i'm trying to call getMensClothing() function from function.php to header.php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "khaki";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
function getMensClothing(){
global $conn;
$sql = "SELECT * FROM men_clothing";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "<li><a href='#' class='hvr-grow'>". $row['men_clo_items']." </a></li>";
}
}
}
header.php file looks like this
<?php include 'functions.php'; ?>
<?php
echo'
<div class="col-sm-2"><br>
<p> <b>Men\'s Clothing</b></p>
<ul>
'.getMensClothing().'
</ul>
</div>'
?>
function is called but the items aren't displayed where it has to everything is show at the top of the page . How to display the items inside the div ??
Use below Code
$html = "";
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
$html .= "<li><a href='#' class='hvr-grow'>". $row['men_clo_items']."</a></li>";
}
}
return $html;
into your function.php file
create a class like
class support{
//inside goes codes and functions
}
while calling into another file.
include it above file then create
$a=new support()
$a->functionname();
this should do the trick
What happens is that you use echo with parameters, that are evaluated to be printed.
You use concatenation with your arguments to echo.
You have one parameter contructed with the concatenation of three arguments.
The result of this concatenation is printed. One of these arguments is the returned value of the getMensClothing() function.
During the evaluation of getMensClothing() you print some data.
Consequently, the data printed in your function getMensClothing() gets printed before the end of the call to echo statement in header.php.
As other people pointed out, you should reconsider your technique as your code could be more easy to use if you separate the job of retrieving and constructing your data and the job of displaying it. Have a look to MVC for instance.
Related
So I'm working on a website where I need to pull data from a MySQL server and show it on a webpage. I wrote a simple PHP script to read data from the database depending upon an argument passed in the URL and it works just fine.
Here is the script:
<?php
function updator($item)
{
$servername = "localhost";
$username = "yaddvirus";
$password = "password";
$dbname = "database";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
echo "Connected successfully";
$table = "inventory";
//$item = "Rose Almonds";
$sql = "SELECT * FROM $table WHERE item = '$item'";
$result = $conn->query($sql);
while($data=$result->fetch_assoc()){
echo "<h1>{$data['item']}</h1><br>";
echo "<h1>{$data['item_desc']}</h1><br>";
echo "<h1>{$data['price125']}</h1><br>";
echo "<h1>{$data['price250']}</h1><br>";
}
//echo "0 results";
$conn->close();
}
if (defined('STDIN')) {
$item = $argv[1];
} else {
$item = $_GET['item'];
}
//$item = "Cherry";
updator($item);
?>
This script works exactly as expected. I call it using http://nutsnboltz.com/tester.php?item=itemname and it pulls and shows the data just fine.
P.S You can test it out by using Cherry or Blueberry as items.
The problem is, when I'm trying to put this data in my productpage.php file, I can't get the data to show up. Here's how the file hierarchy goes:
<php
*Exact same php script as above*
?>
<html>
<head>
Header and navbar come here
</head>
<body>
<div class="container-fluid">
<div class="row">
<div class="col-4">
<h1> RANDOM TEXT BEFORE </h1>
<?php
while($data=$result->fetch_assoc()){
echo "<h1>{$data['item']}</h1><br>";
echo "<h1>{$data['item_desc']}</h1><br>";
echo "<h1>{$data['price125']}</h1><br>";
echo "<h1>{$data['price250']}</h1><br>";
}
?>
</div>
<div class="col-8">
<H!> MORE RANDOM TEXT</h1>
</div>
</div>
</div>
</body>
<footer>
footer here
scripts etc
</footer>
</html>
So the script above the footer prints everything just fine. However, down where the HTML is, nothing is printed after the PHP code. It only shows my Navbar and the H1 tag saying "RANDOM TEXT BEFORE" and that's about it. My footer is gone along with everything else.
What exactly is the issue here and how do I fix this?
The problem seems to be that you're declaring $result inside the updator function, so it's not available when you're attempting to call it later.
The best thing to do might be to return $result from the function and assign that to a variable - something like this:
function updator($item)
{
// ... some code ...
$sql = "SELECT * FROM $table WHERE item = '$item'";
$result = $conn->query($sql);
// ... some more code ...
return $result;
}
<-- HTML CODE HERE -->
<?php
$item = !empty($_GET['item']) ? $_GET['item'] : false;
// yes I know it's a bit hacky to assign the variable
// within the 'if' condition...
if($item && $result = updator($item)) {
while($data=$result->fetch_assoc()){
echo "<h1>{$data['item']}</h1><br>";
echo "<h1>{$data['item_desc']}</h1><br>";
echo "<h1>{$data['price125']}</h1><br>";
echo "<h1>{$data['price250']}</h1><br>";
}
}
?>
I'm trying to get a value from the database and compare it with whatever id href was set. But nothing happens.
