Php select (Option list) - php

Question

I am using these codes
$query = "SELECT date FROM arrival order by date" ;
$result = mysqli_query($con,$query)or die ("Error". mysqli_error($con)) ;
echo "<select name='per1' id='per1'>";
while ($row = mysqli_fetch_array ($result)){?>
<option value=<?php echo $row['date'];?> selected='selected'><?php echo $row['date'];?></option>
</select>
<?php
}
?>
The select (Option list) displays data as
2016-07-01
2016-07-02
2016-07-03
2016-07-04
2016-07-05
2016-07-06
and so on
It is not like a dropdown option list.
How to make it like dropdown list?
I want select one date from option.

Answer 1

You are closing the select in the while multiple times. Move </select> outside.
}?> </select>
You also should quote the attribute value. Full example:
$query = "SELECT date FROM arrival order by date" ;
$result = mysqli_query($con,$query)or die ("Error". mysqli_error($con)) ;
echo "<select name='per1' id='per1'>";
while ($row = mysqli_fetch_array ($result)){?>
<option value='<?php echo $row['date'];?>' selected='selected'><?php echo $row['date'];?></option>
<?php } ?>
</select>

Answer 2

A little disorganized clear it up a bit and try this
$query = "SELECT date FROM arrival order by date" ;
$result = mysqli_query($con,$query)or die ("Error". mysqli_error($con)) ;
$result_array = array();
while($row = mysql_fetch_assoc($result))
{
$result_array[] = $row['date'];
}
echo "<select name='per1' id='per1'>";
foreach($result_array as $name){
echo'<option value="'.$name.'">'.$name.'</option>';
}
echo'</select>';
I believe that will do what you're looking for.