We already know,
check the data type is that an array can use the php is_array to get the answer,
but, how we check a Collection that have a relation (hasMany)?
here is the code:
1:
User::where('name','alex')->first();
2:
User::where('name','alex')
->with(['article' => function($q){
$q->where('active', 1);
}])->first();
A function need to accept those kind data to do somthing,
and I need to know which one have a relation
I think you are referring to getRelations() method:
$user = User::where('name', 'alex')->first();
// If user has some relations loaded (obviously not here)
if ($user->getRelations()) {
}
Related
I have a Controller method like this:
public function awaiting()
{
$producers = Producer::where('producer_process',4)->get();
$producers_list = [];
foreach($producers as $producer){
if($producer->brand->brand_rejected == 0){
array_push($producers_list, $producer);
}
}
return view('admin.brands.awaiting', compact('producers_list'));
}
So basically there's One To One relationship between Producer model & Brand model.
In order to get the collection of brands table records that has producer_process of 4 and ALSO the brand_rejected field of related brands table record must be set to 0, I added an array_push and check the condition.
Now this works fine and properly shows the correct data but I wanted to know, what is the shorthand method of doing this with Eloquent relationships?
I mean is there any concise and useful method written in Eloquent relationships that can do this without using array_push or another foreach loop?
You can use whereHas to constrain the result set based on the existence of a relationship. Here we are saying we only want producers that have the field 'produce_process' set to 4 and have a brand with a field of 'brand_rejected' set to 0:
$producers = Producer::where('producer_process', 4)
->whereHas('brand', function ($q) { $q->where('brand_rejected', 0); })
->get();
If you want these producers to have their brand relationship loaded to use you should eager load that. Before the get call you can tell it to load the relationship:
$producers = Producer::where(...)->whereHas(...)->with('brand')->get();
Laravel 5.8 Docs - Eloquent - Relationships - Querying Relationship Existence whereHas
Laravel 5.8 Docs - Eloquent - Relationships - Eager Loading with
You can try this:
public function awaiting()
{
$producers = Producer::where('producer_process',4)
->with('brand', function($q) {
$q->where('brand_rejected', 0);
})->get();
// dd($producers);
dd($producers->pluck(brand));
Sure you can use the method with() also with the where() clause to can apply some conditions to the relationship
Example
$yourQuery->with('brand', function($query){
$query->where('brand_rejected', 0);
});
check this for more info
https://laravel.com/docs/9.x/eloquent-relationships#constraining-eager-loads
I hope it's helpful
I want to select all the users in my table "User" except the first One cause its the admin,
im using this function index in my controller but it doesn't work .
public function index()
{
// this '!=' for handling the 1 row
$user = User::where('id', '!=', auth()->id())->get();
return view('admin.payroll',compact('user'))->with(['employees' => User::all()]);
}
Better to used here whereNotIn Method
Note: first you find the admin role users and create a static array
$exceptThisUserIds = [1];
$user = User::whereNotIn('id', $exceptThisUserIds)->get();
It's not a good idea to specify the admin user with just id. A better design would be using some sort of a flag like is_admin as a property of your User model.
Still you can use the following code to get the users who have an id greater than 1:
User::where('id', '>', 1)->get()
For getting data skipping the first one you should use skip() method and follow the code like below
public function index()
{
$user = User::orderBy('id','asc')->skip(1)->get();
return view('admin.payroll',compact('user'))->with(['employees' => User::all()]);
}
I have posts table that has related table where I store different translations based on post_id now when I want to return translation data based on user selected locale it says:
mb_strpos(): Argument #1 ($haystack) must be of type string, Closure given
Here is my function
$posts = Post::with('translations', function($q) {
$q->where('translate_code', app()->getLocale());
})->get();
dd($posts); // returning error above
But if I do this
$posts = Post::with('translations')->get();
dd($posts);
I will get following results
Here is translations data details:
My question is:
How can I return the one translation that has current locale name only?
If you using callback in with then use array of relations like below. Older version of laravel was working which you mentioned but latest version need array of relations when using callback.
$posts = Post::with(['translations'=> function($q) {
$q->where('translate_code', app()->getLocale());
}])->get();
using conditional eager loading should be like this:
$posts = Post::with(['translations'=> function($q) {
$q->where('translate_code', app()->getLocale());
}])->get();
while the relation name is the key, a closer to get data should be the value for the associative array for 'with' statement.
You can query your relation by using whereHas().
Docs: Laravel Docs Relationships
For example:
$posts = Post::whereHas('translations', function ($query) {
$query->where('translate_code', 'en');
})->get();
Maybe try to put the app()->getLocale() into a variable first. (after trying this out in tinker, this does seem te return a string, so may passing it by reference might help).
sorry for the title of this question but I am not sure how to ask it...