<?php
$servername = "127.0.0.1";
$username = "root";
$password = "";
$dbname = "products";
$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT id FROM items";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$id = $row["id"];
echo <<<EOT
<br>
<form action='index.php?$id' method="POST">
<input type='submit' name="submit" value="more">
</form>
EOT;
}
} else {
echo "0 results";
}
if (isset($_POST['submit'])) {
while($row = $result->fetch_assoc()) {
if ($_SERVER["QUERY_STRING"] == $row) {
echo 'you clicked something from the database' . $id;
}
}
}
$conn->close();
?>
Trying to eventually get a value from the database then individually show a description if the more href is clicked.
your answer has a high time complexity you can easily make you
SQL query
SELECT id FROM items WHERE id = ?
and if the rows number is 0 this is mean there is no record with this id
you can check row's number from num_rows
You will never see "you clicked something from the database" message because you already fetched the result from your query in the first loop, check this question why-cant-i-loop-twice-on-mysqli-fetch-array-results
An option is to save the result in an array to use it later in your second loop
//your first loop
$savedRows = [];
while($row = $result->fetch_assoc()) {
$savedRows[] = $row;
//the rest of your code
}
// ......
// your second loop
if (isset($_POST['submit'])) {
foreach($savedRows as $row) {
if ($_SERVER["QUERY_STRING"] == $row['id']) {
echo 'you clicked something from the database ' . $id;
}
}
}
Also note that if this is your actual code, you need to make the closing identifier of your herodoc EOT; the first character on it's line, otherwise the rest of the file will be part of this string
In the PHP file can anyone help me directly making a for loop where I don't know the number of rows that are going to be selected.
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "mydb";//database details
$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_error)
{
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM mytable";
$result = $conn->query($sql);
$myarray = array();
$index = 0;
if ($result->num_rows > 0)
{
// output data of each row
while($row = $result->fetch_assoc())
{
$myarray[$index] = $row["firstname"];
$index++;
$myarray[$index] = $row["lastname"];
$index++;
$myarray[$index] = $row["email"];
$index++;
}
}
else
{
echo "0 results";
}
$conn->close();
?>
The Javascript code contains javascript of a search bar suggestion code and here i didn't mention the typeahead javascript file
var substringMatcher = function(strs) {
return function findMatches(q, cb) {
var matches, substringRegex;
// an array that will be populated with substring matches
matches = [];
// regex used to determine if a string contains the substring `q`
substrRegex = new RegExp(q, 'i');
// iterate through the pool of strings and for any string that
// contains the substring `q`, add it to the `matches` array
$.each(strs, function(i, str) {
if (substrRegex.test(str)) {
matches.push(str);
}
});
cb(matches);
};
};
$('#the-basics .typeahead').typeahead({
hint: true, //here i used typeahead js code though i didnt mentioned here
highlight: true,
minLength: 1
}, {
name: 'states',
source: substringMatcher(states)
});
You can simplify the PHP a little bit here when you read in the values as you dont need to increase the index:
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "mydb";//database details
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);//making a connection
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM mytable";
$result = $conn->query($sql);
$myarray = array();
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
$myarray[] =$row["firstname"];
$myarray[] =$row["lastname"];//storing in the array
$myarray[] =$row["email"];
}
} else {
echo "0 results";
}
$conn->close();
?>
You could echo in the results to the Javascript where you require them, echo($myarray[0]) for example.
Your Javascript may look something like this:
var matches = <?php echo($myarray[0]); ?>
There are 4 ways you can do to insert dynamic content to your javascript code.
Make the javascript inline to your PHP page. That is, putting your js code inside <script> tags
Make the dynamic js variables global and populate them in your php page. Your separate JS files will be able to read these global js variables.
If you want to have a separate file for JS, you have to generate it everytime (because you cant have PHP code in javascript. The browser cannot interpret it, and the server cannot interpret it)
If you want to force the server to interpret PHP code in JS files, add a handler so that .js is handler by the php interpreter (whether php module or php-cgi) see Clean links to PHP-generated JavaScript and CSS
Not sure what I did wrong. I'm aware that having two fetch_assoc removes the first result but I don't have such a thing.
$sql = "$getdb
WHERE $tablenames.$pricename LIKE 'm9%'";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
echo $tableformat;
while($row = $result->fetch_assoc()) {
$name = str_replace('m9', 'M9 Bayonet', $row['Name']);
include 'filename.php';
echo $dbtable;
}
My connect file:
$servername = "";
$username = "";
$dbname = "";
$password = "";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
require_once ('seo.php');
$dollar = '2.';
$euro = '1.9';
$tableformat = "<div class=\"CSSTableGenerator style=\"width:600px;height:150px;\"><table><tr><th>Name</th><th>Price</th><th><a class=\"tooltips\">Community<span>New !</span></a> </th><th>Cash Price</th><th>Trend </th><th>Picture </th></tr></div>";
$getdb = "SELECT utf.id, utf.PriceMin, utf.PriceMax, utf.Name, utf.Trend , community1s.price as com_price, utf.Name, utf.Trend
FROM utf
INNER JOIN (select id, avg(price) price from community1 group by id) as community1s
ON utf.id=community1s.id";
$tablenames = 'utf';
$pricename = 'Name';
$idrange = range(300,380);
What happens is, it fetches the first two column's fine and the rest of the row is not there and pushes the other results down one row, which messes up the data.
