysql statement which has "and" and range

I am want to write a php mysql query which includes and and range condition.
In the screen shot you can see the field of the table called search. The fields with same name are the range. I want select query and it should include all the fields and their appropriate range.
The names of the fields are shape1,shape2(it is range from shape1 to shape2) etc and it goes on.
The query should be like this
select * from search where unique_id='$unique_id && (carat1='$carat1' between carat2='carat2') &&...
and there are other field too like cut and shape, all in one query. I am inserting value in to the database directly from android in json format. My problem is that i don't know proper format.
Please help me

It should go like this (an example)
select * from search
where unique_id= 10
and carat1 between 1 and 10
and shape1 between 1 and 10
and cut1 between 1 and 10
EDIT:
If you are trying to run the SQL from PHP script then the format will be different like below (if the column is type integer like unique_id then don't put ' while replacing value. For string type replace with ' like carat)
Select * from search
where unique_id = $unique_id
and carat between '$carat1' and '$carat2'
and color between '$color1' and '$color2'
and shape between '$shape1' and '$shape2'

Example usage of between in mysql:
SELECT * FROM search
WHERE unique_id = 200 AND
carat BETWEEN 1 AND 5;
Note that the AND that follows BETWEEN is used to indicate the range (1,5) and is not a logical AND operator.

Try this, I hope this will help you
SELECT * FROM search
WHERE unique_id = $unique_id AND
carat between $carat1 AND $carat2 AND
color like '%".$color1."%' AND
color like '%".$color2."%' AND
shape like '%".$shape1."%' AND
shape like '%".$shape2."%'

Adding a character to empty row

My database contains empty table columns.
I would like to add a character like § to these empty rows so that I can search for them easier. How would I go about?
I already have a script that lets me replace or remove characters but I dont know a way to specify that rows that are empty should be updated with a character.

First, you probably don't have empty rows but empty column values in the rows. Wouldn't it be better if you just do it like if (!empty($row['column'])) instead of trying to put some bogus character?
Or if you want to do a SELECT just do something like this:
SELECT * FROM table_name WHERE column_name > ''; // seems to work for both NULL and empty string
Or:
DELETE FROM table_name WHERE column_name IS NULL or column_name = '';

UPDATE `table` SET column = "§" WHERE column = "";

It's bad to add character to an empty column because you are only adding extra size to the database. It's easy to search empty string on the database. Possible solutions of searching will be using of IS NULL to search for null columns.
SELECT * FROM tableName WHERE collName IS NULL
Another is by using CHAR_LENGTH (which gets the length of the data in the column)
SELECT * FROM tableName WHERE CHAR_LENGTH(collName) = 0
or by simply comparing it to ''
SELECT * FROM tableName WHERE colName = ''

Categories