I'm having a little problem with php, basically I want to get a random row from my mysql database, I am really new to php and mysql so please be kind and explain me what's going on. I've already granted all permissions on mysql, now I just have to figure out what's going on, i tried to put some echoes to debug but it seems like anything happens, there's just a blank page with nothing on it, this drives me crazy so I'd like to resolve it. Here's the code
<?php
echo "test";
$host="127.0.0.1"; // Host name
$username="username"; // Mysql username
$password="password"; // Mysql password
$db_name="mine"; // Database name
$tbl_name="accounts"; // Table name
// Connect to server and select databse.
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");
// Select a random account
$min=1;
$row=mysql_fetch_assoc(mysql_query("SHOW TABLE STATUS LIKE 'mine.accounts';"));
$max=$row["Auto_increment"];
$random_id=rand($min,$max);
$row=mysql_fetch_assoc(mysql_query("SELECT * FROM `mine`.`accounts` WHERE id='$random_id'");
echo $row["username"]. ":" . $row["password"]
?>
// --- UPDATE ---
<?php
error_reporting(E_ALL); ini_set('display_errors', 1);
$host="127.0.0.1"; // Host name
$username="username"; // Mysql username
$password="password"; // Mysql password
$db_name="mine"; // Database name
$tbl_name="accounts"; // Table name
// Connect to server and select databse.
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");
// Select a random account
$row = mysql_query("SELECT username AND password FROM accounts order by RAND() LIMIT 1");
WHILE ($data = mysql_fetch_array($row))
ENDWHILE;
echo $row['username'] . " " . $row['password'];
?>
On this line, you forgot the closing parentheses.
$row=mysql_fetch_assoc(mysql_query("SELECT * FROM `mine`.`accounts` WHERE id='$random_id'");
Hence the single closing parentheses while you open two.
$row=mysql_fetch_assoc(mysql_query("SELECT * FROM `mine`.`accounts` WHERE id='$random_id'"));
And you'll have to use a while loop to make $row output anything, since fetch_assoc returns an associative array:
while($row = mysql_fetch_assoc(<...>){
$max = $row['Auto_increment'];
}
Also you might wanna look into Prepared Statements or PDO as mysql_* Functions are officially deprecated.
I'm using ampps
The following is my config code. I've not given username and password in it.
$db_name="naatesam_FAMILY"; // Database name
$tbl_name="user"; // Table name
// Connect to server and select database.
$conn=mysql_connect("localhost", "", "")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");
The output it shows is:
cannot select DB
I think without username and password it should work....
If anyhow they're required then please tell me how to set username and password for phpMyAdmin in ampps.
Your code should be :
$db_name="naatesam_FAMILY"; // Database name
$tbl_name="user"; // Table name
// Connect to server and select database.
$conn=mysql_connect("localhost", "root", "mysql")or die("cannot connect");
mysql_select_db($db_name, $conn)or die("cannot select DB");
$conn=mysql_connect("localhost", "", "")or die("cannot connect");
change to
$conn=mysql_connect("localhost", "root", "mysql")or die("cannot connect");
Pretty new to PHP and MySQL.
I have created an insert statement in my php script, to transfer a row of data from one table to the next for certain fields. Only thing is, it doesn't seem to be working?
Can anybody see where the issue is?
<?php
require_once('auth.php');
$host=""; // Host name
$username=""; // Mysql username
$password=""; // Mysql password
$db_name=""; // Database name
$tbl_name="Instruction"; // Table name
// Connect to server and select database.
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");
$sql="INSERT INTO Triage (Reference,Forename,surname,D.O.B,Mobile Number,Home Number,Address,Postcode1,Email,Accident,Details);
VALUES (Reference,Forename,surname,DOB,Mobile,Home,Address,Postcode1,Email,Accident,Details)";
$result=mysql_query($sql);
//
while($rows=mysql_fetch_array($result)){
echo 'update test';
}
//
// end of while loop
echo "Successful";
echo "<BR>";
echo "<a href='list_records.php'>View result</a>";
?>
Update
// Connect to server and select database.
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");
$Reference=$_REQUEST['Reference'];
$Forename=$_REQUEST['Forename'];
$surname=$_REQUEST['surname'];
$DOB=$_REQUEST['DOB'];
$Mobile=$_REQUEST['Mobile'];
$Home=$_REQUEST['Home'];
$Address=$_REQUEST['Address'];
$Postcode=$_REQUEST['Postcode1'];
$Email=$_REQUEST['Email'];
$Accident=$_REQUEST['Accident'];
$Details=$_REQUEST['Details'];
//semi colon removed
$sql="INSERT INTO Triage (Reference,Forename,surname,D.O.B,Mobile Number,Home Number,Address,Postcode1,Email,Accident,Details)
VALUES('.$Reference.','.$Forename.','.$surname.','.$DOB.','.$Mobile.','.$Home.','.$Address.','.$Postcode1.','.$Email.','.$Accident.','.$Details.')";
$result=mysql_query($sql);
echo "Successful";
echo "<BR>";
echo "<a href='list_records.php'>View result</a>";
?>
first you should fix the assignments:
$Reference=$_REQUEST['Reference'];
$Reference=$_REQUEST['Forename'];
...
should be something like:
$Reference=$_REQUEST['Reference'];
$Forename=$_REQUEST['Forename'];
$surname=$_REQUEST['surname'];
Then update the query in:
$sql="INSERT INTO Triage (Reference,Forename,surname,D.O.B,Mobile Number,Home Number,Address,Postcode1,Email,Accident,Details)
VALUES (".$Reference.",".$Forename.","...
and so on with the rest of the values.