Here's an image to demonstrate:
http://imgur.com/CQdnycW
The seo.php file is just a SEO function.
Any ideas on what may be causing this issue?
EDIT:
My Output:
echo $tableformat;
while($row = $result->fetch_assoc()) {
$name = str_replace('m9', 'M9 Bayonet', $row['Name']);
include 'filename.php';
echo $dbtable;
EDIT: Solved it by moving my variables around. Marked as solved.
I found the issue. Some Variables that did the output were in a bad place. Rearranged them and now they are fine.
Your HTML is broken, and strange things happen in broken tables. $tableformat contains HTML that opens a <div> and a <table>, but then closes the <div> with the table still open.
Fix the broken HTML and you'll probably find that all is well
So i ran into some trouble not to long ago. As a student i am relativly new to programming and thus i often visit sites like these for help. My question is how can i add value to database by pressing a button. For me the problem here is that the button has a javavscript function to print. So in other words i want the button to have 2 functions, one that prints the page (which i already have) and one that adds value to the database. The purpose to adding the value to database is so people can see that its already been printed before.
So essentialy what i am asking for is how can i give a button 2 functions (one which is Javascript) and show people that the button is used(in this case, that it has been printed). All help will be appreciated very much.
My code is as following:
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "depits";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Query the database
$resultSet = $conn->query("SELECT * FROM orders");
// Count the returned rows
if($resultSet->num_rows != 0){
// Turn the results into an Array
while($rows = $resultSet->fetch_assoc())
{
$id = $rows['id'];
$naam = $rows['naam'];
$achternaam = $rows['achternaam'];
$email = $rows['email'];
$telefoon = $rows['telefoon'];
$bestelling = $rows['bestelling'];
echo "<p>Name: $naam $achternaam<br />Email: $email<br />Telefoon: $telefoon<br /> Bestelling: $bestelling<br /> <a href='delete.php?del=$id'>Delete</a> <input type='button' onclick='window.print()' value='Print Table' /> </p>";
}
// Display the results
}else{
echo "Geen bestellingen";
}
?>
This would aquire 2 tasks:
Is that you bind a function to the click handler of the button.
Although it is bad practice to use function calls directly, in your case this would be that you replace the window.print() by a custom javascript function.
In that javascript function, you execute the window.print() again, where-after you do the next step in the logic: sending data to PHP.
With ajax you can archieve this.
With a parameter in the function you can pass what the ID of the current row is, which need to be passed to PHP.
You need to create another PHP script, that will be called by tje AJAX script.
In that PHP script you will do the required updates to the database.
Ok There is a lot of ways you can do it but here is how i would do it :
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "depits";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Query the database
$resultSet = $conn->query("SELECT * FROM orders");
// Count the returned rows
if($resultSet->num_rows != 0){
// Turn the results into an Array
while($rows = $resultSet->fetch_assoc())
{
$id = $rows['id'];
$naam = $rows['naam'];
$achternaam = $rows['achternaam'];
$email = $rows['email'];
$telefoon = $rows['telefoon'];
$bestelling = $rows['bestelling'];
//first you call a custom javascript function after the 'onclick'. I believe you'll have to pass a variable as an argument (like $id).
echo "<p>Name: $naam $achternaam<br />Email: $email<br />Telefoon: $telefoon<br /> Bestelling: $bestelling<br /> <a href='delete.php?del=$id'>Delete</a> <input type='button' onclick='print_table($id)' value='Print Table' /> </p>";
}
// Display the results
}else{
echo "Geen bestellingen";
}
?>
Then you write this function in the header of your page
<script>
function print_table(id)
{
//print your document
window.print();
//send your data
xmlhttp=new XMLHttpRequest();
xmlhttp.open("GET","http://www.domaine.com/directories/printed_table.php?id=" + id;
xmlhttp.send();
}
</script>
Then you write your file printed_table.php where you store 1 if printed or 0 if not printed. I don't understand german so i don't know where you store your printed variable but it goes like this:
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "depits";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Query the database
$id = $_GET['id'];
$resultSet = $conn->query("UPDATE `orders` SET `printed` = 1 WHERE `id` = `$id`");
?>
This should work. Just be careful and check the $_GET['id'] before to use it for security purposes. like you can use the php function is_int(). Depending of the security level you need you might want to secure this code a little more.