I am working on a project where I have two Models Trains and Cars, to this model I have a belonging Route.
I want to make a query and check if the routeable_type is App\Car than with the selected routeable_id to get the data from the Car. And if the routeable_type is Train then with the ID to get the data from the Tran.
So my models go like this:
Train:
class Train extends Model
{
public function routes()
{
return $this->morphMany('App\Route', 'routeable');
}
}
Car:
class Car extends Model
{
public function routes()
{
return $this->morphMany('App\Route', 'routeable');
}
}
Route:
class Route extends Model
{
public function routeable()
{
return $this->morphTo();
}
}
And the query I have at the moment is:
$data = Route::leftjoin('cars', 'cars.id', '=', 'routes.routeable_id')
->leftjoin('trains', 'trains.id', '=', 'routes.routeable_id')
->select('routes.id', 'cars.model AS carmodel', 'trains.model AS trainmodel', 'routeable_type', 'routes.created_at');
With this query if I have the same ID in cars and trains I get the data from both and all messes up. How do I check if routeable_type is Car ... do this, if routeable_type is Train .. do that?
Will something like this be possible in a 1 single query:
$data = Route::select('routes.id', 'routeable_type', 'routes.created_at');
if(routeable_type == 'Car'){
$data = $data->leftjoin('cars', 'cars.id', '=', 'routes.routeable_id')->select('routes.id', 'cars.model AS carmodel', 'routeable_type', 'routes.created_at');
}else{
$data = $data->leftjoin('trains', 'trains.id', '=', 'routes.routeable_id')->select('routes.id', 'trains.model AS trainmodel', 'routeable_type', 'routes.created_at');
}
Maybe this is what you are looking for?
DB::table('routes')
->leftJoin('cars', function ($join) {
$join->on('cars.id', '=', 'routes.routeable_id')
->where('routes.routeable_type', 'App\Car');
})
->leftJoin('trains', function ($join) {
$join->on('trains.id', '=', 'routes.routeable_id')
->where('routes.routeable_type', 'App\Train');
})
->select('routes.id', 'cars.model AS car_model', 'trains.model AS train_model', 'routes.routeable_type', 'routes.created_at');
->get();
I think you may want to follow the morphedByMany design.
https://laravel.com/docs/5.7/eloquent-relationships#many-to-many-polymorphic-relations
This was also a neat visual for the different relation types.
https://hackernoon.com/eloquent-relationships-cheat-sheet-5155498c209
I was faced with a similar issue though I failed to follow the correct design initially and was forced to query the many possible relations then wrote custom logic after to collect the relation types and ids then do another query and assign them back through iteration. It was ugly but worked... very similar to how Eloquent does things normally.
i don't have enough repo, so i can't comment. that's why i am putting as an answer.
You should use 2 different queries, for each model.
This will be better, code wise as well as performance wise. also if both models have similar fields you should merge them to 1 table and add a 'type' column.
and put non-similar fields in a 'meta' column.
( in my opinion )
I have the following relationships:
TheEpisodeJob hasOne TheEpisode
TheEpisodeJob hasMany TheJobs
I am successfuly retrieving all TheEpisodesJobs and TheSeriesEpisodes with all the fields in database (including sensitive information) using this command:
$jobs = TheEpisodeJob::with('TheEpisode')->get();
I would like to limit TheEpisode fields shown only for this case (public $hidden will not work)
EDIT
Let's say I need only title and description field from TheEpisode.
How can I achieve that?
As #Buglinjo pointed out you can scope the relationship when eager loading, however, if you're going to be doing this to only select specific columns you must included the related column in the select so that Eloquent knows which Model to attach the related data to.
This should give you what you want:
$jobs = TheEpisodeJob::with(['TheEpisode' => function ($query) {
$query->select('jobID', 'title', 'description');
}])->get();
Furthermore, if you then wanted to to get rid of the jobID as well you could do something like:
$jobs->transform(function ($job) {
$job->TheEpisode->transform(function ($item) {
unset($item->jobID);
return $item;
});
return $job;
});
Hope this helps!
As far as I understood you, you want to limit the results according to some more parameters. If I am right, you should add more queries, like:
->where, ->orwhere, ->select, ->whereNull
Here is the link for more queries. Hope it will help )
I saw an update, so then you need
->pluck('title', 'description');
for more information, go to the link above
You should do like this:
$jobs = TheEpisodeJob::with(['TheEpisode' => function($q){
$q->get(['title', 'description']);
//or
$q->pluck('title', 'description');
}])->get();
Note: pluck is getting as array not as Eloquent Object.