Also
while($rows=mysql_fetch_array($result)){
won't work since result will only contain true on success.
Maybe there are more mistakes I'm not sure. But you should also check this to learn how to avoid injection:
What's the best method for sanitizing user input with PHP?
If you want to transfer data from one table to another, you should select this table somewhere. You have not anywhere in your code, you just specified columns, how is your script supposed to know where do they come from?
INSERT INTO table1 (col1, col2, col3) SELECT correspondingColumn1, correspondingColumn2, correspondingColumn3 FROM table2
P.S.: You do not use $Reference, but still, you are overwritting it
try this one
1) you mention all var name as $Reference its changed
2) query not correct plz study how wrote query..
3) REFER:http://www.w3schools.com/php/php_mysql_intro.asp
<?php
require_once('auth.php');
$host=""; // Host name
$username=""; // Mysql username
$password=""; // Mysql password
$db_name=""; // Database name
$tbl_name="Instruction"; // Table name
// Connect to server and select database.
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");
$Reference=$_REQUEST['Reference'];
$Forename=$_REQUEST['Forename'];
$surname=$_REQUEST['surname'];
$DOB=$_REQUEST['DOB'];
$Mobile=$_REQUEST['Mobile'];
$Home=$_REQUEST['Home'];
$Address=$_REQUEST['Address'];
$Postcode=$_REQUEST['Postcode1'];
$Email=$_REQUEST['Email'];
$Accident=$_REQUEST['Accident'];
$Details=$_REQUEST['Details'];
//semi colon removed
$sql="INSERT INTO Triage (Reference,Forename,surname,D.O.B,Mobile Number,Home Number,Address,Postcode1,Email,Accident,Details)
VALUES ('$Reference','$Forename','$surname','$DOB','$Mobile','$Home','$Address','$Postcode1','$Email','$Accident','$Details')";
$result=mysql_query($sql);
//
while($rows=mysql_fetch_array($result)){
echo 'update test';
}
//
// end of while loop
echo "Successful";
echo "<BR>";
echo "<a href='list_records.php'>View result</a>";
?>
<?php
$host="localhost"; // Host name
$username=""; // Mysql username
$password=""; // Mysql password
$db_name="hsp_property"; // Database name
$tbl_name="project_directory"; // Table name
// Connect to server and select database.
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");
//Get values from form
$id = $_POST['id'];
$hospital = $_POST['hospital'];
$project = $_POST['project'];
$state = $_POST['state'];
$status = $_POST['status'];
$da_status = $_POST['da_status'];
$pm = $_POST['pm'];
$budgett = $_POST['budgett'];
$budgetat = $_POST['budgetat'];
$pdapproval = $_POST['pdapproval'];
$pdcs = $_POST['pdcs'];
$pdcd = $_POST['pdcd'];
$pdcf = $_POST['pdcf'];
$pnm = $_POST['pnm'];
$prm = $_POST['prm'];
$comments = $_POST['comments'];
// update data in mysql database
$sql="UPDATE $tbl_name SET Hospital='$hospital', Project='$project', State='$state',Project_Status='$status',DA_Status='$da_status',Project_Manager='$pm',Budget_Total='$budgett',Budget_Approved='$budgetat',Project_Approval_Dates='$pdapproval',Project_Contstruction_Dates='$pdcs',Project_Contract_Dates='$pdcd',Project_Current_Dates='$pdcf',Program_Next_Milestone='$pnm',Program_Milestone='$prm',Comments='$comments' WHERE id='$id'";
$result=mysql_query($sql);
// if successfully updated.
if ($result) {
header ('Location: ../project_directory.php');
}
else {
echo 'Error';
}
?>
The above is some code to update a MySQL db, i'm running WAMP to test the website before I'll upload.
I've been using the phpeasysteps tutorial as php and mysql is new to me. It's been working all ok until now.
Would love to know what i'm doing wrong, the PhpEasySteps tutorial might be a tad old as i've had to update a few elements of the initial code to get it to work..
Replace echo 'Error'; with echo mysql_error(); to see why you didn't get a result and then slap yourself for misspelling a column name or something most likely easily overlooked. If you still can't figure it out, post the error. And if you go that far, post the result of SHOW CREATE TABLE project_directory
You need to add $link_identifier to your mysql_select_db database selection,
Syntax: bool mysql_select_db ( string $database_name [, resource $link_identifier = NULL ] )
$link = mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name", $link)or die("cannot select DB");
You can use mysql_error(); function to find the mysql related errors.
Below is my code:
session_start();
include_once "config.inc.php";
$tbl_name="members";
$username=$_SESSION['username'];
$sql = "SELECT quiz1mark, quiz2mark, quiz3mark FROM $tbl_name WHERE username='$username'";
$query = mysql_query($sql);
$data = mysql_fetch_array($query, MYSQL_ASSOC);
Then, further down the page:
<p><?php echo $data; ?></p>
This generates a notice: Notice: Undefined variable: data in F:\xampp\htdocs\quiz_home.php on line 35
I've clearly defined the variable though, and am unsure as to what's causing this problem.
***Contents of config.inc.php***:
$host="localhost";
$username="root";
$password=""; //the default installation of xampp does not include a mysql password
$db_name="bda";
//connect to the database using the above information (variables)
mysql_connect("$host", "$username", "$password")or die("cannot connect to server");
mysql_select_db("$db_name")or die("cannot select database");
What is the result when you try?:
var_dump($data);